Sir one doubt 9 th and 11 th sum la x x cross multiply la x* then adukula irukiradu kuutina vara 2 apo x square power 2 nu eludanuma???sir pls clarify me...
First solve "bracket" 3/4+3/5= 27/20 Now u get 9/3÷3/5 of 27/20 Next solve "of" 3/5of27/20 = 3/5*27/20 = 81/100 Now u get 9/3÷81/100 = 9/3*100/81 = 100/27 = 3 19/27
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How to solve this
9/3÷3/5 of (3/4+3/5)
Sir one doubt 9 th and 11 th sum la x x cross multiply la x* then adukula irukiradu kuutina vara 2 apo x square power 2 nu eludanuma???sir pls clarify me...
Sir point piragu 4,6,8 digits irutha 2 la divide panni digit podalam incase point Ku aprm 5,7 digits irutha enna panrathu
First solve "bracket"
3/4+3/5= 27/20
Now u get
9/3÷3/5 of 27/20
Next solve "of"
3/5of27/20 = 3/5*27/20 = 81/100
Now u get
9/3÷81/100 = 9/3*100/81 = 100/27 = 3 19/27
Apdi varathu,
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