Trig: Solving Equations 2

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  • เผยแพร่เมื่อ 7 ก.พ. 2025
  • This mini lecture appears in Trigonometry, published by XYZ Textbooks. The video appears in the eBook and is also accessible through one of the QR codes in Chapter 6 of the printed book. Access to all the eBooks at XYZ Textbooks is $45 per year. The print book sells for $50 and includes access to all the eBooks for a year. There are over 700 instructional videos embedded into the eBook, and more are added each year.

ความคิดเห็น • 51

  • @sabrinamorales7646
    @sabrinamorales7646 10 ปีที่แล้ว +20

    My teacher is extremely smart, but he doesn't know how to dumb things down for the class. He's also very vague and expects us to know everything he's saying without showing things on the board. But not this guy. He's very clear about how and when to do things. I'm definitely subscribing. This channel is officially my new online math tutor.

  • @894Time
    @894Time 12 ปีที่แล้ว

    You are a wonderful person for making this. Helps me out a lot more than my class's explanation did!

  • @proteopathy
    @proteopathy 8 ปีที่แล้ว +2

    Such a brilliant teacher. Thank you for sharing your gift with the rest of us.

  • @Kamzui
    @Kamzui 16 ปีที่แล้ว

    OMG You are like God! I was really scared about going to fail my IB Maths Standard Level examinations since I understood absolutely nothing in my maths lessons at school. But you make it all very VERY easy! I love your videos!! =)

  • @fiftydowabill
    @fiftydowabill 15 ปีที่แล้ว

    you find it using the trig inverse buttons on a calculator, or with triangles if you have special angles of 30, 45, or 60

  • @gerardmatar
    @gerardmatar 12 ปีที่แล้ว

    May I just say that i Love you. I have my honors trig final tomorrow and I have never been more clear on this subject than I am now.

  • @sunshine-bj8ih
    @sunshine-bj8ih 5 ปีที่แล้ว

    You are the best! Thank you. I can work this problems without having to struggle with unit circle

  • @abrown5526
    @abrown5526 12 ปีที่แล้ว

    Another great video. Thanks.

  • @Un1ted-Kingdom
    @Un1ted-Kingdom 12 ปีที่แล้ว

    Hi sir why do you add 360 degrees to the values to find out all the rest of the angles..??? It's this ONE THING that i don't get why also my teacher does this?? :) ur great help

  • @wombocombo6878
    @wombocombo6878 12 ปีที่แล้ว

    There are two places where cos= -0.5 one is 120 degrees the other is 240 degrees, if you put cos 240 in deg mode, you will get -0.5

  • @mkayzondy
    @mkayzondy 7 ปีที่แล้ว

    very helpful...thank you

  • @TheStarfish13
    @TheStarfish13 12 ปีที่แล้ว

    THANK YOU JOHN LITHGOW!!!

  • @nanosanchezlopez575
    @nanosanchezlopez575 11 ปีที่แล้ว +1

    Arcos of -1/2 is 60 degrees? :( I thought we had to apply what quadrant it is positive in? 60 degrees is in quadrant 1, where cos is 1/2; cos60 in quadrant 1 is 1/2 not -1/2???? :( Please answer??

  • @herbalist0
    @herbalist0 11 ปีที่แล้ว

    this guy is my hero! i want to hug him!

  • @Kamzui
    @Kamzui 16 ปีที่แล้ว

    Yes it is, but if you don't have a calculator you will first need to find out what cos= 1/2 is, which is 60°. At the end he shows us that all solutions for cos=-1/2 is 120+360K or 240+360k

  • @punjabi555forever
    @punjabi555forever 11 ปีที่แล้ว

    why are the answers in radians for one and in degrees for the other?

  • @starcalibre
    @starcalibre 15 ปีที่แล้ว

    yeah, N would really be a better variable to use if anyone wants to use Mr. McKeagues otherwise valid methods as this implies the set of natural numbers.

  • @yippyyay
    @yippyyay 15 ปีที่แล้ว

    I don't understand how you find the reference angle =(

  • @corbinfisher5703
    @corbinfisher5703 9 ปีที่แล้ว

    Thanks, Super helpful

  • @TRAPPICK
    @TRAPPICK 12 ปีที่แล้ว

    i wanna ask that one too, i tried checking it with my calculator and it says 120...

  • @zcruz123
    @zcruz123 12 ปีที่แล้ว

    do some with tangent

  • @AmzSongwriter007
    @AmzSongwriter007 12 ปีที่แล้ว

    Your method would not work as you cannot use the zero product property.
    It does actually factor out into (2cos ϴ-1)(2cos ϴ+3). You would get cos ϴ=1/2, and you reference angle would be 60°, or cos ϴ=-3/2 which is not between -1 and 1 so that part would have no solutions.

  • @dohafaeq711
    @dohafaeq711 8 ปีที่แล้ว +1

    شكرا شرحك حلو 😍

  • @freedomisjoy
    @freedomisjoy 12 ปีที่แล้ว

    Thanks for the help!

  • @hichloecheese
    @hichloecheese 15 ปีที่แล้ว

    thank you! very helpful!

  • @1carlento
    @1carlento 17 ปีที่แล้ว

    is cos = -1/2
    not 120 degree?

  • @kebabrepubliken
    @kebabrepubliken 17 ปีที่แล้ว

    thank you sir! your the best :D

  • @Blueknightex
    @Blueknightex 15 ปีที่แล้ว

    I don't get it how he got a 60° from
    x=cos-1 (-1/2), I got a 120°....

  • @Blueknightex
    @Blueknightex 15 ปีที่แล้ว

    I get it now. cosx=1/2 is 60° right? but
    there's minus(-) sign in front of 1/2 so it is counted as a negative 60° which is why
    Sir, here drew the 60° graph on the left side because it is a negative. Try not to confuse yourself with a calculator thinking that it is 120° because that shows that you don't have a clear understanding of trigonometry. It's all about knowledge and common sense ;)

  • @Dominator32RW
    @Dominator32RW 9 ปีที่แล้ว

    Thank You!

  • @danemueller756
    @danemueller756 7 ปีที่แล้ว

    thank you. this video gave me an epiphany

  • @halflife1994
    @halflife1994 14 ปีที่แล้ว

    cos = -1/2 is tangent 60 degrees??????? i think its 120 degrees

  • @nanosanchezlopez575
    @nanosanchezlopez575 11 ปีที่แล้ว

    Please make more videos! :(

  • @IIOsOsII
    @IIOsOsII 12 ปีที่แล้ว

    isnt Cos-1(-0.50) = 120? im sure it is

  • @radilfio
    @radilfio 12 ปีที่แล้ว

    Why doesn't he just use the unit circle?

  • @908bruhh
    @908bruhh 12 ปีที่แล้ว

    you do it when you have to find all the available solutions.
    i.e. 2piN

  • @TheChewymac3
    @TheChewymac3 8 ปีที่แล้ว

    Thanks

  • @matokurin
    @matokurin 2 ปีที่แล้ว

    Great

  • @x4812k
    @x4812k 16 ปีที่แล้ว

    he DOES use radians.

  • @brightnessQQ
    @brightnessQQ 16 ปีที่แล้ว

    i wish you were my teacher.

  • @Koldness99
    @Koldness99 16 ปีที่แล้ว

    god bless you

  • @t0myuri
    @t0myuri 15 ปีที่แล้ว

    agreed.

  • @watts-jake
    @watts-jake 6 ปีที่แล้ว

    I love the apology...

  • @1carlento
    @1carlento 16 ปีที่แล้ว

    oh i see thnx for that ;)

  • @washinmachin
    @washinmachin 16 ปีที่แล้ว

    so apparently i didnt do that well on my test...

  • @nanosanchezlopez575
    @nanosanchezlopez575 11 ปีที่แล้ว

    Nvm, I should have kept watching :D

  • @tonianev
    @tonianev 12 ปีที่แล้ว

    Mmmmmm pie

  • @nanosanchezlopez575
    @nanosanchezlopez575 11 ปีที่แล้ว

    :)

  • @user-dr2xt1en6u
    @user-dr2xt1en6u 8 ปีที่แล้ว

    talu

  • @fyhatters
    @fyhatters 12 ปีที่แล้ว

    pendong!