Recently, I found your channel, and I must say it is one of the most amazing channels I've come across on these topics. The explanations of each topic are great, delivered with extraordinary enthusiasm
in assinment 1st : A={1,1/2,1/3,.......} upper bound should (1,0) according to question at a point there will be 1/infinity which will be equal to 0. Am i right ??
Good method but sir jinko bilkul ku6 nhi aata unko UE math waali language smj ni ayegi...plzz thora Aur simple btaya kren ..I mean mathematical k saath apni wording men b likh diya kren
Ye bonded hy set hy q k ye zero ko approach Kar rahay hen .ye zero or 1 k dermeyan rahy ga . Es ka upper bond bhi hy or lower bond bhi hy .(0,1] Sup=1 Inf= 0
set A is a bounded set because elements are forward to wards or going close to 0, so if it is bounded set then they have upper and lower bounded Upper bounded= [1 to ∞) Lower bounded= (-∞ to 0]
Jazak Allah sir.
Assignment
Upper bound=[1,infinity)
Lower bound=(−infinity,0]
As the upper and lower bound exist so this is bounded set
I'm totally satisfied with your method
Recently, I found your channel, and I must say it is one of the most amazing channels I've come across on these topics. The explanations of each topic are great, delivered with extraordinary enthusiasm
Thanks for appreciation
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I am totally satisfied with u
Very well explained!
Finally understood this concept 🙏
Upper bound=[1,infinity)
Lower bound=(-infinity,0]
So it is bounded set
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Aslamoalikum sir is topic ky related exam m question kis terha sy pochy jaty hai . Discrete mathematics ma please zaroor btaiy ga please🙏🙏🙏
Really
Very good method.
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Simple teaching method that's helpful for me also for others💌
Just trying to be helpful ♥️
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Assignment:
Its upper bound is 1 and lower bound is zero so its bounded set
How lower bond is zero?
@@msbajwi3505 qk values km ho rahi hain. 1 divide ho raha h or divide hoty hoty infinite tk jae ga. 1/infinite = 0.
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in assinment 1st : A={1,1/2,1/3,.......}
upper bound should (1,0)
according to question at a point there will be 1/infinity which will be equal to 0.
Am i right ??
Thanku sir
Great method sir jii
Is upper bound bigger value and lower bound smaller value. Please tell.
Upper bound =[1, +infinity)
Lower bound =(-infinity ,0]
Is it correct sir
Right
(-infinity,1] upper bound and it has no lower bound sir,so it is not bounded set
MashAllah sir great
Good method but sir jinko bilkul ku6 nhi aata unko UE math waali language smj ni ayegi...plzz thora Aur simple btaya kren ..I mean mathematical k saath apni wording men b likh diya kren
Aoa sir...may i th k a is also belong to R....but you said a belong to A.
Thanks you so much sir
Your method of teaching very good sir
Great sr
Ye bonded hy set hy q k ye zero ko approach Kar rahay hen .ye zero or 1 k dermeyan rahy ga .
Es ka upper bond bhi hy or lower bond bhi hy .(0,1]
Sup=1
Inf= 0
Prove that set of whole num is not bounded above??? Plz sir
Upper bound [1, ♾️)
Lower bound (-♾️,0]
Yes it is bounded
Upper bound=[1,0)
Lower bound=o .it approach to o so it is bounded set. Sir yh dkhn correct hai kia?
ASSIGNMENT
Upper bound [0,i.finity]
Lower bound[-infinity,1]
It's wrong
Upper bound[0,infinity)
Lower bound(-infinity,1]
This is bounded set
Sir is this correct
thanku very well explained
set A is a bounded set because elements are forward to wards or going close to 0, so if it is bounded set then they have upper and lower bounded
Upper bounded= [1 to ∞)
Lower bounded= (-∞ to 0]
Gud
@@m.k.f.amathematicsknowledg1668 Thank you sir
Lower bond kese aya
Nice method..sir
Assignment wala set bounded set ho ga ya nhi????
Assignment
Upper bound =[1,infinity)
Lower bound not exist so it not bounded set
Sir it approaches to zero but not equal to zero
How we find lower bound??
Plzz answer me
upper bounds of A (0 , +infinity)
lower bounds of A (_infinity,1)
A is bounded set
Bounded above and below ni bataya sir
Here lower bound is 1 and and upper bound is 0 bcs 1,1/2,1/3... Approaches to 0. And is bounded set.
Upper bound " 0 to infinity
Lower bound " -ive infinity to 1
Upper bound:1 to infinity
Lower bound:0 to -ve infinity
I have also noticed.
Love you sir
It's not a bounded set because we don't know about the upper bound
[-infinity , 1]
[⅓ , infinity]
Sir upper bound will be [1, ♾️)
And lower bound is 1/♾️ = 0 so lower bound is ( ♾️ ,0 ]
Upper bound:{ 1,+infinity)
Lower bound:( _infinity, 0}
Uper bound =[ 1,infinity)
and
Lower bound =[0,-infinity)
Here uper bound are 1 and lower bound 0 b.c it approch to zero so it s bounded set
Correct answer
Upper bound 1 to infinity
And lower bound 0 to _infinity
Plz sir, tell me my answer is correct or not
upper bound 1 to positive infinity while no lower bound
Please dear response our desirable result ,to solve chapter 1 book naame real analysis writer name wader roder
How [1,1/2.......) Are bounded??????
Because icki limit exist krti h jo k 0 h
Nice sir
1 uppor ifinty lgana sa 0 lower bounded
Great method sir
Upper bound 1,infinity
Upper bound=[1, ♾️)
Lower bound=(- ♾️,0]
So,it is bounded.
Ye bounded b ni h or na ye upar h
Upper bound 1infinate
Upper bound is 1 and lower bound is 0
Lower bound infinity, 0
Upper bownd 1 to infinity and lower bound not exist
Upper bound 1
Lower bound 0
upper bound 1 lower bound 0 .it is bounded
Correct answer
Upper bound doesn't exist
Lower bound is negative infinity to 1
This is not bounded se
UB=1
LB=0
Here uper bound are 1 and lower bound 0 b.c it approch to zero so it s bounded set