Here's an explanation to why 6 is to be added: The BCD system consists of 4 bits, so the total number of values it can have is 2^4=16. But since the numbers from 10 to 15 of the total possible 16 are considered invalid, if you add 6, the invalid states are skipped and the code returns to valid BCD code again.
@@sugamrajput5951 If a four bit sum is greater than 9, or if a carry out of the group is generated,it is an invalid result. Add 6(0110)base 2 to the four bit sum in order to skip the six invalid states and return the code to bcd
What is the reason behind giving importance to 8421 weighted code among other codes And I want to know why XOR gate is used for 2's complement while performing arithmetic operations
If I am add bmtwo bcd number 16 and 17 I am add first 16 and 17 result is 100001 but which number I am add to check the result please tell me now madam I see your all video for gate préparation please immediately tell me my answer
Invert the bits which means Do the one's complement first and then add 1 now in case if 101010 We find the one's complement which is 010101 And now add 1 to this we get 010110 this is your answer
Abhishek got it wrong. See, BCD uses 4 bits to represent 10 digits if decimal number system. With 4 bits you can represent 2^4 = 16 numbers. But we're only representing 10 numbers, There are 6 numbers which are unassigned, or we can say, invalid. So suppose we did 7+3 in BCD (0111 +0110) the sum we get is 1101 which is invalid, when we add 0110, we're moving the sum 6 places down so it gets mapped to a valid BCD code. I hope you understand.
@@sainikhilrajakaveeti6342 they're invalid Because we represent 10 decimal digits with 4bits and total no of combinations under 4bits are 16 tht is 2^4=16 but only 10 of these combinations are use for encoding the 10 decimal digits that is 0 to 9 hence some 6 Left Combinations are invalid in BCD but Incase To represent 2 digits number you need 2x4 =8 bits
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Here's an explanation to why 6 is to be added:
The BCD system consists of 4 bits, so the total number of values it can have is 2^4=16. But since the numbers from 10 to 15 of the total possible 16 are considered invalid, if you add 6, the invalid states are skipped and the code returns to valid BCD code again.
Thank you 🙂
Bcoz there is 6 means 10 to 15 is invalid so add 6 to correction
thanks you so much ❤️
finally sb explained this part :) thnx
Thanks 😊
Disliker are those who have joined paid classes and can't digest free education
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Superb explanation. I looked for where the 6 came from ... it allowed me to better understand the method. Thank you !
Sir,
Thank you for giving a best class to understand the bcd addition,but I think you must solve another example having 3 digit numbers like 598+546.
thank you ma'am you are the best
Respect from South Africa.
Very nice explanation madam ....iam very big fan of ur lecture
U should make a playlists of this series.
Explanation was quite good.
Good explanation. Excellent
Nice teaching
Fir your explanation skills ki ❤
But why do you add 6 for correction ?
You can account the number between 9------ 15 is 6 do you understand it
Same doubt I have, how will we know to correct BCD addition?,we will have to add 6
@@sugamrajput5951 If a four bit sum is greater than 9, or if a carry out of the group is generated,it is an invalid result. Add 6(0110)base 2 to the four bit sum in order to skip the six invalid states and return the code to bcd
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What is carry ?
Thank you...may Allah guide you to islam
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Veri good class sister
Exilent mam
Good class
On point thank you
Okay it usually a guy who saves my a$$ before the exam but it’s a girl now which amazing 💯
Thx .
Everything was good apart from the voice! Thankyou v.Informative
Give a clarity about adding 6
Just add 6 if it's greater than 9
@@animeexplorerxd4356 greater than 9 what?
For any value greater than 9 we can add 6
Where did you get 8421 please tell me
What is the reason behind giving importance to 8421 weighted code among other codes
And I want to know why XOR gate is used for 2's complement while performing arithmetic operations
You class is very useful but unfortunately I cannot understand what you are saying. Is it possible to add subtitles? Thank you
Ma'm why did u add 6 to correction..
Ma'am how to find bcd of alphabetic letter
Good class m
Thank u❤
Super 👌
nice video
I wish you were my teacher tho😢
Thanks a lot
Sis ur explanationvery very nice and ur English easily understand and very good tanq 🤴🤴🤴🤴🤗
If I am add bmtwo bcd number 16 and 17 I am add first 16 and 17 result is 100001 but which number I am add to check the result please tell me now madam I see your all video for gate préparation please immediately tell me my answer
What would be the 2'a complement of (101010)_2?
Invert the bits which means Do the one's complement first and then add 1 now in case if 101010
We find the one's complement which is 010101 And now add 1 to this we get 010110 this is your answer
Is is simple or on signed magnitudr??
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thank you mam
Why 6 is added after bcd addition
BCD addition for 12 ,3 is 15(1111)... Without any carrier..is it crt??
Binary division plz
I don't have any words ❤️🙏
But why only we add 6 why we don't add any other number ????
wow did you just say the exact same thing like 3 times in a row? yes, yes you did
Thanks
Please explain why exactly 6 is to be added.
Why add 6 only?? Why not other numbers
Shashwat Sinha because bcd having only 6 bit no. To represent diff character
Abhishek got it wrong. See, BCD uses 4 bits to represent 10 digits if decimal number system. With 4 bits you can represent 2^4 = 16 numbers. But we're only representing 10 numbers, There are 6 numbers which are unassigned, or we can say, invalid. So suppose we did 7+3 in BCD (0111 +0110) the sum we get is 1101 which is invalid, when we add 0110, we're moving the sum 6 places down so it gets mapped to a valid BCD code. I hope you understand.
sir, exactly there are 6 invalid codes i.e., 1010, 1011, 1100,1101, 1110 and 1111. so to make BCD sum a valid sum 6(0110) must be added.
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Tnk u
How to take 6
Why you are adding 6 in the result case tell me now
sir, exactly there are 6 invalid codes i.e., 1010, 1011, 1100,1101, 1110 and 1111. so to make BCD sum a valid sum 6(0110) must be added.
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Thank u
Why do you add 6 not other number
sir, exactly there are 6 invalid codes i.e., 1010, 1011, 1100,1101, 1110 and 1111. so to make BCD sum a valid sum 6(0110) must be added.
@@sainikhilrajakaveeti6342 they're invalid Because we represent 10 decimal digits with 4bits and total no of combinations under 4bits are 16 tht is 2^4=16 but only 10 of these combinations are use for encoding the 10 decimal digits that is 0 to 9 hence some 6 Left Combinations are invalid in BCD but Incase To represent 2 digits number you need 2x4 =8 bits
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but what if you add 15 + 15 , then there is carry of 1 and the sum >9 so do you add the six twice or what?
why add 6 what is special ,i can see direct thos vedio
Mam 6 add kyu kiye...
In BCD code, 10-15 (10,11,12,13,14,15-which are six digits in total) are invalid. To replace these,6 is added.
@@hehehehehe1878 thanks mam
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Can you help me... (1001)+(1001)=?
Thank you.. Mam
why adding 6
SHAKIR
Davis Steven Miller William Miller Matthew
voice is so annyoing though
Pratyay Bhattacharya you’re being taught something for free. Stop complaining.
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Hi Madam I want bcd addition coding explanation
Can u help me...how 0011+0011
Athirah yo 0110
@@arshbains ok tqs
Maam your voice can break a glass, its so annoying