So, for anyone wondering, the point of this is that instead of tracing from just one spot every time you get that case, you can trace from a more comfortable position depending on the scramble
4 ปีที่แล้ว +5
My CSP tracing is sub-inspection, usually 9-10 on familiar cases, 12-14 on rarer cases, but this still seems super interesting and may consider learning.
This is applied the same way on the bottom layer. It is easier to visualize it with pretty much any non square case. For square, if on top you are starting with a corner and on bottom you are starting with an edge, although technically the layers are "aligned" they are actually starting from opposite count positions. You would start with a corner on the top and bottom or an edge on top and bottom for them the get the same count positions.
Late comment, but you can memorize counting positions for shield easier. The parity count changes every time you pass a corner in the front. For example: if your initial position is when shield edges are on the right, and you do 2,0 the parity count won't change because you didn't pass a corner. However if you do -2,0 the parity count will change, because you passed a corner. Sorry for my bad English, hope you will understand.
I see people saying to do an inverted count when it’s mirrored but what does this mean. Does this mean you start with 1 and trace like normally or does this mean you invert the colors so ‘blue orange green’ would be 1 parity. I don’t know which is what they are talking about
also does the colors have any meaning? For example let's say if you started counting from a blue position in the top, do you have to start counting from a pink position in the bottom?
I think you might be misunderstanding the colors. They don't mean anything for the top and bottom layer specifically, they work with both layers. If you start from one color you would get one count, and if you start from the other you would get another count
I'm also confused with cases on the bottom. For example if we take a solved state and started counting from the corner in the top layer and started counting from the edge in the bottom layer, i should get no parity. Does cases in the bottom layer mean i have to switch the parity number?
So if I trace from a blue position on one layer and a pink position on the other, would that mess up the whole trace? Do I need to use one color position on both layers
It depends on the starting position you choose for your case . For example your starting position corresponds to a blue position but you accidentally started to trace from a pink position , then you have to just reverse the count you got , ie if you get odd then change it to even and if you get even change it to odd. But if you trace from a wrong position on both the layers then you don't need to change your count . You can solve with whatever parity count you get. Hope it helps you
What's the point in learning which count positions will give you different parity? If you don't know whether those positions give you odd or even parity, can't you just start from any sliceable position?
Sorry, but I don't quite understand your question. The point though of learning count positions is to give more options when doing a trace, especially in awkward alignment of the layers. You can't trace at any sliceable position because most cases are not traced the same from every position.
You can start from any sliceable position, but if you start from a position that is a different color from your usual position (the one you first learned from doing), you just need to reverse the parity count at the end :)
That's weird, it should work. Maybe try double checking, since shield is quite a difficult case because it is not symmetrical. If you provide a scramble I might be able to help you further.
@@CubeMasterYT (0,2)/ (0,3)/ (0,3)/ (4,-2)/ (0,-3)/ (0,-3)/ (3,0)/ (0,-4)/ (3,0)/ (-4,-3)/ (4,-4)/ (0,-4)/ (-4,0)/ (2-2) i tried to trace it and got even but i still got parity.
I'm not sure exactly what you are asking, but after I did the scramble and from the exact orientation after scrambling, I got odd parity (0, white edges 0, yellow edges 0, yellow corners 0, white corners 1, odd edges 2, odd corners 3 -> 3 gives odd parity. If you choose to start from a different piece for the shield to trace, you would use the picture on 10:43 to find whether to change its state at the end, depending on where you start.
I have a tutorial on CSP and a video series that goes over all the cases with tracing, and there is a document too. You can use concepts in this video along with those videos :) (playlist here th-cam.com/play/PLF0mfn_ogsH_mGKR9j4mR-USh7CnBxec-.html)
I mean you could trace from any position as shown here, but if the color from the diagram is different you would trace there but just change the trace at the end from odd->even or vice versa
The blue and red dots represent different tracing positions to start at. All the blue dots give the same trace, and all the red dots give the opposite trace from the blue dots :)
Thanks for telling me, must have forgotten it. That case is also really simple, it's traced the same from anywhere except for positions that separate the perpendicular edges with the scallop (visual here: cdn.rawgit.com/sp3ctum/squanmate/6.10/resources/public/index.html#/count-positions)
So, for anyone wondering, the point of this is that instead of tracing from just one spot every time you get that case, you can trace from a more comfortable position depending on the scramble
My CSP tracing is sub-inspection, usually 9-10 on familiar cases, 12-14 on rarer cases, but this still seems super interesting and may consider learning.
I definitely recommend learning all the awkward and easy cases, they help quite a bit with both speed and accuracy :)
I am confused, How does this apply to the bottom layer?
For example square case, on top you start by a corner but on bottom you start by an edge
This is applied the same way on the bottom layer. It is easier to visualize it with pretty much any non square case. For square, if on top you are starting with a corner and on bottom you are starting with an edge, although technically the layers are "aligned" they are actually starting from opposite count positions. You would start with a corner on the top and bottom or an edge on top and bottom for them the get the same count positions.
Late comment, but you can memorize counting positions for shield easier.
The parity count changes every time you pass a corner in the front. For example: if your initial position is when shield edges are on the right, and you do 2,0 the parity count won't change because you didn't pass a corner. However if you do -2,0 the parity count will change, because you passed a corner.
Sorry for my bad English, hope you will understand.
This video really helped, thank you very much :)
I see people saying to do an inverted count when it’s mirrored but what does this mean. Does this mean you start with 1 and trace like normally or does this mean you invert the colors so ‘blue orange green’ would be 1 parity. I don’t know which is what they are talking about
also does the colors have any meaning? For example let's say if you started counting from a blue position in the top, do you have to start counting from a pink position in the bottom?
I think you might be misunderstanding the colors. They don't mean anything for the top and bottom layer specifically, they work with both layers. If you start from one color you would get one count, and if you start from the other you would get another count
I'm also confused with cases on the bottom. For example if we take a solved state and started counting from the corner in the top layer and started counting from the edge in the bottom layer, i should get no parity. Does cases in the bottom layer mean i have to switch the parity number?
Not sure what you are saying, sorry :( but you should get odd parity for square/square
So if I trace from a blue position on one layer and a pink position on the other, would that mess up the whole trace? Do I need to use one color position on both layers
It depends on the starting position you choose for your case . For example your starting position corresponds to a blue position but you accidentally started to trace from a pink position , then you have to just reverse the count you got , ie if you get odd then change it to even and if you get even change it to odd. But if you trace from a wrong position on both the layers then you don't need to change your count . You can solve with whatever parity count you get.
Hope it helps you
What's the point in learning which count positions will give you different parity? If you don't know whether those positions give you odd or even parity, can't you just start from any sliceable position?
Sorry, but I don't quite understand your question. The point though of learning count positions is to give more options when doing a trace, especially in awkward alignment of the layers. You can't trace at any sliceable position because most cases are not traced the same from every position.
@@CubeMasterYT Which sliceable positions can't I start from? The ones labled red?
You can start from any sliceable position, but if you start from a position that is a different color from your usual position (the one you first learned from doing), you just need to reverse the parity count at the end :)
@@CubeMasterYT what do you mean by a 'different colour from your starting position' ?
Please answer
Nvm I understood
i am having trouble for shield i tried your way but i am always getting it wrong.
That's weird, it should work. Maybe try double checking, since shield is quite a difficult case because it is not symmetrical. If you provide a scramble I might be able to help you further.
@@CubeMasterYT (0,2)/ (0,3)/ (0,3)/ (4,-2)/ (0,-3)/ (0,-3)/ (3,0)/ (0,-4)/ (3,0)/ (-4,-3)/ (4,-4)/ (0,-4)/ (-4,0)/ (2-2) i tried to trace it and got even but i still got parity.
I'm not sure exactly what you are asking, but after I did the scramble and from the exact orientation after scrambling, I got odd parity (0, white edges 0, yellow edges 0, yellow corners 0, white corners 1, odd edges 2, odd corners 3 -> 3 gives odd parity. If you choose to start from a different piece for the shield to trace, you would use the picture on 10:43 to find whether to change its state at the end, depending on where you start.
does it matter where you start tracing the bottom layer or does it?
Yep
In this video, you showed from where to start tracing odd-even whatever...but can you show us how do you tracing any cube shape?
I have a tutorial on CSP and a video series that goes over all the cases with tracing, and there is a document too. You can use concepts in this video along with those videos :) (playlist here th-cam.com/play/PLF0mfn_ogsH_mGKR9j4mR-USh7CnBxec-.html)
So for cases where u can’t trace from any position, where do u start tracing from?
I mean you could trace from any position as shown here, but if the color from the diagram is different you would trace there but just change the trace at the end from odd->even or vice versa
@@CubeMasterYT oh ok i'll try that
@@CubeMasterYT so u can trace from the blue dots but when you trace for the pink dots you have to reverse it?
@@randomizedcuber3073 ya
Late reply ik
I dont get it. Whats the purpose of bueand red dots?
The blue and red dots represent different tracing positions to start at. All the blue dots give the same trace, and all the red dots give the opposite trace from the blue dots :)
@@CubeMasterYT thanks for clarifying!
Where are the 4-1-1 ?
4-1-1 missing
Thanks for telling me, must have forgotten it. That case is also really simple, it's traced the same from anywhere except for positions that separate the perpendicular edges with the scallop (visual here: cdn.rawgit.com/sp3ctum/squanmate/6.10/resources/public/index.html#/count-positions)