i don't know; i have already had a few offers of marriage this week. either i need to become mormon or you all need to have some sort of math/marriage contest or something. oh, and you will have to get my wife to agree to all of it :)
EXCELLENT! What would take me about 5 hours to figure out, you have made me understand in 30 min! (Indeterminate Products, Differences and Powers!) Done!!! Thank you so much!
In your first example, when you factor out x, can you just simply put that in the denominator, then use L Hopitals rule to get 1/-1x^ -2, then factor out this to get, -1x^2, and then apply the limit, which would go to infinity as well?
Hey Patrcikinator why is it that on your 3rd example, the lim as x approaches 1 of 1/lnx and 1/x-1 is infinity? I'm confused on this because when examining the graphs, as x approaches 1 from the left y goes to - infinity and as x approaches 1 from the right y goes to + infinity, but for the limit to exist the limit from both sides must be the same right? Thanks!
***** I don't think the limit as x approaches 1 of the expression 1/(x-1) exists. This is because the right hand and left hand limits calculated at an x value near 1, but not at one, increases or decrease as you approach x=1 on the graph of f from the right or left, respectively. look at 4:00 on this video: L'Hospital's Rule - Indeterminate Differences
@rapzone93 There is no certain grade you learn L'hospital's rule. You have to take Calculus to learn the rule, and not everyone takes calculus in the US.
@fmkk2000 Well, if you're writing it as L'Hopital's rule, there has to be an accent for the "o", which I guess you cannot add on TH-cam (not sure!). And since Hopital translates to hospital, you can for convenience sake say L'Hospital or The Hospital's Rule
One other thing on minute 5:55 you multiply by x/x, when you do so, you get x-1+xlnx in the denominator, how do you get that? if you multiply (1/x)(x-1) you get, x-1/x, and if you multiply this by x, this does not give you x-1, I am pretty sure there is something im not seeing here, i know that you can multiply first the x and then the x-1, and that way you would get x-1, but how do you go from multiplying 1/x * x-1 = x-1/x * x = x^2 -1/x = x-1/x= -1 to x-1?
just like everyone else your videos have saved me...if i was up to me u would be a millionaire, for all the help you have given everyone lol..unless you are already rich haha but seriously i am so grateful!!=)
Hey, does anyone know how to do this? I'm trying to prove that: lim x--> (infinity) for (sqrt(x^2+x+1)+x) I've tried everything that I could think of, and it just blows up. I already know that it equals -1/2 (checked numerically, and with Wolfram), but if someone could show me how to prove it, that'd be great.
i don't know; i have already had a few offers of marriage this week. either i need to become mormon or you all need to have some sort of math/marriage contest or something. oh, and you will have to get my wife to agree to all of it :)
EXCELLENT! What would take me about 5 hours to figure out, you have made me understand in 30 min! (Indeterminate Products, Differences and Powers!) Done!!!
Thank you so much!
Thanks Patrick. All those missed lectures can be made up by your vidz.Really appreciate it.
thank you so much! you always have the perfect videos to help me out when I'm stuck.
cause the are equivalent if you 'undo' the division
@fmkk2000 i guess the guy who has written the most popular calculus textbook in usa also does not know how to spell it after his 8th edition
This video literally saved my life
Larissa Oliveira hahaha but how
@barbaric37 tons of calculus stuff, so come back any time : )
either or... i have seen it taught in both
very nice : )
keep up the good work!!
me make me so proud!
The Prince of Mathematics
In your first example, when you factor out x, can you just simply put that in the denominator, then use L Hopitals rule to get 1/-1x^ -2, then factor out this to get, -1x^2, and then apply the limit, which would go to infinity as well?
On the first example you did, we got the form infinity * infinity. Shouldn't we apply the L'hopital's rule for calculating indeterminate products?
@elejalde3 all the tea in china
how do you know when to use the last method in the first example? or how do you know which one to use?
Hi Patrick, in the second example, did you use the chain rule on e^(1/x) to get e^(1/x)*-x^-2?
Great stuff man, thanks.
No. Exponential Rule
Thanks a lot, your videos are great
This really helps. Thanks a lot :)
Hey Patrcikinator why is it that on your 3rd example, the lim as x approaches 1 of 1/lnx and 1/x-1 is infinity? I'm confused on this because when examining the graphs, as x approaches 1 from the left y goes to - infinity and as x approaches 1 from the right y goes to + infinity, but for the limit to exist the limit from both sides must be the same right? Thanks!
***** I don't think the limit as x approaches 1 of the expression 1/(x-1) exists. This is because the right hand and left hand limits calculated at an x value near 1, but not at one, increases or decrease as you approach x=1 on the graph of f from the right or left, respectively. look at 4:00 on this video: L'Hospital's Rule - Indeterminate Differences
@rapzone93
There is no certain grade you learn L'hospital's rule. You have to take Calculus to learn the rule, and not everyone takes calculus in the US.
This video has saved my hide the day before the 2012 AP Calc exam.
thanks dude. good last example
excellent! u helped me sooo much!
ThNk god for people like you thank you so much
@fmkk2000 Well, if you're writing it as L'Hopital's rule, there has to be an accent for the "o", which I guess you cannot add on TH-cam (not sure!). And since Hopital translates to hospital, you can for convenience sake say L'Hospital or The Hospital's Rule
OMG this was soooooooooooooooooooooooooooooooooooooo helpful
Thank you thank you thank youuuuuuuuuuuuu
you make things seem so easy i swear
@patrickJMT working on it
@iCHAINSAW ha ; )
One other thing on minute 5:55 you multiply by x/x, when you do so, you get x-1+xlnx in the denominator, how do you get that? if you multiply (1/x)(x-1) you get, x-1/x, and if you multiply this by x, this does not give you x-1, I am pretty sure there is something im not seeing here, i know that you can multiply first the x and then the x-1, and that way you would get x-1, but how do you go from multiplying 1/x * x-1 = x-1/x * x = x^2 -1/x = x-1/x= -1 to x-1?
i am a tough teacher : ) tough love, tough love
me too :)
in which class,in USA, do you learn L'hospital rule? 'cause here in Romania we learn it in 11-th grade.
how much would it cost me to have an in ear mic during my calc 2 exams with you on the other side???
@elejalde3 why would you have an microphone in your ear?
just like everyone else your videos have saved me...if i was up to me u would be a millionaire, for all the help you have given everyone lol..unless you are already rich haha but seriously i am so grateful!!=)
hhahahaha! you all would say the EXACT same thing if i were to be your teacher, 100% guarantee it : )
hahah wonderful : )
thank you
ha! that was gauss!
Thanks
marry me?
my professor is a tool and has no idea how to explain anything like you!
i love you!
if this is the scariest thing in your life, you are lucky : )
Hey, does anyone know how to do this? I'm trying to prove that:
lim x--> (infinity) for (sqrt(x^2+x+1)+x)
I've tried everything that I could think of, and it just blows up. I already know that it equals -1/2 (checked numerically, and with Wolfram), but if someone could show me how to prove it, that'd be great.
i guess you are using calculus 6th edition for james stewart ?!!! just wish u have the solution manual for the even problems PLZ PLZ PLZ
wait wouldn't infinity times infinity be 2 infinity?
@TheMexicanRambo1 lol by class he meant grade
@rapzone93 in a math class? because I don't think they teach it in a history class...
we have some formula for differences of indeterminate forms which i cant remember do any one know over here?
Could have also distributed the 1/x to the brackets
that seemed easier to me
great videos but its l'hopital's rule not hospital's, funny I made the same mistake...
it's taught in cal2!!!
ur a boss(: