“I am not going to motivate you or recite Kabir ke dohe as I am not that talented “ you nailed it man ... Ultra level of sarcasm 😎 Straight ,to the point, pure quality academics Proud of you Janardhan 👍👍👍
Thank you so much for this sir, I m Nitin sir's student, currently studying in class 10, I have already covered basic ncert physics, this is a god source for me to boost my knowledge before Nitin sir start the advanced classes... You rockkkkk
31:30 ans should be 192N sir as g is also applied on the rest of the mass we have to write T- (M2 + rod mass/2)g =( M2 + rod mass/2 ) a so tension comes out to be 192N... Loved the video thanks
Yeah, I like how both of them (Considering g and not considering g) give the same answer. Also, I am very curious about how (if we went by the original solution) they defined the UP direction without gravity 😆.
Yes bhaiya, that's a very good idea, may be Sir could not help us but other students who are seeing sir's lectures regularly can discuss doubts there and most difficult one will be devoted to Sir , by the way telegram is better.
In the question 24 where you mentioned it incorrect.. Answer will match by taking gravity as well, as we have to consider weight of the remaining bottom part while calculating tension then answer will match 29:58
Could someone please explain to me what I did wrong and why I was wrong at 33:57? I only applied the constraint to the left rod, assuming the movable roller to move with constant velocity U towards the right and the pivot at top to move with velocity U upwards and I got the relation, V= U cot theta unlike sir who got V=(U cot theta)/2. I understand that this has something to do with taking the x component of length of rod as x/2 (unlike the X given in the original question) for taking only the left rod in the constraint. But I still don't understand why it went wrong.
1:15:52 sir same pathfinder nlm question i dont know that it is in pathfinder or not but in old version published by cengage 'advanced problems in school physics ' which i have it is there but pathfinder is pure copy of that only
sir could you please check the solution of question at 1:08:00 . if both block moving together corresponding to 12N force common acce should be 12/9 you wrote 3 . i am getting 15 as final ans. plz check.
Sir In ques 24 according to me if we consider gravity then we get net force equals32 Newton upwards so I thing that when we add gravity in free body diagram of lower part we will get tension 32 +160 .=192 Newton.
Sir at 36:52 Where you used virtual work method .... We can also use the fact simply that velocity of both blocks along the thread will be equal..... In this way...it becomes even more shorter... Btw ... Video was amazing 👍👍👍
In practice problem q26 8 Jan If I were to make an educative guess first by basic dimensional analysis on denominator I would’ve eliminated option A and D. Now in option B and C if I take L common in B I get (mw2/k-mw2) which is greater than 1 and in C I get (mw2/k+mw2)which is less than 1 but then we know elongation will be greater than L so coeff of L must be greater than one and I would’ve chosen option B.Sir please verify my approach if you get time.Thanks again sir for continuing this series😃😃
@@PHYSICSSIRJEE As per my solution F cos(a) if cancelled by friction block will not move. And if not completely overcome by friction it will accelerate horizontally and it has said constant velocity.
@@PHYSICSSIRJEE that's amazing sir . Sir I'm understanding the theory but I'm not able to do problems,I got a less experienced teacher in 11th and it has been weak and my 12th is fine . Can I just say me a plan , I want to crack jee mains February attempt so that I can get ample time for advance as I lack in practicing, plz sir it's a request. I will hard work plz🙏🙏🙏🙏
@@chemsonbro7325 plan is to first solve previous Papers and attempt a test series in mains like Allen. Be thorough with NCERT exercises and exemplar problems
@@PHYSICSSIRJEE I will put that into work sir , I am solving pyqs .and thanks for speed reply , even I'm following nitin sir on plus , ur both combination is just like Newton and Einstein combination
janardhan sir the new edition of ncert does not contain transistors in semi conductors and communication system chapter itself is not there sir do you recommend us to study those topics as in my coaching they have assigned 1 week of revison plan just for teaching those topics
Sir when I solved 2020 September and january papers I am constantly getting marks in the range of 230:240,I am facing problems in transistor ques(even after I watched your video of jee mains extra topics) could you suggest how to practice more numericals on transistor? Also:are these marks good for a decent percentile? ALSO SIR THANK YOU FOR YOUR EFFORTS🙏🙏🙏
I've gotta problem with the usage of the word average Wen sirs says he is an AVERAGE he means to say that he is an AVEnger enRAGEd Sir jee you come out here and laks of aspirants you do encourage You guide us digitally and aid us with pyqs with full syllabus coverage Your videos offers to us in the exams more leverage and advantage The word average to sir jee is an umbrage To here you use the the word average did to me an emotional damage We believe that your originals are out for rampage Guruji you no average but a being more than a physics savage
37:28 20.(A)25m/s 21.(D)6.25m/s^2
53:22 (C)
58:43 (C)
1:15:40 (A)(C)(D)
1:30:10 By dimensions we can get to B or D
1:30:30 (B)(D)
Agreed
Especially ACD⚡⚡🔥
Beautiful Q
True 🙂
2021 ADV AIR 14 ORZ
@c,cAndc with khush kakliya No
@c,cAndc with khush kakliya No
Thanks sir for all these valuable lessons , keep it up 👍👍👍 these lessons will give a great edge to the students who will be completing it 👏👏
Thank you sir 😊👍
“I am not going to motivate you or recite Kabir ke dohe as I am not that talented “ you nailed it man ...
Ultra level of sarcasm 😎
Straight ,to the point, pure quality academics
Proud of you Janardhan 👍👍👍
Great initiative..... heavily helpful and of most importance now, lots of hardwork and selfless work, thank u very much.
sir pls bring solution to pathfinder emi questions given
You are really working hard for making such a good quality content
i am very grateful. your videos are really helping me sir :)
1:42 🖤
Sir thank you so much for continuing this series, saves alot of our time and keeps us from getting anxious about how to revise
Beautiful explanation. Quite fun as well
thanks sir for this revision series ....
Thank you so much for this sir, I m Nitin sir's student, currently studying in class 10, I have already covered basic ncert physics, this is a god source for me to boost my knowledge before Nitin sir start the advanced classes... You rockkkkk
31:30 ans should be 192N sir as g is also applied on the rest of the mass we have to write T- (M2 + rod mass/2)g =( M2 + rod mass/2 ) a so tension comes out to be 192N... Loved the video thanks
Yes ,you are right 👍, I was concerned about my answer at that time itself 😁
Yeah, I like how both of them (Considering g and not considering g) give the same answer.
Also, I am very curious about how (if we went by the original solution) they defined the UP direction without gravity 😆.
Plzz make a video for wpe and rotation too
Sir I Think You SHOULD MAKE A TELEGRAM OR WHATSAPP GROUP OF OLYMPIAD ASPIRANTS
Yes bhaiya, that's a very good idea, may be Sir could not help us but other students who are seeing sir's lectures regularly can discuss doubts there and most difficult one will be devoted to Sir , by the way telegram is better.
Telegram group for future physicists!!
Thanks a lot Sir
AMAZING channel photo sirjee
Trying different things before finalising one👍🙂
28:21 sir if tension would be same if g = 10 is taken as T - weight of lower part = mass of lower part * acc
Average guy at its best.
WE WANT ONLY AVERAGE GUY
BECAUSE WE LOVE IT
We can realise how much time it take to make all these slides. Thankyou sir
🙏😊
Superb video sir
46:30 Calculation can become bit easier by putting value
of sin and cos at the end.
33:28 sir how would i find x component of asked in these question?
If*
Sir i am doing this question by applying rod constraint on both rod by this i got Vx andVy
Sir topic 03 ki video le aaiye please jaldi....
You are simply awesome
1:38 Cut to the chase 😄👌
awesome series sir 👍👍
Iam telling my students also to go through this 👍
In the question 24 where you mentioned it incorrect..
Answer will match by taking gravity as well, as we have to consider weight of the remaining bottom part while calculating tension then answer will match 29:58
Could someone please explain to me what I did wrong and why I was wrong at 33:57? I only applied the constraint to the left rod, assuming the movable roller to move with constant velocity U towards the right and the pivot at top to move with velocity U upwards and I got the relation, V= U cot theta unlike sir who got V=(U cot theta)/2. I understand that this has something to do with taking the x component of length of rod as x/2 (unlike the X given in the original question) for taking only the left rod in the constraint. But I still don't understand why it went wrong.
1:30:32 Only (D). acc.=2g/pi
thank you sir
Thank u so much sir for boosting our concepts
Thanks sir for your valuable help sir 🙏
Thank u very much sir ..❤🤩🤩🙏🙏🙏🙏🙏🙏...
1:15:52 sir same pathfinder nlm question i dont know that it is in pathfinder or not but in old version published by cengage 'advanced problems in school physics ' which i have it is there but pathfinder is pure copy of that only
True 👍 , checked it just now . It's the same. Someone modified it for AITS
Sir plz take more and more problem...
...💓💓💓💓💓♥️♥️♥️ ...
All things fully described...
Thanku sir...
Helping 2021 jee aspirants
Thanks sir👍👍
Thank you very much sir...excited👍👍👍👍
1:16:00 Ans A,C,D?
Please continue this series sir
sir please cover other chapters as well for mains 2022
Practise problem -2. (--37:41--) Q1- Ans A(25m/s) Q2 - Ans B (62.5m/s^2)
10:42 sir if we apply limit , we get same ans in options b,d
But from previous question we knew it was not logarithmic. That's why limit won't save you. Same point was told too
@@PHYSICSSIRJEE im talking about that previous sum only sir,
@@praneethbalaji4444 hmm, yeah 👍😁. So , in this problem , limit idea will not work
@@PHYSICSSIRJEE ok sir tq, i found your videos helpful and shared your videos in my friends circle☺☺
@@praneethbalaji4444 thank you for the kind gesture 🙂
Sir your lectures are very useful for me for jee mains 2023 ......in 35 days
sir could you please check the solution of question at 1:08:00 . if both block moving together corresponding to 12N force common acce should be 12/9 you wrote 3 . i am getting 15 as final ans. plz check.
absolutely amazing sir!!!
Sir your approach was speed but need practice thank you sir
1:01:07 sir the block will do shm under friction force i think sir same question on time period is in krotov
Yes , a part of SHM in one direction 👍
Thank you very much sir🥳🥳🥳🥳
I request you do rotational motion video similar to this kindly do if yoh get time
Super ❤️❤️🙏🔥🔥🔥🔥🙏🙏
this was amazing
Sir In ques 24 according to me if we consider gravity then we get net force equals32 Newton upwards so I thing that when we add gravity in free body diagram of lower part we will get tension 32 +160 .=192 Newton.
30:20
🥰your lectures are just 🥰🥰🥰🥰😍😍😍😍😍😍😍
Thank you sir ❤️
Sir at 36:52 Where you used virtual work method .... We can also use the fact simply that velocity of both blocks along the thread will be equal..... In this way...it becomes even more shorter...
Btw ... Video was amazing 👍👍👍
In practice problem q26 8 Jan If I were to make an educative guess first by basic dimensional analysis on denominator I would’ve eliminated option A and D. Now in option B and C if I take L common in B I get (mw2/k-mw2) which is greater than 1 and in C I get (mw2/k+mw2)which is less than 1 but then we know elongation will be greater than L so coeff of L must be greater than one and I would’ve chosen option B.Sir please verify my approach if you get time.Thanks again sir for continuing this series😃😃
Also sir could you take up modern physics ques as it is frequently asked in mains
Start at 3:38
sir please try to upload videos as fast as possible on remaining topics "Mainly Second Year's"
Sir please go through heat and thermodynamics its best to go through that topic and it has lot of weightage
Your Icon Looks Nice
Sir,Q 54 solution is wrong?
54:31 Answer is (D). Please confirm.
No , please try again
@@PHYSICSSIRJEE As per my solution F cos(a) if cancelled by friction block will not move. And if not completely overcome by friction it will accelerate horizontally and it has said constant velocity.
@@PHYSICSSIRJEE Sir can you please clarify my explanation
@@swatiprusty5256 friction will not act opposite Fcos alpha only , Who do you think balances mg sin theta?
@@PHYSICSSIRJEE Fsin(alpha)
at 58.36 , ans c ?, AND 3D inclined pro ans c?
Sir in the first question force is vxi-vyj i guess
Because vxvy-vxvy=0
The old dp was good sir , by the way it’s awesome.
The sarcasm was op and why alpha is beginning and omega is ending 🧐
1) old dp was hand drawn by me... So trying out software drawn ones
2) alpha and Omega are first and last of Greek alphabets
@@PHYSICSSIRJEE that's amazing sir .
Sir I'm understanding the theory but I'm not able to do problems,I got a less experienced teacher in 11th and it has been weak and my 12th is fine . Can I just say me a plan , I want to crack jee mains February attempt so that I can get ample time for advance as I lack in practicing, plz sir it's a request. I will hard work plz🙏🙏🙏🙏
@@chemsonbro7325 plan is to first solve previous Papers and attempt a test series in mains like Allen. Be thorough with NCERT exercises and exemplar problems
@@PHYSICSSIRJEE I will put that into work sir , I am solving pyqs .and thanks for speed reply , even I'm following nitin sir on plus , ur both combination is just like Newton and Einstein combination
Namaste Sir.
Answer to book stacks question is a),c) and d). Please confirm sir.
Perfect 👍👌
Sir why not at 12:35 we should integrate further because ltv-0 give same ans to a and d I think sir pls clear🙏
Yes , praneeth Balaji commented the same below. Here , short cut won't work 👍
54:01 D is it correct sir
No ,I don't remember between b and c but critical value is 45 degrees
@@PHYSICSSIRJEE ok sir
janardhan sir the new edition of ncert does not contain transistors in semi conductors and communication system chapter itself is not there sir do you recommend us to study those topics as in my coaching they have assigned 1 week of revison plan just for teaching those topics
It's very much part of mains syllabus brochure
@@PHYSICSSIRJEE thank us sir for replying
@@PHYSICSSIRJEE sir but the ncert new edition does not contain communication systems and transistors
@@ponnapu it doesn't matter to JEE main people and their data base of Questions
@@PHYSICSSIRJEE ok sir
sir please tell your new channel name sir of telugu version
Not there yet
Answer to Q 24. is still 192 N, including g !!
Time stamp?
@@PHYSICSSIRJEE 28 min
@@SoI_JEE_NEET_Physics_Math_IITB you mean 27:41 . Yes I forgot weight in last step. Thanks for bringing it to my notice as I said 2 min later
practice problem 2 ans-- A) and B)
Time stamp ? please 🙂
37:41
Sir when I solved 2020 September and january papers I am constantly getting marks in the range of 230:240,I am facing problems in transistor ques(even after I watched your video of jee mains extra topics) could you suggest how to practice more numericals on transistor?
Also:are these marks good for a decent percentile?
ALSO SIR THANK YOU FOR YOUR EFFORTS🙏🙏🙏
Please aim for 270+ if you are in general category 👍. All the best 🙂
Also , firstly finish transistors from NCERT back exercises and NCERT exemplar , even subjective
Kabir ke dohe 😂😂 savage 😂
35:00 43:39
I've gotta problem with the usage of the word average
Wen sirs says he is an AVERAGE he means to say that he is an AVEnger enRAGEd
Sir jee you come out here and laks of aspirants you do encourage
You guide us digitally and aid us with pyqs with full syllabus coverage
Your videos offers to us in the exams more leverage and advantage
The word average to sir jee is an umbrage
To here you use the the word average did to me an emotional damage
We believe that your originals are out for rampage
Guruji you no average but a being more than a physics savage
🤗🤗🙂
Beautiful words 🥰🙏. Humbled 😀
Janardhansir_op
Sir please can you post video quickly
Quickly is not possible. Each video takes atleast 4 days to make with my regular offline job
I want to be this much average in physics