02.3 Linear and nonlinear analysis in FEA/CAE (Analysis step)

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  • เผยแพร่เมื่อ 24 ก.ค. 2024
  • In this video tutorial i tried to explain analysis step in Abaqus for geomtric linear analysis, geometric Nonlinear Analysis & combined geo and material non linear Analysis.
    I also talked a little on convergence issue in abaqus standard, which i decide to explain completely in next video tutorial (I don't want to make this video more lengthy).
    I suggest to have a look on video 02.1, 02.2 before 02.3 in playlist (Abaqus Simulia). Plz have a look I'm sure it will be much helpful for beginners in Abaqus & if you are already Abaqus user then also here you find something new (probably little confusion). On which I'll discuss more in next video tutorial.
    To know more plz check playlists.
    For related questions & discussion you can contact me on 7891401376. or mail me gkn0504@gmail.com
    Telegram Link - t.me/joinchat/OL8CZhZnuJkiTei...
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ความคิดเห็น • 17

  • @simtech0598
    @simtech0598  5 ปีที่แล้ว +6

    Here density should be 7800e-12 for steel material according to mm, ton, sec unit system. I made little mistake - instead of 7800e-12 I put 7800e-9.
    But static analysis are independent to density value, even you not need to define it. So analysis results remains same, Please don't bother about it.

    • @aukfaworld4792
      @aukfaworld4792 3 ปีที่แล้ว

      Dear sir, I also confused about this point defining the mass density, I try to model the load for N, dimension for mm, Elastic modulus by MPa or N/mm2. in this case what mass density value I should use.

    • @simtech0598
      @simtech0598  3 ปีที่แล้ว

      Dear,
      It is just unit conversion.
      If ur model unit is in meter..it easy to use MKS unit system.
      If ur model is in mm...it easy to use...mm,ton,sec unit.
      In case 2 (mm,ton,sec)
      Density become ton/mm3
      Or
      7800 Kg/m3 = 7800*e-12 ton/mm3
      Similarly stress
      1 N/m2 = 1*e6 N/mm2 or 1Mpa

    • @aukfaworld4792
      @aukfaworld4792 3 ปีที่แล้ว +1

      @@simtech0598 I really appreciate your response. It very useful information. Thank you.

  • @HayatTeleHealth
    @HayatTeleHealth 4 ปีที่แล้ว +2

    Best video, I don't know how you manage you keep our intrest in the entire video. well done sir.

    • @simtech0598
      @simtech0598  4 ปีที่แล้ว

      Just sharing knowledge dear.
      Thanks for appreciation.

  • @ib_parametres724
    @ib_parametres724 4 ปีที่แล้ว +2

    I'm just getting familiar with the software, and I must say your videos are quite elucidating. Thumbs up!

  • @le_Bizarre
    @le_Bizarre 3 ปีที่แล้ว

    Thank you for a great content. I have a question, though: in the linear simulation, I wonder how Abaqus is 'stretching' the length of the plate: is it stretching it via an additional tension force, or is it simply considering the plate as being longer and longer as time goes by, so no added stresses, just an additional length is given for it?

    • @simtech0598
      @simtech0598  3 ปีที่แล้ว +1

      Dear,
      The reason you mentioned is wrong.
      As i told i video...in linear analysis stiffness matrix not change...so for large deformation also it not update stiffness matrix (it should be updated as shape of elements change)...hence nodes are not follow load path..

  • @aukfaworld4792
    @aukfaworld4792 3 ปีที่แล้ว

    Dear Sir, Actually, I use Marc for structure analysis. have you ever use Marc Mentat. I wonder that I set the material yield criteria as Von Mises criteria, it means it will stop when I reach the criteria or not?.

    • @simtech0598
      @simtech0598  3 ปีที่แล้ว

      Dear,
      I'm unaware to word "Marc mentat"

  • @alialijamelll5016
    @alialijamelll5016 2 ปีที่แล้ว +1

    dear sir, why should we define increments for linear, static analysis and small deformation? I know that for this case we solve the equation f=k*d one time that will give the deformation because stiffness matrix will not change, so why do we define increments and why does software solve the problem by dividing it into many increments (my qustion is only for static, linear and small deformation cases).

    • @simtech0598
      @simtech0598  2 ปีที่แล้ว

      Dear,
      The general static step is based on increment method... whether stiffness changes or not (linear or nonlinear). This method converge solution in better way when convergence tolerance is higher than the specified tolerence.
      Let say for any increment ∆f = k ∆x convergence not occur due to larger difference un RHS and LHS (convergence tolerance). In next increment it consider lower step time and other subsequent values and try to converge.
      The method of direct solution (without iteration) is used in linear pertribution step in Abaqus.
      I also suggest you to learn FEA in this way... raise good question as you raised here.
      Read Abaqus documentation and practice finite element analysis book (Nitin gokhle sir).

  • @Bala92635
    @Bala92635 2 ปีที่แล้ว

    sir i wanted to know what is solution for the convergence error occurred in material non linearity problem

    • @simtech0598
      @simtech0598  2 ปีที่แล้ว

      Dear,
      Whats problem you are facing... share visuals on my WhatsApp.

  • @ravipukale6073
    @ravipukale6073 ปีที่แล้ว +1

    What if I have to do it on solid elements, which element type must be selected?

    • @simtech0598
      @simtech0598  ปีที่แล้ว

      Dear,
      Element selection depends on analysis type.
      I uploaded one video that may helpuf - th-cam.com/video/PhZhNAwUaxI/w-d-xo.html