What if the distribution of scores in ungrouped data is bimodal, how to find the value of mode? Example: 5, 3, 2, 5, 7, 2, 8, 11..what is the value of mode?
15 devide by 2, we get 7.5. in f, 1 + 2 + 3 = 6 and 6 + 4 = 10. so 7.5 in range between 128 and 129 because 128 is 6 and 129 is 10. for that, we consider 129 as the median.
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on problem 3 calculating mean why did you the formula of grouped data when its ungrouped data
They have the same formula only the X's are different.
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What if the distribution of scores in ungrouped data is bimodal, how to find the value of mode? Example: 5, 3, 2, 5, 7, 2, 8, 11..what is the value of mode?
It has bimodal mode of 2 and 5 as you stated earlier
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Interesting
Sum number 3 I didn't understand the median part. How comes 4 is the median number? I wish you could elaborate more
15 devide by 2, we get 7.5. in f, 1 + 2 + 3 = 6 and 6 + 4 = 10. so 7.5 in range between 128 and 129 because 128 is 6 and 129 is 10. for that, we consider 129 as the median.
The median:
15÷2=7.5
How did you round it with a whole number to get 8?
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How or why?
Meanwhile, you are meant to always round off to obtain a counting number.
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