Problem Solving Approach: Photochemistry | Barton Reaction | Beckmann Rearrangement

This video is a part of Problem Solving series, in this series you will get videos which will just contain solution of problem and how you can approach them.
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#CSIR #photochemistry #barton #Beckmann #PSA

[@ashutoshblockbuster2.0]

Sir I had get many great concept by you in easy way u can explain thank you sir❤❤

[@kajaljoshijoshi7144]

Thanks sir

[@maheshamaheshakp4512]

Sir plz add more and more

[@dharantamil9050]

Semma thala

[@anoosharahman5758]

Sir please solve June 2019 Part B organometallic problems.

[@AllBoutChemistry]

Can you specify question number

[@anoosharahman5758]

June 2019 Part B Q: 23. Booklet code B, about isolobal species.

[@sujankundu5918]

Sir i think here beckman fragmentation observed, because there is a possibility of formation of stable benzylic carbocation and cyanide is formed

[@sujankundu5918]

I think product D will be correct, sir please kindly check this

[@angelriyavarghese5863]

sir,can you explain important topics of organic photochemistry

[@saisankargedala]

Hello mam....i hv done cls 12 with pcm....im doing bsc chem...i want to do msc in deemed central universities....as i dont hv maths in 12 class im nt eligible in iits...can u suggest some deemed college where i could do msc

[@pratipchatterjee7646]

How to know beckmann rearrangement or beckmann fragmentation occur

[@AllBoutChemistry]

I don't think Barton fragmentation is any reaction, I think you're asking about beckmann fragmentation

[@AllBoutChemistry]

Beckmann fragmentation occurs if you have EDG on alpha carbon of oxime or if they have quarternary carbon anti to hydroxyl group then fragmentation will take place.

[@rahulkesarwani8561]

sir, what condition must be applied to get option C.
H2SO4 is also used for dehydration then, then how we know that there is possible or dehydration or not in this quesn or other quesn

[@AllBoutChemistry]

Option C is result of dehydration but look at the position of NH it will be possible to get it if we migrate 1° alkyl part in the rexn mechanism and followed by dehydration in the last step but since that migration is not possible thus option c is not favorable option.
It could be confusing if the position of NH in the ring would be according to option B and H2SO4 would've been given in excess. Then product would've been dehydrated result of option B