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  • เผยแพร่เมื่อ 25 พ.ย. 2024

ความคิดเห็น • 17

  • @JanVanHunks
    @JanVanHunks 8 ปีที่แล้ว +4

    Thank you University of Texas, class is for students without TH-cam

  • @waqasmuneer7951
    @waqasmuneer7951 8 ปีที่แล้ว +1

    Excellent presentation

  • @oscarjeans4119
    @oscarjeans4119 7 ปีที่แล้ว

    This is a really good video! thank you very much :)

  • @katek5568
    @katek5568 8 ปีที่แล้ว +1

    very well presented. thank you. x10000000 likes

  • @erasmo273
    @erasmo273 8 ปีที่แล้ว +3

    i was watching alien videos how did i get here lol

    • @juliosanchez1614
      @juliosanchez1614 8 ปีที่แล้ว +1

      +erasmo hinojosa this is a education video for are materials class

    • @syedmahdi4934
      @syedmahdi4934 8 ปีที่แล้ว +3

      It's usually the other way around

  • @lorenamonteiro6411
    @lorenamonteiro6411 7 ปีที่แล้ว +1

    very helpful. thank ou

  • @2sunami
    @2sunami 7 ปีที่แล้ว

    thanks for this very informative video,,,
    I have a question though
    what if I heated the alloy to 800 and then quenched it rapidly all the way to room temperature without holding seconds in between. Then what phases will I have?

    • @melearn-utrgvley2252
      @melearn-utrgvley2252  7 ปีที่แล้ว +1

      If it's 800C it's 100% Martensite. If it's 800F, then it would be considered a reheat.

    • @2sunami
      @2sunami 7 ปีที่แล้ว

      thanks for your reply +MELearn UTRGV
      the question I am trying to solve is
      I am working with 2 steels 1045 and 1022
      I am doing two experiments for both steels
      exp 1:
      heating to 900C and then quenching in oil
      heating to 900C and then quenching in water
      exp 2:
      heating to 800C and then quenching in oil
      heating to 800C and quenching in water
      assuming cooling rate for oil is 75C/sec and
      assuming cooling rate for water is 300C/sec.
      what phases will I have for them?
      thanks

    • @melearn-utrgvley2252
      @melearn-utrgvley2252  7 ปีที่แล้ว

      If you have your continuous cooling curves for both of these steels, you can email them at melearn.utrgv@gmail.com.

  • @a7majed
    @a7majed 8 ปีที่แล้ว +1

    I have a question..
    @3:50 you said: "When you hit the Solidus line" describing the solidification process, although solidification starts when you hit the Liquidus line, it ends when you hit the Solidus line, doesn't it?

    • @melearn-utrgvley2252
      @melearn-utrgvley2252  8 ปีที่แล้ว +2

      When cooling from the molten state, solidification begins when you reach the liquidus line, continues as you cool through the two phase liquid-solid region and then finishes when you hit the solidus line. Note that these are equilibrium diagram temperatures so a practical cooling rate will not begin solidification at exactly the diagram indicated liquidus temperature (usually slightly lower) nor finish at the diagram indicated solidus temperature (again probably slightly lower). The slower you cool (that is the closer you keep the entire system to equilibrium) the closer the actual temperatures will be to the diagram values.
      If you cool really fast, some systems can achieve a super-cooled liquid state which will solidify rapidly once initiated. The King of Random has some nifty experiments you can do with super-cooled water: th-cam.com/video/sQdLttUh_b0/w-d-xo.html
      - Dr. Jones