I'm currently taking Calculus III in Vancouver, British Columbia, Canada. My teacher speaks terrible English, and I learn nothing from lectures, you are saving me with your Calc III lectures and suggestions of what to review. Keep it up.
I'm taking calc III in Ontario, and my prof can't pronounce a single word correctly. What's worse is that he completely skipped over the section 11 stuff Leonard put up and started with taking derivatives and integrals of vector valued functions. If videos like this weren't put up I would never understand what we're actually studying. Our education system needs a complete overhaul and the ability to speak clearly must be mandatory.
Pardon my saltiness, but what my Korean teacher could barely recite over this topic in an entire week while i couldn't comprehend shit; I learned all this in 54 minutes. Thought it was me and not the teacher, boy I was wrong! Thank you so much good sir! Ill be using these videos when I take Cal 1
Something that might help in comprehending the vertical and horizontal shifts is understanding that each polynomial could individually be equal to zero. In finding the X component of the center of a circle (x-2)^2 + y^2 = 2^2, if the (x-2) = 0 then X = 2, and then turn around an do the same for Y. For me this is an easier way to think about it. Its the exact same thought process as finding X and Y intercepts for linear equations, just being applied to a different type of problem.
Wait your test are multiple choice? I wish I would of had you as my professor you saved my life while taken statistics (which I took online) and now with algebra. Thanks a lot Prof. Leonard.
Professor, looking at the equation of a circle I wondered if humans invented the equation to fit a pre-conceived idea, or if the equation of a circle already existed just waiting to be discovered.
The given formula y=4ax^2 works only when the vertex = 0,0 , parabola opened rightwards. These formulas are based on an idealist reduction of eccentricity =1
I'm currently taking Calculus III in Vancouver, British Columbia, Canada. My teacher speaks terrible English, and I learn nothing from lectures, you are saving me with your Calc III lectures and suggestions of what to review. Keep it up.
ha, I'm doing the exact same! Calc 3, but he said to review conic sections!
I'm here too guys! My professor told me the same. I'm in Cal 3.
I'm taking calc III in Ontario, and my prof can't pronounce a single word correctly. What's worse is that he completely skipped over the section 11 stuff Leonard put up and started with taking derivatives and integrals of vector valued functions. If videos like this weren't put up I would never understand what we're actually studying.
Our education system needs a complete overhaul and the ability to speak clearly must be mandatory.
Lol right now im taking Calc 3 at UBC in Vancouver too!!
Seems we're all here for the same reasons lol!
Pardon my saltiness, but what my Korean teacher could barely recite over this topic in an entire week while i couldn't comprehend shit; I learned all this in 54 minutes. Thought it was me and not the teacher, boy I was wrong! Thank you so much good sir! Ill be using these videos when I take Cal 1
It's hard not to turn math into a spectator sport with Prof Leonard teaching.
Professor Leonard sent me from his calc 3 chapter 11.6 video to here!
lol sameeeee
lmaooooo
same
lol same here. i found vectors with 3d a bit messi tho.hard to understand
thanx prof leonard, you are my favourite lecturer in youtube.
Something that might help in comprehending the vertical and horizontal shifts is understanding that each polynomial could individually be equal to zero. In finding the X component of the center of a circle (x-2)^2 + y^2 = 2^2, if the (x-2) = 0 then X = 2, and then turn around an do the same for Y.
For me this is an easier way to think about it. Its the exact same thought process as finding X and Y intercepts for linear equations, just being applied to a different type of problem.
thank you soo much Prof, your videos are really helpful
I found out your channel short time a go and it is totally amazing. Thank you a million 😍😍😍
I like circles. Its gonna be very useful once i make a game one day in coding
Wait your test are multiple choice? I wish I would of had you as my professor you saved my life while taken statistics (which I took online) and now with algebra. Thanks a lot Prof. Leonard.
I hate multiple choice. No partial credit
Im sure they still had to show work
Hey Prof. Leonard, are you going to do any vids on trigonometry?
they are up now
@@siamhasan288 Good thing you let him know, he was clueless about trig. for the past 4-5 years....
@@djt6fan hmm
I'm pretty he’s a software engineer already
At 13:34 shouldn't the type 2 parabola have (k,h)? Since the type 1 has (h,k)
Type 2 is still (h,k), because h and k still mean same things in Type 2. h -- horizontal shift along x-axis, y -- vertical shift slong y-axis.
@@PastryDonut btw type 2 isn't a function right? so what exactly is it?
@@dankster7993 Yep, these are equations
Who's here for Cal III?
I here for cal2
Meee
Am I the only one who still reads textbooks anymore? 💀🤓
the translations are the same as type one but its reflected about y=x.
Thank you so much for these wonderful videos.
good job professor
Professor, looking at the equation of a circle I wondered if humans invented the equation to fit a pre-conceived idea, or if the equation of a circle already existed just waiting to be discovered.
2nd one
awesome Prof
what about these sir,
(x - h)² = 4p (y - k)
(y - h)² = 4p (x - h)
how are these related to the formulas you have just taught to us??
thank you so much prof , l just don't get the vetex how to find it ?
Thanks!
Epic!!
thaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaank u soooooooooooooooh much
Solid!
what about y=4ax^2 how does that differ from this ?
The given formula y=4ax^2 works only when the vertex = 0,0 , parabola opened rightwards. These formulas are based on an idealist reduction of eccentricity =1
Sir please this video has a poor camera quality I can’t see from the board well
11:00
11:00