For those who are having difficult understanding how that h2co3 came Na2Co3 + HCl ----> NaHCo3 + NaCl NaHCo3+ HCl -----> H2Co3 + NaCl (don't confuse ki teesri reaction mei bhi toh wahi hai jo maine dusre number par diye hai. above 2 reactions are only for Na2Co3) Sir instead of giving us the equations individually, gave the final result by adding the above 2 equations which gives us Na2Co3 + 2HCl --> H2Co3 + NaCl also for those who have doubt in how vf=2 In case of acid-base reaction, the valency factor is the actual number of H+ or OH- replaced (i.e. added or lost) in the reaction since 2H replace Na, vf=2 edit: I am not a master of this topic so I may have made mistakes. Do correct me in that case. Thought that I should share my insights since so many of us were having doubt in this
because, methyl orange shows colour change at much more acidic pH. So you'll add more HCl to reach that pH, as a result nahco3 is converted to h2co3. in hph case, colour change happens at around 8 so NaHCO3 presence will give colour change.
diff product nhi h actually Na2CO3 aur HCl se NaCl + H2CO3(H2O+CO2) hi ata h pehle wale case me excess HCl se react krta h ye so shayd isliye hi NaHCO3 bn gya sir ne vf calculation me btaya bhi tha ye example ... 2nd wale case me kyuki NaHCO3 bhi react krega so excess HCl nhi bachega so normal conditions me wahi H2CO3 aya Na2CO3 wale me ..................fir vf factor to ho hi gya H+ ya OH- dekhna h bs kitna gya kitna aya 1st case me ek H add hua to vf 1 aur 2nd case me 2H add hua to vf 2 bs...
waise last me 3 equations se answer aarha h kya aise 2 aur 3 ko dekhe to a+b=a+2b+c arha h but wo to sure galat hoga kyuki moles positive integer hote h .. isse to -b = c arha h jiska bs ek hi ho skta h b=c=0 jo ki hona nhi chahiye
For those who are having difficult understanding how that h2co3 came
Na2Co3 + HCl ----> NaHCo3 + NaCl
NaHCo3+ HCl -----> H2Co3 + NaCl
(don't confuse ki teesri reaction mei bhi toh wahi hai jo maine dusre number par diye hai. above 2 reactions are only for Na2Co3)
Sir instead of giving us the equations individually, gave the final result by adding the above 2 equations
which gives us
Na2Co3 + 2HCl --> H2Co3 + NaCl
also for those who have doubt in how vf=2
In case of acid-base reaction, the valency factor is the actual number of H+ or OH- replaced (i.e. added or lost) in the reaction
since 2H replace Na, vf=2
edit: I am not a master of this topic so I may have made mistakes. Do correct me in that case. Thought that I should share my insights since so many of us were having doubt in this
Thankyou so much bhai.
Thanks bhai 🙏
Thanks man, it's correct
In hph nahco3 does not react with HCl but in second (meoh) nahco3 reacts with HCl explain man 😮💨
Thanks man
to everyone saying sir is wrong..its absolute nuisance as sir is absolutely correct with v.f. calc and with concept as well..
Yeah sir’s calculations are absolutely correct
Best chemistry teacher ever 🙏🏻🙏🏻 you’re so smart and your method of teaching is excellent
Sir , I am unable to understand Why in 1st reaction it is NaHCO3 and in other H2CO3???
nahco3 se jyada he H+ mila diya, So Nahco3 H2Co3 bun gaya
Acidic medium me Hco3- exist nahi karega
I guess conjugate acid base pair liye h sir 🤧
Bhai indicators alag hai
Absolutely mind-blowing
in first titration Na2CO3 goes to NaHCO3 but in 2nd titration it goes to H2CO3 , why is that?
because, methyl orange shows colour change at much more acidic pH. So you'll add more HCl to reach that pH, as a result nahco3 is converted to h2co3.
in hph case, colour change happens at around 8 so NaHCO3 presence will give colour change.
Every vf calculation are correct
nice explanation
agar iit clear hua to ek din apse zarur milunga
Why does NaHCO3 reacted inMeOH while not in Hph ?
@@AbjSir thanks bro for your explaination
Thank you sir❤,really very helpful 😇
Sir why is there different products and different VF of Na2CO3 in case of Hph and MeOH
diff product nhi h actually Na2CO3 aur HCl se NaCl + H2CO3(H2O+CO2) hi ata h pehle wale case me excess HCl se react krta h ye so shayd isliye hi NaHCO3 bn gya sir ne vf calculation me btaya bhi tha ye example ... 2nd wale case me kyuki NaHCO3 bhi react krega so excess HCl nhi bachega so normal conditions me wahi H2CO3 aya Na2CO3 wale me ..................fir vf factor to ho hi gya H+ ya OH- dekhna h bs kitna gya kitna aya 1st case me ek H add hua to vf 1 aur 2nd case me 2H add hua to vf 2 bs...
waise last me 3 equations se answer aarha h kya aise 2 aur 3 ko dekhe to a+b=a+2b+c arha h but wo to sure galat hoga kyuki moles positive integer hote h .. isse to -b = c arha h jiska bs ek hi ho skta h b=c=0 jo ki hona nhi chahiye
@@ok-ez1xl are bhai dono baar gram equivalent alag hai HCl ke tum 2 and 3rd ko equate nahi krr skte
thank you sir ❤❤❤❤❤❤❤❤❤❤
10:00 next time double titration revise karna ho toh yaha se start kariyo.
Haha lol, I also came for the same. Test mein atak gya tha to realize kiya double titration bhul gya
@@alphaiitd1😅...good luck
Thank you so much sir :)
Thanks a lot sir!
sir agr 8-10 k bich m hogi ph toh HPh ka colour ky hoga?
Tab color change dikhega
We can't detect that colour. That will be very light pink.
Great explanation
Lecture 11
Thank you
Very nice explanation sir 👌👌
Can't understand the way you choose the valency factors in the calculations regarding double titration in this as well as the next video.
These are acid base rxn so the vf depends on (H+ gained or OH- lost per molecule for base )and H+ lost or OH- gained per molecule for acids)
U should repeat the calculation of vf lecture again….sir had explained very clearly
@@sahebOp_exactly..
Thanks 😂
Sir waha p jab na2co3 h2co3 m convert hua to valency factor 2 kaise hua???
na2co3 is basic in nature ...sir covered same example in vf video
@@_jot_singh_7679 can you tell me in which video did he say?
@@nitinchinmay260 may be in 3rd or 4th
How to calculate values of last question plz tell
it gained two h+ thats why
Thank you sir, really helpful!!
Most welcome!
Om om om….om om
❤️