A big round of applause for you sir. I have been following Computational Photonics book by Marek S Wartek and had a hard time understanding the topics as no geometry was involved. Now you have made my life simpler.
Why exponential terms will cancel out? I think there is a term k.z. But for different medium k will be different because k=(w/v),where w is the angular frequency of the wave and v is the velocity of the wave in the medium and w is same but v is different for different medium.
Thank you for this video! Suppose we want to calculate R and T for the second interface, external to which is air again, so that, for instance n2=1,5 and n3=1. Can we use the same equations? It appears to me that T becomes greater than 1 and I do not understand how this can be. Thank you very much.
I think it's a mistake, power transmission coefficient is (1-R^2), the part written around minute 13 is wrong and violates power conservation, he needs no multiply T by n2/n1 I guess if u want to state it that way, but i just use T=(1-R^2), this can be proved when you calculate the power of the incident and reflected wave, power = (E x H*)
Thank you, I also think there are some mistakes with transmission coefficient. But it is strange that the lecturer can solve the reflection coefficent correctly by these equations, but not correct for transmission.@@thedarkcider4450
Pregunta 1 Hello, I need your help plz, good video.. Estimate the approximate output coupling power losses (in percent) from Fresnel reflection at normal incidence in a phosphor/air interface, where the phosphor has an index of 2.3 and air has a refractive index of 1.
A big round of applause for you sir. I have been following Computational Photonics book by Marek S Wartek and had a hard time understanding the topics as no geometry was involved. Now you have made my life simpler.
The internet states that Fresnel is pronounced "Fray nel". You do a nice job. And don't forget Einstein's statement about simplicity.
thank you so!
do you have a video explaining the antireflection coating?
are we missing a factor of n_2 for the E_t equation?
Why exponential terms will cancel out? I think there is a term k.z. But for different medium k will be different because k=(w/v),where w is the angular frequency of the wave and v is the velocity of the wave in the medium and w is same but v is different for different medium.
Thanks for the video! So a good mirror would have n2 >> n1?
Exactly! ... or an n2
Thank you! At z = 0, why time dependence cancels out, please? OK, the phase term becomes a constant?
Yes, when we take ratios of amplitudes the e^(iwt) term will cancel out, so we usually ignore it.
@@JordanEdmundsEECS Thank you!
Thank you for this video! Suppose we want to calculate R and T for the second interface, external to which is air again, so that, for instance n2=1,5 and n3=1. Can we use the same equations? It appears to me that T becomes greater than 1 and I do not understand how this can be. Thank you very much.
I think it's a mistake, power transmission coefficient is (1-R^2), the part written around minute 13 is wrong and violates power conservation, he needs no multiply T by n2/n1 I guess if u want to state it that way, but i just use T=(1-R^2), this can be proved when you calculate the power of the incident and reflected wave, power = (E x H*)
Thank you, I also think there are some mistakes with transmission coefficient. But it is strange that the lecturer can solve the reflection coefficent correctly by these equations, but not correct for transmission.@@thedarkcider4450
Why can't we have E_i = E_r + E_t as the third equation? Won't the magnitude of the Electric field be conserved?
It will be the violation of boundary conditions.
Great presentation but there was no explanation or insight regarding the boundary conditions.. it was just stated
Pregunta 1
Hello, I need your help plz, good video..
Estimate the approximate output coupling power losses (in percent) from Fresnel reflection at normal incidence in a phosphor/air interface, where the phosphor has an index of 2.3 and air has a refractive index of 1.
Excellent! Thanks you.
11:48
do u mean the corkscrew rule ?
You're the best
why Ei=nHi? i think it should be (n/c)Ei=Hi
The n-looking thing is actually the Greek letter eta (the wave impedance), not the refractive index. Good eye!