For anyone wondering about Q.20, this how to answer it: Chance of tails = 1/2 Chance of only tails per x number of throws = (1/2)ˣ counter probability = chance of an outcome not happening Can be calculated by taking a 100% chance in the form of 1 and subtracting chance of outcome so, Chance of not getting tails = 1 - 1/2 Chance of not only tails per x number of throws = 1-(1/2)ˣ All of this applies to chance of getting heads, therefore: Chance of only tails or only heads per x number of throws = (1/2)ˣ + (1/2)ˣ = 1ˣ/2ˣ + 1ˣ/2ˣ and as 1 to the power of anything ≥1 is 1, and a dice cannot be thrown minus or effectively zero times 1ˣ/2ˣ + 1ˣ/2ˣ = 1/2ˣ + 1/2ˣ = 2/2ˣ Chance of this not happening = The chance of at least 1 head or 1 tail, so Chance of at least 1 head or 1 tail = 1 - (2/2ˣ) x= number of throws = n 1 - (2/2ⁿ)
For anyone wondering about Q.20, this how to answer it:
Chance of tails = 1/2
Chance of only tails per x number of throws = (1/2)ˣ
counter probability = chance of an outcome not happening
Can be calculated by taking a 100% chance in the form of 1 and subtracting chance of outcome so,
Chance of not getting tails = 1 - 1/2
Chance of not only tails per x number of throws = 1-(1/2)ˣ
All of this applies to chance of getting heads, therefore:
Chance of only tails or only heads per x number of throws = (1/2)ˣ + (1/2)ˣ = 1ˣ/2ˣ + 1ˣ/2ˣ and as 1 to the power of anything ≥1 is 1, and a dice cannot be thrown minus or effectively zero times 1ˣ/2ˣ + 1ˣ/2ˣ = 1/2ˣ + 1/2ˣ = 2/2ˣ
Chance of this not happening = The chance of at least 1 head or 1 tail, so
Chance of at least 1 head or 1 tail = 1 - (2/2ˣ)
x= number of throws = n
1 - (2/2ⁿ)
Is there paper 2 by any chance
Sorry, we did it in class. I put these together for the group I teach but am glad if you found them useful.
My condolences