The correct answer is 8 itself. I made a error while writing the no of total DNA sample loaded. It should be 50 and not 25. Thus no. Of recombinats= 4 no of total DNA loaded=50. So linkage distance=4/50*100=8 cm So sorry for the error on my part!
mam in question 12 (IN the formula the total protein is in mg ) and in 13q you are converting mg to ug if I did in that way then my ans 1 SO plz clear this that why u did in that way ?
Thnku mam...mam in frst qstion ansr is 8 bt u markd d option which is 18....ansr should b 8 ??? And in 101 qstion....mam u hv writtn 4÷25*100=8....accrding to this...it should cm 16....plz mam clear this doubt....
The correct answer is 8 itself. I made a error while writing the no of total DNA sample loaded. It should be 50 and not 25. Thus no. Of recombinats= 4 no of total DNA loaded=50. So linkage distance=4/50*100=8 cm So sorry for the error on my part!
![LAVROV's interview with Tucker CARLSON 😁 [Parody]](http://i.ytimg.com/vi/mbMemqc-QEk/mqdefault.jpg)
Thanks a lot
In 101
I think DNA loaded should be 50
4/50×100=8?
Please Correct me if I wrong.
Yes you are absolutely right
Mam please correct Q.101 at time 21:38. It should be 2/25 x 100 = 8.
The correct answer is 8 itself. I made a error while writing the no of total DNA sample loaded. It should be 50 and not 25. Thus no. Of recombinats= 4 no of total DNA loaded=50. So linkage distance=4/50*100=8 cm
So sorry for the error on my part!
mam in question 12 (IN the formula the total protein is in mg ) and in 13q you are converting mg to ug if I did in that way then my ans 1 SO plz clear this that why u did in that way ?
mam please make video on BOD and COD problems
BOD COD se v questions aata hai ?
Oky dear I’ll do it
plz explain bod and DOD
Thank you sooo much maam
Welcome!!🤗
Thank you ma'am
Welcome ☺️
thank you mam. can u make us solve more genetics and techniques questions?
Yes part 2 coming soon!
Mam please explain again Qno. 183 ??
Thnku mam...mam in frst qstion ansr is 8 bt u markd d option which is 18....ansr should b 8 ??? And in 101 qstion....mam u hv writtn 4÷25*100=8....accrding to this...it should cm 16....plz mam clear this doubt....
It should be 2/25 x 100 = 8
@@shilpasinha272 ...yss i think recmbinant is 2 not 4
The correct answer is 8 itself. I made a error while writing the no of total DNA sample loaded. It should be 50 and not 25. Thus no. Of recombinats= 4 no of total DNA loaded=50. So linkage distance=4/50*100=8 cm
So sorry for the error on my part!
Tqsm
Most welcome ☺️
Mam would u please make some more vedio related to icmr jrf life science part 1 as well as 2nd also
Yes I will👍
@@IntrovertGeek thank u so much mam
Thanks a lot mam , can you make a solve video on molecular biology also ?
👍 yes good idea
I didnt get 183 question explaination,could u explain again in next video.
Oky I’ll do a similar question
Thank u so much
Same here ma’am plz explain it again
Mam you have uploaded only 6 parts? Of bioinformatics
Yes
Hello ma'am I have cleared csir LS how to get the certificate will they release any notification?
Hello
Hello 1