Lecture-4 Radioactivity

[@pooja-t9k]

you are clearing each concept in a easy way, that is the best part, thank you so much, sir

[@physicsbya.singhsir3629]

Thanks dear enjoy it

[@monipathak8334]

The facilities that you have proviide us are very nice sir.. Hardly anyone will have given the convenience of their online classes.. Audio,video clearity👌👌

[@physicsbya.singhsir3629]

Thanks dear..it’s our duty

[@Daku4201]

Class starts 11:05

[@kanhaarora5883]

when we find out Q value then if mass of reactant & product is in Mev then we shall not use multiple term c2

[@shravanchandravanshi9192]

Very Cristal clear lacture sir ji, osm that aaj Ka classs👍👍👍👍👍👍👍👍👍

[@physicsbya.singhsir3629]

👍

[@Nis5367]

The value of temperature is 2.73*10^11k

[@jayprakashnirmalkar7426]

Question karane ka bahut sahi tarika h sir

[@shivamagarg023]

बहुत ही उम्दा पढ़ाते हैं सर आप।
Aapka pyar ese hi bnaye rkhna sir🙏🙏
totally dependent on u🙏🙏

[@artitayde3206]

Thank you sir 🙏

[@mrinaldeka9151]

Sir by doing your class I feel so energetic 😊

[@physicsbya.singhsir3629]

Thanks

[@MohitSharma-yg3hm]

these lecture are full of information sir, sir agar CM frame mae target particle or projectile particle different hae , then also jo Kth hogi in lab frame wo half hogi kya ?

[@anilyadav-gj2qk]

Mza aa gya sir
Thank u so much

[@pallavigurjar1405]

Best explanation with best way to solve problems.... Thank you sir for a great arrangement 👌👌

[@physicsbya.singhsir3629]

Thanks dear

[@mdfirdosh007]

sir quantum bhi karege youtube pe? iski bahut jarurat hai...

[@sunilsaini9059]

great sir

[@RohitYadav-PHYSICS]

Threshold ke formula me capital Mx vo target ka mass h kya

[@sweety6861]

thanku so much,sir
for nyc session

[@anushyapurohit7457]

In 4th ques Q value is not negative it mean KE will be negative thats not right na

[@shipradas8880]

2. a

[@AnuSingh-km9ej]

Thank you so much sir.

[@irfanjanjua987]

Very interesting method sir.

[@Udaymeenakansotikhera]

Ans of last question is
i- b ,ii- a

[@rajkumarthakur571]

🙏🙏🙏

[@Udaymeenakansotikhera]

Sir in last question what is the value of p

[@kanhaarora5883]

sir when will start December batch course??

[@physicsbya.singhsir3629]

Wednesday

[@kanhaarora5883]

okk

[@PHYSICS_BY_G.D]

Sir in question 1 how we came to know that the nuclei of mass no. 180 split into two small nuclei of equal mass no. 90 it is not mentioned in the question that products are of equal masses.

[@ShivamVerma-hg2iv]

TRUE

[@ShivamVerma-hg2iv]

yes not mentioned in question but how does sir took this into concideration.

[@sauravsaha1293]

In the TIFR question fo calculating Q value in amu, how do we calculate Q value in terms of amu, what should be done to c²?
Kindly reply.
Thank you.

[@physicsbya.singhsir3629]

Convert it

[@AKHILESHYADAV-ms5vw]

Saurav this is the best lecture series on nuclear

[@sauravsaha1293]

@@AKHILESHYADAV-ms5vw Very true, I am not at all traumatized.😂

[@Udaymeenakansotikhera]

Sir ji

[@sweety6861]

ans of last ques
ii). A

[@praveshbarthwal2279]

Sir 1Giga eV = 1.6×10^-10joule toh yeh toh bahut small nahi hui kya 1 joule ka bhi 10^-10 time

[@physicsbya.singhsir3629]

How to give such energy to proton

[@praveshbarthwal2279]

@@physicsbya.singhsir3629 matlab proton ko uske rest mass ke 6 times energy dena bhi muskil he.

[@raviraturi6034]

@@praveshbarthwal2279 yes equipments not available.

[@bestrong8249]

sir app jo qn hamee karnee ko detee ho unka ans bhi bataa diyaa kijyee takii hame pataa chal sake ki ham sahii kare h ya galt. please

[@physicsbya.singhsir3629]

Ok

[@dhanpalprajapat498]

K.E.of Zn 0.64 mev

[@shipradas8880]

Temperature produced is 2.74×10^11

[@yogeshyadav698]

Radhe radhe sir

[@roshnichoudhury6795]

Hum application kab tak access kar payenge sir? Matlab sare lectures kab tak hum application me dekh payenge.

[@physicsbya.singhsir3629]

Application launch on Sunday

[@Udaymeenakansotikhera]

I got it

[@praveshbarthwal2279]

Sir 3 Gev energy 2 protons ko de ya 6 Gev ek proton ko baat toh ek hi he. Total energy toh 6 GeV hi use hui

[@physicsbya.singhsir3629]

But beam produced is only 3GeV ..we don’t required to 6 GeV ..it is not easy to produce such energy beams..

[@praveshbarthwal2279]

@@physicsbya.singhsir3629 ok sir thank you

[@rahultripathi900]

kth=70mev

[@shaktipadamahato5619]

Sir ye online course kya sirf abhi ke lie ha.....Ya ab se offline ke sath ek online eisehi bad me bhi chalta rhega

[@physicsbya.singhsir3629]

All time

[@Jamgymhealthcare]

Radhe Radhe

[@PFV-1]

Ye hee h ans.

[@Rulebasedworldorder]

🙏🙏🙏🇮🇳🙏🙏🙏👍

[@rahultripathi900]

30

[@lifeinviewofiitians6769]

I think sir 37.00 pr jo question ka solution h uska answer gate ki answer key se 35 MeV aayega.

[@sayeerisc2928]

240mev

[@artitayde3206]

Thank you sir 🙏

[@shipradas8880]

Temperature produced is 2.74 ×10^11

[@sachin.tiwarisachintiwari6838]

Radhe Radhe sir