What is we won't add biased and instead of that we convert the exponent of a number in its binary form and then represent it in the exponent bit of single/ double precision from right to left like 100 if we'll represnt this in exponent part then it will be 0000 0100? Will this be correct if we won't find it's biased ?
how does the number of mantissa bits are related to significant decimal digits after decimal point ? and also how are we loosing the precision even though number of bits are 23 ? do you mean precision of the 32 bit floating point is less than 32 fixed point ?
It’s a rule To calculate the exponent For single : add 127 to the numbers of bits in mantisa after removing one bit for sign For double: add 1023 in the same way Notice that number of bits in double must be 11 while single is 8
Floating point representation 11001000110100011110100000000000, a. - 0.1101000111101 x 2^9 b.- 0.1101000111101 x 2^ 8 c.- 0.1101000111101 x2^7 d.- 0.1101000111101 x 2^6 Can you figure and explain how to reduce the exponent . THANK YU VERY MUCH
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ngl you just taught me my profs whole weeks lecture, in 22 mins. Genuinely appreciate it!
Example 1 really helped me out, thank you so much
TH-cam lectures are better than college lecture
before commenting like this compare your concentration levels while listening to TH-cam videos and listening to college lecture
That is true
Very nice as usual 🎉🎉
Amazing explanation every time 🎉
so good explaination, If only clg prof taught like this !
Please do a video on multiple sequence detecting fsm in one Sequence
What is we won't add biased and instead of that we convert the exponent of a number in its binary form and then represent it in the exponent bit of single/ double precision from right to left like 100 if we'll represnt this in exponent part then it will be 0000 0100? Will this be correct if we won't find it's biased ?
how does the number of mantissa bits are related to significant decimal digits after decimal point ? and also how are we loosing the precision even though number of bits are 23 ? do you mean precision of the 32 bit floating point is less than 32 fixed point ?
Man u are great, thank god for you and godbless you
Nice explanation bruh 🎉
Very Nice Continue 👍👍👍👌👌👌
Hello man, welcome to you.
Please someone tell me why he add(+) 127 why he subtract ?
It’s a rule To calculate the exponent
For single : add 127 to the numbers of bits in mantisa after removing one bit for sign
For double: add 1023 in the same way
Notice that number of bits in double must be 11 while single is 8
11 and 8 bits .. I mean for exponent
To make it clear
Floating point representation 11001000110100011110100000000000,
a. - 0.1101000111101 x 2^9
b.- 0.1101000111101 x 2^ 8
c.- 0.1101000111101 x2^7
d.- 0.1101000111101 x 2^6
Can you figure and explain how to reduce the exponent . THANK YU VERY MUCH
Thanks!
The Scientific Notations
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