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Without choaching students please read this... I m in 11th class studying in "The aakash" instiute... Preparaing for medical.. But trust me guys there is nothing special in these institutes ... Uh knw wht we have completed gravitation like chapter in 3 classes for 1 hour 30 min duration not just clearing the concepts like alakh pandey sir give us.who give us 8 lectures on it ... They just give us books enough.. I just want to make uh believe guys uh can too crack exam without choaching ... Do hard work be regular ... Please like this if it help uh in anyway to motivate yourself... Just showed the reality
Its not like that.. Coaching se faiyada b h bhoot but yah aisa b nhi h tht kuch ho nhi skta coaching ke bina... Uh can too crack exam without coaching .. Do hard work 😊 praticse mcq
For Screenshot ==> 3:37 = Formula of RMS Velocity 8:37 = Derivation of Formula of RMS Velocity 11:38 = Q1 (Based on RMS Velocity) 14:36 = Q2 (Based on RMS Velocity) 15:58 = HW - Q1 (Based on RMS Velocity) 21:10 = RMS Velocity in Terms of Pressure & Density 31:42 = Maxwell's Distribution of Velocities 35:24 = Introduction to Free Path & Mean Free Path 47:43 = Derivation of Formula of Mean Free Path
@@nidhikeshan2665 see if it was 300°C (for H2) the answer which is coming is 9168 but if it was 300°K the answer is 4800°K which is in option..so it was a bit wrong..nothing else
18:40 for finding that Vrms is inversely proportional to square root of density we can also get it from d = PM/RT, RT/M = P/d, Vrms = under root 3RT/M = under root 3P/d. Hence Vrms is inversely proportional to the square root of density.
@@ArmanMulla-l1j Sir ne question me 300°C likha hai, agar isko kelvin me convert krke solve karenge to ans 9168 aayega, pr agar quest. Me 300K lekar solve kren to ans 4800 aayega!!
12:55 ANS: T1=T2 For H2=> √R*T1/M=Vrsm √R*T1/M= x T1=x^2/4 Since Temp is same as For H2 gas, therefore T=x^2/4 For O2=> √R*T2/M=Vrsm putting t=x^2/4 and R is constant i.e. 8.314 (maine toh 8 li h iski value), we get: Vrsm for O2 = x/4
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Sir, Sabse pehle mey apko thanks kehna chahungi apke physics ke difficult and tricky topic ko itna easy and elaborate way mey numerical ke saath samjhaane vale videos ke liye.... Jo mene der se dekhe kyuki pehle I don't have any access to Internet, on those samajh nhi aata tha kaise kr paungi pr ab lagta h kr lungi...... Vo alag baat h ki abhi time se race chal rhi h kyuki Dec tk pura krna Sir apke padhne ke tarike ka universal law ban sakta h ki aapka padhne ka tarika especially physics Superb👏👏👏👏👏👏👏👏👏👏👏👏h pure universe mey (#Pw law ya LAW OF SUPERB PHYSICS TEACHING ) Or dusra mera doubt Vrms is a Velocity or a speed? as in maxwell distribution curve when u write vavg before it "u said another speed like"
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Find the temperature at which oxygen molecules would have the same rms speed as of hydrogen molecules at 300k . Then answer is 4800k 16:00 But in question sir given h.w Ans is 9168 will be correct answer Awesome lecture with full of josh ❤️💐😁😁😁😁😁😁😁😁😁👍👍👍👍👍👍
Many gases such as nitrogen, oxygen, hydrogen, noble gases, some heavier gases like carbon dioxide and mixtures such as air, can be treated like ideal gases within reasonable tolerances over a considerable parameter range around standard temperature and pressure.
The ques at 15:26 has a error it will be 300 K rather than 300°C which sir as written by mistake...as on solving ques considering 300°C the ans is approx 9168 K bt on considering 300 K u will get option C of ques that is 4800 K...I wish u all will understand...at last sir you are the best phy teacher...♥️♥️♥️
Sir if I take Temperature of Oxygen in 300 degree celsius then I get 9168 but there isn't any option for this result sir previously we have taken Temperature of Oxygen in 27 degree Celsius if take Temperature as 27 degree Celsius then I get 4800K sir :)
at 16:03 , sir the T(of h2) it should be in kelvin,i.e T= 300K becoz the option is not matching with actual answer[T(of o2)=9168k] when we change the temperature to kelvin which T(of h2)= 300+273= 573k....😬
Sir at 16:30...HW Q... the temp should be in 'K' ..soo that the temp is 300 K and after that the ans will be "c.4800" ...bcoz with 300*C the ans coming is 9168 K which is not given in options...
In the Maxwell Boltzmann Distribution curve, the Y axis contains fraction of molecules(unitless quantity) and X axis contains velocity(m/s). Then how is the area under the curve supposed to give total number of molecules(unitless) even though we must get a quantity with Dimensions like that of Vrms(m/s)?
Bro we have represented them graphically not dimensionally we just considered here only number of molecules for the different velocities of the molecules in graphical diagram
Isn't the maximum value of the Y axis(fraction of molecules)=1? If so then According to Einstein's theory, any physical object can Attain A maximum speed which is Less than The speed of Light(3×10^8 m/s). I know that such large speed Cannot be Attained By a Gas Molecule but to find The Max possible area Under The curve let us Consider all the Gas molecules have a Speed Of 3×10^8 m/s. So Area Under the graph Is 1×3×10^8= 3×10^8. According to Sir this must Be The total Number of Molecules and it shows That the maximum no. Of Molecules we can Obtain will be less than 3×10^8 which Is Very small in Comparison to a mole.
But, mean free path is given by: l = kT/√2πd²p Here, l= mean free path k= boltzmann constant T= temp. in Kelvin d= diameter of one molecule p= pressure of gas Why you haven't mentioned √2 in the formula?
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3)PDF Notes of each class.
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6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021)
7)In case you missed a live class, you can see its recording.
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The test series follows very logical sequence of Basic to Advance questions.&
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H. W Q. Answer is C) 4800
@@next_in question mein 300 celcius mein de rakha hai 300 Kelvin mein hota toh yeh answer aata
@@aarti8103 meri marzi kya karlega
@@aarti8103 ha
@@aarti8103 u hi
Without choaching students please read this... I m in 11th class studying in "The aakash" instiute... Preparaing for medical.. But trust me guys there is nothing special in these institutes ... Uh knw wht we have completed gravitation like chapter in 3 classes for 1 hour 30 min duration not just clearing the concepts like alakh pandey sir give us.who give us 8 lectures on it ... They just give us books enough.. I just want to make uh believe guys uh can too crack exam without choaching ... Do hard work be regular ... Please like this if it help uh in anyway to motivate yourself... Just showed the reality
Hi ayushi can i help waise me kota se coaching kr rha hoon iit ka
@@kishansingh4939sure... what help you would do..?
@Ayushi Singh.... really coaching se koi fayeda nhi h ??😮😮😮
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For Screenshot ==>
3:37 = Formula of RMS Velocity
8:37 = Derivation of Formula of RMS Velocity
11:38 = Q1 (Based on RMS Velocity)
14:36 = Q2 (Based on RMS Velocity)
15:58 = HW - Q1 (Based on RMS Velocity)
21:10 = RMS Velocity in Terms of Pressure & Density
31:42 = Maxwell's Distribution of Velocities
35:24 = Introduction to Free Path & Mean Free Path
47:43 = Derivation of Formula of Mean Free Path
Mean free time reh gaya , sir ne cover nahi kiya
Thanks bhai It save my time
Bhai kuch kam me nhi aaya
Made my day
Thanks a lot siddharth
ATQ, T = 9168K
And if 300K is taken ,then the answer would be (c) 4800 K
Ryt
Yes bro
@@karansahni3533 kese bro
In kalvin temp will be 573k if temp is taken 300*C
@@karansahni3533 but fir to ans 9168k aata he na
Best!!! Mera naam Physics Wallah...or hamara or aapka pyara sa channel Alakh Pandey 😂😂😂😂
Reverse ho gaya
😂 Reciprocal hogya
This is the reverse or u can say reciprocal theorem. 😂😂😂😂
Good
its evolving.. just backwards
16:30
Sir yahan temperature 300°C ki jagah 300K, nahi aana chahiye, isse, answer would be c. 4800K
I m also confused
I also figured that
@@nidhikeshan2665 see if it was 300°C (for H2) the answer which is coming is 9168 but if it was 300°K the answer is 4800°K which is in option..so it was a bit wrong..nothing else
Ya right 300° c laka ans approx 9168 k arra
Yes 300 k ma hi hona chaiya
18:40 for finding that Vrms is inversely proportional to square root of density we can also get it from d = PM/RT, RT/M = P/d, Vrms = under root 3RT/M = under root 3P/d. Hence Vrms is inversely proportional to the square root of density.
sir made a mistake there by equating (V rms)2 = ROOT(3PV/M) am i right?
@@ItsMe-uv8kv yeah i also think
I DONT THINK AANE WALE SMAY ME KOI LAKHON RUPAY DEKE OFFLINE PDHEGA AGR AAP JAISE TEACHER SATH HO. VO BHI ONLINE FREE. THANK U SOOO MUCH SIR
correct
offline class feels more interactive u know
Your predictions...🔥
Became true❤
Sir I think 300calcius ky jagaha 300K hoga. Tho ans 4800K ayaga.
Yes 300℃ nhi hoga....
Yes. Apologies
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Haan sir 300k heho gai
Yeah
16:11 at 300°C for H2 vrms for O2 is 9168K
But at 300K for H2 vrms for O2 is 4800K which is option (C)
that is not vrms that is temp.... temp for oxygen is 9168k and 4800k
How
@@ArmanMulla-l1j Sir ne question me 300°C likha hai, agar isko kelvin me convert krke solve karenge to ans 9168 aayega, pr agar quest. Me 300K lekar solve kren to ans 4800 aayega!!
@@gkdhkdky 2400 hoga
4800 hoga Calc check karlo ek bar
12:55 ANS:
T1=T2
For H2=>
√R*T1/M=Vrsm
√R*T1/M= x
T1=x^2/4
Since Temp is same as For H2 gas, therefore T=x^2/4
For O2=>
√R*T2/M=Vrsm
putting t=x^2/4 and R is constant i.e. 8.314 (maine toh 8 li h iski value), we get:
Vrsm for O2 = x/4
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Q)15:58
Ans if taken 300°C ans is 9168 K
And if taken 300K ans is 4800 K
correct
I also thought that
thank u jaanu
Aapke channel ka ab tak ka sara physics ka lecture dekh chuka.
Physics ko maine real jindgi me jiya sir.
Thanks a lot sir.
Iit nikalne ke baad mai aapse jrur se jrur milunga sir... My dear sir.
Mai 10th ke baad financial weaknesses ke karan mera padhai chhuth gya. Pr mujhe isaki kami feel nahi hone di. Mera jee ka exam 2022 me hoga sir . Aur iit jane se pahle aapse aashirwad jarur lunga sir
10:47 me doing all the calculation after pausing the video by taking R=8.314 . Le alakh sir isko 8 maan liya jaaye 😂😂😂😂
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sameee
Same 😂😂😂
Dimag ko use karna sikh lo
Toh aisa nahi hoga
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Sahi bola
16:30 9168 K.... When we take temp. as 300°C
4800 K..... When we take temp. as 300 K
That correct no body is perfect
You are my best teacher ever in my whole life I say with confident that i will never able to get a teacher like you. You are the only & only 1 masterpiece love you sir ♥️♥️♥️♥️
is this the last lecture for this chapter?
Yes
@@preetiraut787yes
If you are watching this video in 2024 then you're legend
Maxwell's distribution of Velocities 21:50
Sir,
Sabse pehle mey apko thanks kehna chahungi apke physics ke difficult and tricky topic ko itna easy and elaborate way mey numerical ke saath samjhaane vale videos ke liye.... Jo mene der se dekhe kyuki pehle I don't have any access to Internet, on those samajh nhi aata tha kaise kr paungi pr ab lagta h kr lungi...... Vo alag baat h ki abhi time se race chal rhi h kyuki Dec tk pura krna
Sir apke padhne ke tarike ka universal law ban sakta h ki aapka padhne ka tarika especially physics Superb👏👏👏👏👏👏👏👏👏👏👏👏h pure universe mey (#Pw law ya LAW OF SUPERB PHYSICS TEACHING )
Or dusra mera doubt
Vrms is a Velocity or a speed? as in maxwell distribution curve when u write vavg before it "u said another speed like"
Bhai He never asks for like...its duty of all of us to give him a like... Like kr diya kro yr sir bohot mehnat karte hain....👍
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@@vikki9762 now it is 2.34
@sadaf ansari yeahhh ikik....2 weeks ago it was 2.34 and now 2.38
Over smart hai ye
Assalamualaikum, sir apka bahut bahut shukriya sir ap jio hazarao saal sir ap ne pura topic yt per pada Diya aj Kal Kon bhi aisa nahi karta ap sab se dayalo aur ap duniya ke sab se ache insaan ho sir allaha bless you sir apki jo bhi preshani ho vo door hujaye ap ki income bade ap isse bhi zyda uncha muqaam hasil kare Meri duva hai...🥺❣️💕💯💯
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Waah
T=9168k if we take 300°c , when we take 300°K then T=4800K answer is C
Find the temperature at which oxygen molecules would have the same rms speed as of hydrogen molecules at 300k . Then answer is 4800k
16:00 But in question sir given h.w
Ans is 9168 will be correct answer
Awesome lecture with full of josh ❤️💐😁😁😁😁😁😁😁😁😁👍👍👍👍👍👍
Yes
Bro but no option
Sorry
Answer is coming 9100.7 approx. When taken Tof H↓2 as 300°C or 573 K
" Isko special maine banaya hai, ye kuch special paida nahi hua tha" Literally Felt it Sir!!
Answer of question is option c 4800 k when temperature of H^2 is 300k and if temerature of H^2 is 300 °C then answer is 9168k
3:30 , sir ur alternating current video lectures was awsum
Sir ap kesa koi physics ka teacher ho hee nai skta ...aleeza from Pakistan❤❤
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Sir at 16:07 par ek question me sir jo temprature hai wo 300 k lene p answer aa raha h , 300 c lene par nhi.
Hmmm u r correct
Yes
Yes bro
Sahi hh bhai....4800 degree Celsius aayega...
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Many gases such as nitrogen, oxygen, hydrogen, noble gases, some heavier gases like carbon dioxide and mixtures such as air, can be treated like ideal gases within reasonable tolerances over a considerable parameter range around standard temperature and pressure.
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HARDWORK
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4th & 5th lecture kha h ??
Sir, please make a video on distance of closest approach in Kinematics.
Answer 9168kelvin when temperature 300°c
Answer 4800kelvin when temperature 300kelvin
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July 31 2023
sir
16:00 ans is 9168 K
(c)will be right if T is in (K)
Thank you sir ☺️☺️☺️
Amazing lecture sir!!!!! Loved it...!!!
Mene ye lecture bhi dekhkar notes 📝 bana liye 🙏👍
16:26 Numerical base RMS velocity
T=300K
Answers Temp. of O2=4800K
T=300°C=300+273=573
Answer Temp. Of O2= 573×16=9168K
=8895°C
sir in the hw question the ans would be 9168K
but if the temp is 300 K then the ans is c) 4800K
Right
9168 K... When we take temp. as 300°C
4800 K... When we take temp. as 300 K
@Asad Khan correct answer will be 9168K
@@shubhanshurajiitm7335 agreed
Can uhh give solution of this ques??
@@ossumindia4995 read the question it is given 300 degree C so convert it into kelvin
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Are you in class 11
16:27
Sir question mey 300'C k jgh Kelvin hona chiye tha..tb answer 4800K aarha hai. Otherwise 300'C ko ley kr answer 9168k hai.
Yes bro
@rohan saxena 😂mera to alag aaya to me direct comments me aa gaya tha
@rohan saxena sameeeeeee
@@shreyash8294 op😂
@rohan saxena same here
The ques at 15:26 has a error it will be 300 K rather than 300°C which sir as written by mistake...as on solving ques considering 300°C the ans is approx 9168 K bt on considering 300 K u will get option C of ques that is 4800 K...I wish u all will understand...at last sir you are the best phy teacher...♥️♥️♥️
Sir I love your teaching style 😘😘😝
We all love it
I'm
dw,=fdx=kxdxproblemsir
Thankyou for starting shm upnext sir😀😀😀😀😀😀
Kb kha sir ne
@Lisha Kumari ye video suru ka half minute dekho.
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16:28 ..The answer is (C)4800K
Point me aayega aapi
Mera mtlb exact 4800 nhi aayega 4584 final h jo approx h
I want know why people dislike such a great video .........
congrats on completing this short yet imp chapter mate !!more power to you love you all
Ans is 4800K ( T= 300*32/2 by using √3RT/M)
Sir if I take Temperature of Oxygen in 300 degree celsius then I get 9168 but there isn't any option for this result sir previously we have taken Temperature of Oxygen in 27 degree Celsius if take Temperature as 27 degree Celsius then I get 4800K sir :)
The question points out that the Vrms of O2 at “300*C” and H2 at T(Kelvin)
🧠👈🏽
16:00
Agar 300k liya to 4800k
❤️✨THANK U SIR 😻🔥
T=9168k
In Kelvin( 273+300)K
√3*R*573/√2 = √3RT/√32
Squaring both side
R and 3 cancel
573*16=9168 answer
Ya too option he nhi ha....
Yhi aata ha k..ma..c. ma 4800..aata ha
Friends, this concepts are enough for neet
Yes
Sir answer for the question at 16:27 is 4800K option C
thankyou sir
Sir answer for the given question is 4800K(temp of O2).
How
Kya baat hai , Subha Subha 😀😀😀😀
at 16:03 , sir the T(of h2) it should be in kelvin,i.e T= 300K becoz the option is not matching with actual answer[T(of o2)=9168k] when we change the temperature to kelvin which T(of h2)= 300+273= 573k....😬
Right
Rip to those watching this 1 day before exam on 2x speed
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Sir at 16:30...HW Q... the temp should be in 'K' ..soo that the temp is 300 K and after that the ans will be "c.4800" ...bcoz with 300*C the ans coming is 9168 K which is not given in options...
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13:14 ans. d) x/4
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Option c:) 4800K
But i can't understand why we put the temp in this question in celsius and get the answer in kelvin
You're probably giving 12th preboards now, but same is happening with me
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31:49 when sir repeated the formula wrong ..with a great accent 😂🔥
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Sir 16:30 ans is 4800K
But you the given temperature is degree centigrade which should have been in Kelvin.
In the Maxwell Boltzmann Distribution curve, the Y axis contains fraction of molecules(unitless quantity) and X axis contains velocity(m/s). Then how is the area under the curve supposed to give total number of molecules(unitless) even though we must get a quantity with Dimensions like that of Vrms(m/s)?
Bro we have represented them graphically not dimensionally we just considered here only number of molecules for the different velocities of the molecules in graphical diagram
Isn't the maximum value of the Y axis(fraction of molecules)=1?
If so then According to Einstein's theory, any physical object can Attain A maximum speed which is Less than The speed of Light(3×10^8 m/s). I know that such large speed Cannot be Attained By a Gas Molecule but to find The Max possible area Under The curve let us Consider all the Gas molecules have a Speed Of 3×10^8 m/s.
So Area Under the graph Is 1×3×10^8= 3×10^8. According to Sir this must Be The total Number of Molecules and it shows That the maximum no. Of Molecules we can Obtain will be less than 3×10^8 which Is Very small in Comparison to a mole.
Bhai y axis pr jo quantity hai uski unit hai sec/m
Sir temperature of O2 is 4850kelvine option (c)
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Sir now I have got the correct answer as option c- 4800 J ..
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But, mean free path is given by:
l = kT/√2πd²p
Here, l= mean free path
k= boltzmann constant
T= temp. in Kelvin
d= diameter of one molecule
p= pressure of gas
Why you haven't mentioned √2 in the formula?
I have same doubt...
16:13
Answer is : (C)4800 K
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16:23 300°C nhi 300k lena h sir ne galti se 300°C likh dia
300°C lene se answer ayega 9168K
300K se correct answer ayega 4800k(option C)
Right mein bhi soch rha tha kya galti kari hein But temperature kelvin mein hoga 😊