+MasterOfDesaster They may be given, or to make it more tricky you may be given moles and volume then have to calculate the concentration. Anything not mentioned is assumed to be zero.
It is incredibly rare for water to split into its ions. So the concentration of these ions will be very small, so the bottoms numbers are very small - so kc must be big!
![7.1/R2.3.1 Outline the characteristics of systems in a state of equilibrium [SL IB Chemistry]](http://i.ytimg.com/vi/hSxTNEyTogU/mqdefault.jpg)
![7.1/R2.3.1 Outline the characteristics of systems in a state of equilibrium [SL IB Chemistry]](/img/tr.png)
![7.1/R2.3.4 Apply Le Chatelier's Principle [SL IB Chemistry]](http://i.ytimg.com/vi/xQ19LBdoLis/mqdefault.jpg)
![6.1/R2.2.1 What is the Rate of Reaction ? (definition/graphs) [SL IB Chemistry]](/img/n.gif)
How do you know the values of the concentrations? Are they given?
+MasterOfDesaster They may be given, or to make it more tricky you may be given moles and volume then have to calculate the concentration. Anything not mentioned is assumed to be zero.
is that g mod?
the demonstration of equilibrium was so good hahahaha
How did u get the "10^14" in 3:43
I understood why the concentrations don't affect Kc. But can you please tell me why the pressure has no effect of Kc? Why is it only temperature?
After teaching this for 16 years and now spending 10 mins pecking around online I can say that I still do not know the answer to this!
@@ibchemvids time to do an IA on this lol
Can someone explain why Kc is enormous, I dont understand his explanation at 3:25
It is incredibly rare for water to split into its ions. So the concentration of these ions will be very small, so the bottoms numbers are very small - so kc must be big!
1:57 why is there a lady on the ground? lmao