the worst part about this is that most engineers would just say "oh the eyebolt and the ropes can handle more than enough force to ever need to account for" and none of this would be needed this problem literally had me up for hours bro wtf
*******at **14:03**, the actual value is 367851.309 for cos139.2^2 * 800^2******* issue: you plugged in cos 139^2, not cos139.2^2 . even little number make big difference for cosine my fren resultant force is actually 137.402 lb or 1246.068 lb as a result, double check your work homies
At 14:45 when you mention how to get to the next step, "doing these two squares, adding all of them together and using the quadratic formula", can you show those steps?
(-B +- Sqt(B^2 - 4AC)) / 2A A = 1 , B = -1798 , C = 543035 , note( Don't forget to subtract the 640000 on the other side of the equal sign before using the quadratic equation.) The quadratic will give you the two values for Fr. Writing it all out is a LOT of simple arithmetic. You can handle it and it is good practice. If you are allowed to use a TI-84 or better you can enter the quadratic (ax^2 + bx + c = 0)into the solver feature and solve for those values.
the worst part about this is that most engineers would just say "oh the eyebolt and the ropes can handle more than enough force to ever need to account for" and none of this would be needed
this problem literally had me up for hours bro
wtf
*******at **14:03**, the actual value is 367851.309 for cos139.2^2 * 800^2*******
issue: you plugged in cos 139^2, not cos139.2^2 . even little number make big difference for cosine my fren
resultant force is actually 137.402 lb or 1246.068 lb as a result, double check your work homies
I dont think so. Im getting the same resultant force as he did
At 14:45 when you mention how to get to the next step, "doing these two squares, adding all of them together and using the quadratic formula", can you show those steps?
(-B +- Sqt(B^2 - 4AC)) / 2A
A = 1 , B = -1798 , C = 543035 , note( Don't forget to subtract the 640000 on the other side of the equal sign before using the quadratic equation.)
The quadratic will give you the two values for Fr. Writing it all out is a LOT of simple arithmetic. You can handle it and it is good practice.
If you are allowed to use a TI-84 or better you can enter the quadratic (ax^2 + bx + c = 0)into the solver feature and solve for those values.
For the part (.866Fr - 830)/800, where did the 830 come from? Same goes for the -360
Add j values 480 + 350 to get -830. -360 is the final k value for F2.
Thank you so much!
thank you so much for this
Godsend of a video thank you
do you have venmo?
fr fr
Thanks for the video, but the volume is way too low
Angles of F3??