Good show/ program... Thought.... Often a person makes a comment... And you answer ... But for us at home. ..We could not hear the question. . So maybe you could next time.. Repeat the question to clarify and at the same time.. Reveling the question, clear to the viewing audiences
Another great video. But you should zoom out so we can see G and Pete set up the test. For example when G use the power probe to check for VD on power side. Just a thought...
Hey thanks for watching and your comment...this video is over 5 years old...we have gotten better...we appreciate your comment and for watching. If you have not already subscribed to our tstseminars TH-cam channel please do so. also check out mour tstseminars.org website for newer videos some free and some for pay...thanks
Hello. I keep asking myself this question because I don't know the internal of an injector, a coil or a solenoid: How a shorted coil, injector or solenoid that finds its ground inside of itself can cook the driver? I am thinking that the load would draw more current because of the shorted path and blow the fuse, but not sure how the driver can take a hit from that. Your answer would be very appreciated. By the way, you two together, always make some very interesting and excellent videos.
The answer is smiple...if the injector winding take a shorter path rather then going all the way through the winding the RESISTANCE will be LOW....Low Resistance = Higher amps. If the amps on most computer circuits go past 1200mA / 1.2 amps it will burn the driver. Thanks for your question and watching.... If you have not already subscribed to our tstseminars TH-cam channel please do so. Thanks for your comment.
At the 18:56 min. mark, loads in series. 2 light bulbs in series. How does the system voltage, 12.5 volts detect and react to a second resistance beyond the initial load (first light bulb) so that only half of system voltage is consumed in the first light bulb
The above question is merely a comment. My real confusion is a single resistance load circuit ( one light bulb )why does all system voltage get consumed to zero voltage on the ground side. The voltage is not released to he atmosphere like water released after twirling a sprinkler head but is piped back to the voltage source . If all voltage is consumed by the load. Then there should be no electron movement in the ground side . There is no current because there is no voltage to push the electrons. So if the ground wire doesn't promote electron movement , why does there need to be a return line back to the battery? There is nothing to return
I was installing LEDs into my 99 Expedition and shorted out my interior lights and the ones on my running board. Radio and cluster lights still work but now my engine wont start. Help me rule out the issues please.
A short decreases resistance by removing resistance, that is short cutting the complete circuit. Example...think of electricity as a 360 circle...the 12 volt battery negative post is the starting point...electrons flow from negative to positive...the positive post is connected to wire...in the middle is a load (bulb/motor/etc) after the load is more wire that returns to the negative post of the battery making a complete circle. Now a short can cut the circle in half that will decrease resistance leaving the 180 of the circle behind. Of course the short can be in other area of the circle as well. Hope this helps. If you have not already subscribed to our tstseminars TH-cam channel please do so. Thank you G
Take a 16 gauge wire and with welding gloves on touch it across a positive and negative battery posts (of a charged batt) Then take a test light with about the same size wire and do the test again. Ask yourself why the test light wire didn't burn up. Before you start check the wire and then the test light with an ohm meter, You will see the difference.
John that a hard question...but when the owner feel enough pain by loosing customers he will understand. If you have not already Subscribed to our tstseminars TH-cam channel please do so. Interested in more training? Go to www.tstseminars.org and www.attstraining.com
This is a good video so don't think I am bashing it because there is a wealth of good information and techniques contained succinctly within this small video. I have two qualms myself that are worth mentioning, but I don't think they are thumbs down worthy. 1. The video is grainy and I cannot really make out much on the block diagrams. 2. As an electrician, I am totally bewildered by the statement that once voltage gets to the device, you no longer have to worry about it. It was combined with the example of rolling the stone uphill and letting it drop downhill. That is not how current works and the whole circuit is important. There is no current without a path back to source and the current passing through a lightbulb is not simply factored by the resistance in the bulb, but the total circuit resistance, i.e. the resistance of all connections on positive and negative side plus the resistance of the wires as well. Arguably the path to ground is the most important. (Electrons flow from negative to positive but that's not totally important to distinguish). Additionally, when you measure voltage what you are really doing is measuring the difference in potential between two parts. When a bulb is glowing, you will have the same current running through the negative side as you do the positive side--it does not get used up or lost in the bulb. This is in essence how a millivolt test works--it tests the voltage difference between negative and positive sides of a component. There is still voltage on the negative side, and the whole ground of the system is referenced to that voltage which is why you'll read 0 volts negative to ground--no difference in potential. You could actually reverse this and bind the positive to ground instead. I have a variety of other qualms with the information in this video, but I ask myself if this information is counter to developing the practicable ability to diagnose electrical issues on a car (which is the aim of the video) and the answer to that is no. The video is a resounding success and those thumb-downers are just salty.
James that is correct...thanks for watching. If you have not already Subscribed to our tstseminars TH-cam channel please do so. Interested in more training? Go to www.tstseminars.org and www.attstraining.com
I really think its a great video and cudos to you guys doing this but you really need to get your definition of Voltage right. The way its described in the beginning of the video makes it sound a lot like current. Voltage is the difference/potential difference in electrical charge. not meaning to nitpick or anything!
All comment welcome...thanks for watching...If you have not already subscribed to our tstseminars TH-cam channel please do so. Also if you are looking for more training go to www.tstseminars.org
Thanks but that is one of our old videos...check out some of our other ones...thanks for watching...If you have not already subscribed to our tstseminars TH-cam channel please do so. Interested in more training? Go to www.tstseminars.org and view full length videos for members on TechFlix for $9.99 unlimited viewing …Membership and over 85 videos for less than $200.00 a year. Also checkout www.attstraining.com for hands on training and webcast FREE videos at www.tstseminars.org/training-videos
I don'r believe so...thanks for watching....If you have not already subscribed to our tstseminars TH-cam channel please do so. Also if you are looking for more training go to www.tstseminars.org
At the 25:28 mn mark a switch nstalled on the ground side. The ground side has no voltage thus no current and no electron flow, supposedly. . There has to be potential difference on the ground side to make the ground switch to activate electronic movement on the positive side . What am I missing?
There IS a small voltage drop across the ground wire, from the load back to the battery. The actual value will depend on the current flowing through the loop and the resistance of the ground wire (in is not zero Ohms). Ohms law still applies. You are absolutely right, if there is no voltage drop, there will be nothing to promote current :)
We have some of that but it is for pay...sorry we cannot give everything that people ask for for free. We are a not for profit group that has bills just like you. Thanks for watching...If you have not already subscribed to our tstseminars TH-cam channel please do so. Interested in more training? Go to www.tstseminars.org and view full length videos for members on TechFlix for $9.99 unlimited viewing and www.attstraining.com for hands on training and webcast FREE Unlocking The Potential Of Your Scan Tool with EScan and Generic Part 1 - AutoLand iScan3 Part 2 - Autel Part 3 - LAUNCH Part 4 - Snap-On Part 5 - OPUS IVS ES Part 6 www.tstseminars.org/blank-1 www.tstseminars.org/blank-2 www.tstseminars.org/blank-3 www.tstseminars.org/blank-4 www.tstseminars.org/blank-5 www.tstseminars.org/blank-6 www.tstseminars.org/blank-7 www.tstseminars.org/blank-8 www.tstseminars.org/blank-9
Good show/ program...
Thought....
Often a person makes a comment...
And you answer ...
But for us at home. ..We could not hear the question. .
So maybe you could next time..
Repeat the question to clarify and at the same time..
Reveling the question, clear to the viewing audiences
I love the teaching.
Another great video
The power probe 3 is a brilliant tool (built in voltmeter) to check voltage drop
Great tool I used it all the time.
Another great video. But you should zoom out so we can see G and Pete set up the test. For example when G use the power probe to check for VD on power side. Just a thought...
Hey thanks for watching and your comment...this video is over 5 years old...we have gotten better...we appreciate your comment and for watching. If you have not already subscribed to our tstseminars TH-cam channel please do so. also check out mour tstseminars.org website for newer videos some free and some for pay...thanks
Hello. I keep asking myself this question because I don't know the internal of an injector, a coil or a solenoid: How a shorted coil, injector or solenoid that finds its ground inside of itself can cook the driver? I am thinking that the load would draw more current because of the shorted path and blow the fuse, but not sure how the driver can take a hit from that. Your answer would be very appreciated. By the way, you two together, always make some very interesting and excellent videos.
The answer is smiple...if the injector winding take a shorter path rather then going all the way through the winding the RESISTANCE will be LOW....Low Resistance = Higher amps. If the amps on most computer circuits go past 1200mA / 1.2 amps it will burn the driver. Thanks for your question and watching.... If you have not already subscribed to our tstseminars TH-cam channel please do so. Thanks for your comment.
What I failed to realize was current in a shorted winding continue its path through the entire winding to ground.
great...thanks
Hi tst and motorage... id like to know where i can get wiring diagram if i need it for all different kind of car
At the 18:56 min. mark, loads in series. 2 light bulbs in series. How does the system voltage, 12.5 volts detect and react to a second resistance beyond the initial load (first light bulb) so that only half of system voltage is consumed in the first light bulb
The above question is merely a comment. My real confusion is a single resistance load circuit ( one light bulb )why does all system voltage get consumed to zero voltage on the ground side. The voltage is not released to he atmosphere like water released after twirling a sprinkler head but is piped back to the voltage source . If all voltage is consumed by the load. Then there should be no electron movement in the ground side . There is no current because there is no voltage to push the electrons. So if the ground wire doesn't promote electron movement , why does there need to be a return line back to the battery? There is nothing to return
ohms law dictates what happens in any circuit learn ohms law and you will understand , easy
I was installing LEDs into my 99 Expedition and shorted out my interior lights and the ones on my running board. Radio and cluster lights still work but now my engine wont start. Help me rule out the issues please.
Very informative! I am yet to understand how a short decreases resistance. Would you please explain to me how?
A short decreases resistance by removing resistance, that is short cutting the complete circuit. Example...think of electricity as a 360 circle...the 12 volt battery negative post is the starting point...electrons flow from negative to positive...the positive post is connected to wire...in the middle is a load (bulb/motor/etc) after the load is more wire that returns to the negative post of the battery making a complete circle. Now a short can cut the circle in half that will decrease resistance leaving the 180 of the circle behind. Of course the short can be in other area of the circle as well. Hope this helps. If you have not already subscribed to our tstseminars TH-cam channel please do so. Thank you G
It really helps. Thank you.
Take a 16 gauge wire and with welding gloves on touch it across a positive and negative battery posts (of a charged batt) Then take a test light with about the same size wire and do the test again. Ask yourself why the test light wire didn't burn up. Before you start check the wire and then the test light with an ohm meter, You will see the difference.
PJH
How would I go about convincing garage owners to use a professional diagnostician
John that a hard question...but when the owner feel enough pain by loosing customers he will understand. If you have not already Subscribed to our tstseminars TH-cam channel please do so. Interested in more training? Go to www.tstseminars.org and www.attstraining.com
ty for the hands on... thats how i learned easier...
I'd like to know why eight persons gave this a thumbs down ? They probably know nothing about automotive electrical systems !
This is a good video so don't think I am bashing it because there is a wealth of good information and techniques contained succinctly within this small video.
I have two qualms myself that are worth mentioning, but I don't think they are thumbs down worthy.
1. The video is grainy and I cannot really make out much on the block diagrams.
2. As an electrician, I am totally bewildered by the statement that once voltage gets to the device, you no longer have to worry about it. It was combined with the example of rolling the stone uphill and letting it drop downhill. That is not how current works and the whole circuit is important.
There is no current without a path back to source and the current passing through a lightbulb is not simply factored by the resistance in the bulb, but the total circuit resistance, i.e. the resistance of all connections on positive and negative side plus the resistance of the wires as well. Arguably the path to ground is the most important. (Electrons flow from negative to positive but that's not totally important to distinguish).
Additionally, when you measure voltage what you are really doing is measuring the difference in potential between two parts. When a bulb is glowing, you will have the same current running through the negative side as you do the positive side--it does not get used up or lost in the bulb. This is in essence how a millivolt test works--it tests the voltage difference between negative and positive sides of a component. There is still voltage on the negative side, and the whole ground of the system is referenced to that voltage which is why you'll read 0 volts negative to ground--no difference in potential. You could actually reverse this and bind the positive to ground instead.
I have a variety of other qualms with the information in this video, but I ask myself if this information is counter to developing the practicable ability to diagnose electrical issues on a car (which is the aim of the video) and the answer to that is no. The video is a resounding success and those thumb-downers are just salty.
👍🏽 Great!
Wow, you guys are great.
Steven THANK You... If you have not already subscribed to our tstseminars TH-cam channel please do so.
On believable talent. Raw.
I think than you... If you have not already subscribed to our tstseminars TH-cam channel please do so. Thank you for watching
Even the long trevel of wire puts resistance on circuit
James that is correct...thanks for watching. If you have not already Subscribed to our tstseminars TH-cam channel please do so. Interested in more training? Go to www.tstseminars.org and www.attstraining.com
I really think its a great video and cudos to you guys doing this but you really need to get your definition of Voltage right. The way its described in the beginning of the video makes it sound a lot like current. Voltage is the difference/potential difference in electrical charge. not meaning to nitpick or anything!
All comment welcome...thanks for watching...If you have not already subscribed to our tstseminars TH-cam channel please do so. Also if you are looking for more training go to www.tstseminars.org
Very very useful
Thanks but that is one of our old videos...check out some of our other ones...thanks for watching...If you have not already subscribed to our tstseminars TH-cam channel please do so. Interested in more training? Go to www.tstseminars.org and view full length videos for members on TechFlix for $9.99 unlimited viewing …Membership and over 85 videos for less than $200.00 a year. Also checkout www.attstraining.com for hands on training and webcast
FREE videos at www.tstseminars.org/training-videos
Do fuse's go bad from age .
I don'r believe so...thanks for watching....If you have not already subscribed to our tstseminars TH-cam channel please do so. Also if you are looking for more training go to www.tstseminars.org
At the 25:28 mn mark a switch nstalled on the ground side. The ground side has no voltage thus no current and no electron flow, supposedly. . There has to be potential difference on the ground side to make the ground switch to activate electronic movement on the positive side . What am I missing?
There IS a small voltage drop across the ground wire, from the load back to the battery. The actual value will depend on the current flowing through the loop and the resistance of the ground wire (in is not zero Ohms). Ohms law still applies. You are absolutely right, if there is no voltage drop, there will be nothing to promote current :)
Hi TST team, good day, my request for to put good vedio for basic current flow from where to go with read wiring diagram.. pls
We have some of that but it is for pay...sorry we cannot give everything that people ask for for free. We are a not for profit group that has bills just like you. Thanks for watching...If you have not already subscribed to our tstseminars TH-cam channel please do so. Interested in more training? Go to www.tstseminars.org and view full length videos for members on TechFlix for $9.99 unlimited viewing and www.attstraining.com for hands on training and webcast
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I wish I could hear you
an open does not have resistance ,,,its open no nothing is flowing ! careful there
a for effort, you need to show us where your putting leads i under stand the theory, but you lost me . with details.