Answers never matter which matters for us is the way which is provided in utmost clarity and in depth . Thank you sir and keep making these videos for us.
@@PHYSICSSIRJEE Sir I have a small silly doubt that everyone says that string only applies tension force when string is taut(tight), but sir in catenary the string is not tight or taut(as otherwise it would be straight), the string is just hanging casually, so sir by that logic shouldn't the tension in string be 0??? Please help me sir🙏
*DOUBT* 12:25 sir i got the angle as 53 degrees but i can't get the value of k...I tried a lot of manipulations but k is always getting canceled out...please help me out on how to find k
@@PHYSICSSIRJEE but sir that is for the third part of the question na? when block begins sliding in third case we got height as 0.5 m and k=37.5 ...but in the second question y=2m and at that point k is just static friction not limiting so why will we equate it to umg? even if we do we get k as (0.5)2g=10 N ..not 15 N
@@yeetmeet haan , got it , it's not maximum friction force like I said in previous comment... It's due to substitution of 53 degrees in the left most box of tan theta equation alongwith lamda and I value given in question... You get K is 15
Sir I have a small silly doubt that everyone says that string only applies tension force when string is taut(tight), but sir in catenary the string is not tight or taut(as otherwise it would be straight), the string is just hanging casually, so sir by that logic shouldn't the tension in string be 0??? Please help me sir🙏
Sir your techniques in these catenary problems is very much helpful and time saving. Sir can you please help in the 26:11 PP3 problem? I have tried hard but couldn't find the right way.
Sir, I have a doubt regarding ghe terms 'slack and 'taut'after watching this video. In most cases we are given massless strings and in that case the term 'slack' is used when the string is not fully stretched and tension is zero when we say string is taut we mean the string is tight and has some tension but in this case even when the string is not fully stretched there's some tension so what's exactly the definition of slack and taut
Hello sir I am actually learning the way(procedure) of solving these type of problems like as in the time stamp of 8:58 Is it a correct way?? The way you have solved at 8:58 is applicable to all problems of these vedios..so if I am perfect with that way of solving (**learning the procedure**) ....Will it be the right way of benefit from thse vedios??🙏 please help me 🙏🙏 Thankyou.
Sir kindly do problem number 18 from aits (fiitjee) 2019 part test 1, paper2... In its solution one line is written T-Tb=(lambda)gy, how does it come?? It has used some sort of work enegry by shifting a dl portion from bottom to topmost point please explain...
Amazing explanation sir 🤘🏼🤘🏼 But I think I am the only one who didn't know that these questions can be done using equation too🤣🤣 I did with almost same methods as you when these questions came in my test but obv not with such amazing clearity of concept ...
Hello sir i have following your channel since last 2 months and had been loving the pathfinder series.I am currently in class 11 and after looking few pathfinder questions i decided to try to solve the book my self but lately i am struggling to approach the questions i have been solving my coaching material and cengage but i am not able to solver pathfinder.Is it ok to continue with book and refer to the solutions after giving it a fair try?
@@PHYSICSSIRJEE sir I am facing the same problem while solving pathfinder, sir as you have shown in many solutions that some questions require some advanced concepts, example the virtual work concept, so where can we study those concepts from before solving pathfinder?
Sir i have a small doubt from nlm from a long time pls clarify- when a pulley(with mass) is pressed against a massless string then why do we not consider normal force between the two. We only write tension in the fbd of pulley. (For ex que 6 mcq pathfinder)
We actually include the semicircular part of the string in the fbd of the pulley thags why the force on the pulley is only the two tensions. This does not change the actual force on the pulley because the net force on the semicircular part of the string is anyway zero (as it is massless)
Sir did we have to assume that the process is reversible or piston is moved slowly so that the process is adiabatic in chp thermal physics challenge ur understanding question 5
@@PHYSICSSIRJEESir I have a small silly doubt that everyone says that string only applies tension force when string is taut(tight), but sir in catenary the string is not tight or taut(as otherwise it would be straight), the string is just hanging casually, so sir by that logic shouldn't the tension in string be 0??? Please help me sir🙏
@@PHYSICSSIRJEESir I have a small silly doubt that everyone says that string only applies tension force when string is taut(tight), but sir in catenary the string is not tight or taut(as otherwise it would be straight), the string is just hanging casually, so sir by that logic shouldn't the tension in string be 0??? Please help me sir🙏
homework answers : 1) 37 degrees ...chaand pe he apun 😎 2) (hookes law) i can't figure it out. if somebody got it , please explain. according to me both should be equal (although my intuition does say it will be longer in second case) but mathematically i am gettin both equal=lambda*l*g
Wow sir!!! I attempted these type of questions earlier in my test series but I would often tend to forget that big equation and mess up. Your methods are next level!!👍👌
Sir aap kitne blessings loge aur..kuch to bachake rakho. Takhi adv ke baad bhi mein apko mere taraf se blessings de Saku.. had kardi sir aapne..itna awsm method upload karke...just a joke...boom 💥
Sir i had seen the video but couldn't get why it was adiabatic as in question it is not mentioned that piston is moved slowly sothat process could be revesible
Please post your comment there below that video 🙂along with the time in the video at which you have a doubt . It will be convenient and beneficial for everyone. Appreciate your patience🙏
Sir what would you suggest to a simple student who is struggling with advanced problems. This problem is very hard for me. Though with efforts I am able to understand it. 😔
@@PHYSICSSIRJEE ....sir do you know one surprise....one student is a big fan of me .......I have introduced your vedios .....Sachin sir vedios ....asish arora sir vedios.......haa he became a big fan of four (janardhan sir ...asish sir and Sachin sir and me ).....yesterday he have a status of ur pics .......BUT I AM MOST HAPPY SIR JI ....WHAT A BEAUTIFUL SUBJECT PHYSICS IS
14:43 shouldn't it be 17/15
Yes , a typo on my part 😋. Apologies , also the numerical Calculation gives 1m as the answer 👍.
@@PHYSICSSIRJEE no problem sir🙏😊
Answers never matter which matters for us is the way which is provided in utmost clarity and in depth . Thank you sir and keep making these videos for us.
@@PHYSICSSIRJEE Sir I have a small silly doubt that everyone says that string only applies tension force when string is taut(tight), but sir in catenary the string is not tight or taut(as otherwise it would be straight), the string is just hanging casually, so sir by that logic shouldn't the tension in string be 0??? Please help me sir🙏
Solving catenary without catenary. OP
your presentation idea with concept makes these content look new to us.
At 20:50 R=2L/3 where L=12
So R = 8m
Am I right sir ??
20:41 i think as l is given 12 m so putting those values there we should get R= 8.
yes
Amazing sir.🙂. I will try to watch all videos of yours till jee adv. 2023 ✨
GAWD
Already did all of the problems months back , But must say your technique in some of the problems was more elegant . Thanks sir!
Vishal Kumar what🙀you solved all problems of pathfinder?
@@thayanithirk1784 Yeah mostly especially the mechanics ones
Vishal Kumar are you preparing for iitjee?
@@vonneumann3592 how did you find the height in the practice problem 1? Can you just give any sort of hint?
@@vonneumann3592 How do you approach advanced level problems. Any tip for an average student who is able to solve HCV only
After this video catenary problem of GMP is a cakewalk 🧡
Best video on Catenary I have ever seen🙌🙌🙌🙌🙌
achcha
Shri sir✨🙂
*DOUBT* 12:25 sir i got the angle as 53 degrees but i can't get the value of k...I tried a lot of manipulations but k is always getting canceled out...please help me out on how to find k
12:25 right most diagram, k is static friction maximum.... So it's equal to mu mg
@@PHYSICSSIRJEE but sir that is for the third part of the question na? when block begins sliding in third case we got height as 0.5 m and k=37.5 ...but in the second question y=2m and at that point k is just static friction not limiting so why will we equate it to umg? even if we do we get k as (0.5)2g=10 N ..not 15 N
@@yeetmeet let me check again, very old video, so may be I missed something in my previous explanation 🙂
@@yeetmeet haan , got it , it's not maximum friction force like I said in previous comment... It's due to substitution of 53 degrees in the left most box of tan theta equation alongwith lamda and I value given in question... You get K is 15
I can understand the efforts put into making this masterpiece video
Sir I have a small silly doubt that everyone says that string only applies tension force when string is taut(tight), but sir in catenary the string is not tight or taut(as otherwise it would be straight), the string is just hanging casually, so sir by that logic shouldn't the tension in string be 0??? Please help me sir🙏
Sir your techniques in these catenary problems is very much helpful and time saving. Sir can you please help in the 26:11 PP3 problem? I have tried hard but couldn't find the right way.
6:38 even while b is near wall torque of mg forms a catenary still
Near wall is different from on wall.
@@PHYSICSSIRJEE sir is catenary relevant for jee advance or can i skip it?
@@pranjalbivare7667 all problems chosen in this video are solved using simple nlm methods. So , very relevant
sir really enjoyed a lot and yaa i was able to derive the catenary equation
sir the 3 ans should be 1m but no problem
20:54 after putting l=12m we get R=8m??
Sir, I have a doubt regarding ghe terms 'slack and 'taut'after watching this video. In most cases we are given massless strings and in that case the term 'slack' is used when the string is not fully stretched and tension is zero when we say string is taut we mean the string is tight and has some tension but in this case even when the string is not fully stretched there's some tension so what's exactly the definition of slack and taut
Taut refers to the string being completely stretched, to the full extent. Slack is every other situation
Hello sir
I am actually learning the way(procedure) of solving these type of problems like as in the time stamp of 8:58
Is it a correct way?? The way you have solved at 8:58 is applicable to all problems of these vedios..so if I am perfect with that way of solving (**learning the procedure**) ....Will it be the right way of benefit from thse vedios??🙏 please help me 🙏🙏
Thankyou.
Thanks sir for giving us such type of content.....🙏
Sir kindly do problem number 18 from aits (fiitjee) 2019 part test 1, paper2... In its solution one line is written T-Tb=(lambda)gy, how does it come?? It has used some sort of work enegry by shifting a dl portion from bottom to topmost point please explain...
Thank you sir for such a nice explaination 🙌🙌
Sir in quetion 3 I tried it and but stuck on integration of sec( theta ) dl I don't know the relation between theta and dl . What to do
Thank you very much sir keep doing this wonderful work for society thank you very much sir again..
can anyone help me to find theta knot at 11:51 ?? equations are getting very odd looking
wonderful explanation .......
Sir at @26:12 dono case me same aaega kya??
Sir 25:12 ans is 37° ?
Same Mera bhi
best way of explaining
Amazing explanation sir 🤘🏼🤘🏼
But I think I am the only one who didn't know that these questions can be done using equation too🤣🤣 I did with almost same methods as you when these questions came in my test but obv not with such amazing clearity of concept ...
Hello sir i have following your channel since last 2 months and had been loving the pathfinder series.I am currently in class 11 and after looking few pathfinder questions i decided to try to solve the book my self but lately i am struggling to approach the questions i have been solving my coaching material and cengage but i am not able to solver pathfinder.Is it ok to continue with book and refer to the solutions after giving it a fair try?
PATHFINDER problems require more number of attempts for a usual student. Don't give up after one attempt. You will learn more from failures 👍🙂
@@PHYSICSSIRJEE sir I am facing the same problem while solving pathfinder, sir as you have shown in many solutions that some questions require some advanced concepts, example the virtual work concept, so where can we study those concepts from before solving pathfinder?
Thank you so much sir.. 💙💕
sun vaste chikati pothundi..
janardhan sir vaste doubts pothayi.. 😁💕
Sir i have a small doubt from nlm from a long time pls clarify- when a pulley(with mass) is pressed against a massless string then why do we not consider normal force between the two. We only write tension in the fbd of pulley. (For ex que 6 mcq pathfinder)
We actually include the semicircular part of the string in the fbd of the pulley thags why the force on the pulley is only the two tensions. This does not change the actual force on the pulley because the net force on the semicircular part of the string is anyway zero (as it is massless)
Sir can you explain check your understanding problems in kinematics
Answer to practice problem 3 should be case 1 when elastic string is held by a single nail.
Sir can you tell the centre of mass of a catenary like a rope btw 2 nails. I m not able to get it tried many times.
You cannot integrate certain functions , just like, how you cannot integrate to find the perimeter of the ellipse
@@PHYSICSSIRJEEso sir basically you are saying its not possible to find com of this catenary.
really helpful video, as usual.
sir Tsin(theta) is acting in the downward direction how can it balance downward force.... in the first question
Time stamp ?
@@PHYSICSSIRJEE 4:54
20:50 R comes as 8m ?
Best video on Catenary ❤❤❤
Sir did we have to assume that the process is reversible or piston is moved slowly so that the process is adiabatic in chp thermal physics challenge ur understanding question 5
Already done the video . Please check in playlists , either "thermodynamics" or "PATHFINDER Solutions"
Amazing problem set!! Sir when you are free can you please mark imp questions from pathfinder for her adv? Thanks for all that u do sir!
Thank you sirji😊♥️
Just great job
one of the best PHYSICS SIR JEE videos .Truly best explaination
Thank you. Please kindly share it with your relevant telegram and whatsapp groups if possible 🙏🙂
@@PHYSICSSIRJEESir I have a small silly doubt that everyone says that string only applies tension force when string is taut(tight), but sir in catenary the string is not tight or taut(as otherwise it would be straight), the string is just hanging casually, so sir by that logic shouldn't the tension in string be 0??? Please help me sir🙏
sir in the last problem u solved wont the wont tension act on the bead
Time stamp of your doubt in the video???
@@PHYSICSSIRJEESir I have a small silly doubt that everyone says that string only applies tension force when string is taut(tight), but sir in catenary the string is not tight or taut(as otherwise it would be straight), the string is just hanging casually, so sir by that logic shouldn't the tension in string be 0??? Please help me sir🙏
Sir what's the app you use for your thumbnail?
Sir please do theory lectures of inpho 2021
Thank you very much sir
homework answers :
1) 37 degrees ...chaand pe he apun 😎
2) (hookes law) i can't figure it out. if somebody got it , please explain. according to me both should be equal (although my intuition does say it will be longer in second case) but mathematically i am gettin both equal=lambda*l*g
Please suggest me a TH-cam channel for chemistry for JEE advanced
sir more videos on fluid mechanics sir plz
Sure👍🙂
Sir can you do coriolis force next?
Already done. It was my 💯 th video. Please search in RESOLVED series playlist
PHYSICS SIR JEE - JANARDHAN - IIT JEE and Olympiad thank you sir🙏🙏🙏🙏
At 21:10 should R be 8m?
Yeah , I think wrong substitution of L 👍
@@PHYSICSSIRJEE Thank you for confirming
This is just an amazing explanation for such an important topic
Thank you sir
Op sir loved this ❤
sir 28:00 was that man you and teaching whom?
Yes , it was a guest lecture to my 6 year old son's class on "Gandhi Jayanti" last year🙂
@@PHYSICSSIRJEE means you were teaching patriotism and philosophy rather than physics 😁😁
Sir it would be gr8 if u come to unacademy plus....
Sir woudl you please solve krotov mechanics questions
Solutions are available in detail at the back of the same book
Wow sir!!!
I attempted these type of questions earlier in my test series but I would often tend to forget that big equation and mess up.
Your methods are next level!!👍👌
Which test series
Which test series brother pls reply
@@abhishekchauhan1193 AITS FIITJEE
completely enjoyed...thank you sir!!!!
Sir where do you teach..?
Please kindly check the "about me" description in the channel 🙏
Where can I get pathfinder book?
Google , search for "pathfinder physics pdf" or even on telegram
Thank you sir
Thanks ❤️
used to do them with catenary equation thanks for this amazing analysis
🙏🙂 . It's difficult to remember the equation in an exam. In fact , I don't remember 😉
@@PHYSICSSIRJEE yess ur method is quite better sir
Can you tell me the catenary equation? and a basic idea of your method please
Great sir
Radius of curvature =8?
Where ? Time stamp?
Sir please take krotov q
1.38
Sir aap kitne blessings loge aur..kuch to bachake rakho. Takhi adv ke baad bhi mein apko mere taraf se blessings de Saku.. had kardi sir aapne..itna awsm method upload karke...just a joke...boom 💥
amazing sir
Sir aap offline mein padhate ho or online sir?
Offline , you can read about me here 👇
www.physicssirjee.in/About.html
Sir i had seen the video but couldn't get why it was adiabatic as in question it is not mentioned that piston is moved slowly sothat process could be revesible
Please post your comment there below that video 🙂along with the time in the video at which you have a doubt . It will be convenient and beneficial for everyone. Appreciate your patience🙏
Sir how is K=15 pls tell
Time stamp of your doubt please? 🙂 On old videos, time stamp is a must and make it easy to navigate
12:03 sir🙏
thank you sir
do you teach in unacademy plus sir?
No , not yet
@@PHYSICSSIRJEE sir will u teach in future sir ?
I will give it a try , only , if it has to be done for serious students . Right now , I don't like the current format , where it's open to all
@@PHYSICSSIRJEE ok sir
@@PHYSICSSIRJEE sir which book would you recommend for extra concepts for jee advanced and Nsep inpho
47th q will be 1.0 m
Time stamp?
Please check the pinned comment if you are referring to the same typo
catenary is amazing
#jee advance 2023
Tnx sir
Sir what would you suggest to a simple student who is struggling with advanced problems.
This problem is very hard for me.
Though with efforts I am able to understand it. 😔
I already answered your query under other video. All the best,👍🙂
❤❤❤
♥️
S TR V V V GOOD QUES
Janardhan sirrrr ......are u human???????
Answer to the Question is "relative"😋
@@PHYSICSSIRJEE ....sir do you know one surprise....one student is a big fan of me .......I have introduced your vedios .....Sachin sir vedios ....asish arora sir vedios.......haa he became a big fan of four (janardhan sir ...asish sir and Sachin sir and me ).....yesterday he have a status of ur pics .......BUT I AM MOST HAPPY SIR JI ....WHAT A BEAUTIFUL SUBJECT PHYSICS IS
😔
Thank you very much sir
thank you sir