Oxford University entrance Exam

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  • เผยแพร่เมื่อ 17 ต.ค. 2024
  • University Admission Exam Question || Algebra Problem || Entrance Aptitude Simplification Test || Tricky Interview
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ความคิดเห็น • 14

  • @rajbhatt1
    @rajbhatt1 วันที่ผ่านมา +2

    Easier method: Square root of any number ending in 5 ends in 5; Square of any number 10n+5 is 100n(n+1) +25; so we just need to factorize 44442222; 44442222= 2222*20001=1111*2*3*6667= 6666*6667; THerefore sq root of the number is 66665

    • @milan.matejka
      @milan.matejka 23 ชั่วโมงที่ผ่านมา

      I am not a mathematician, so my approach is kinda stupid.
      I looked at the end of the number as realized it can be divided first by 25. So I did, with result of 177768889. As it ended with 9, it might get divided by a square of a prime number ending with 3 or 7. I tested (hardest part of my approach) 7,13,17,23,37,43,47,53 and finally 67, which turned out to fit, leaving 39601. It was close to a square of 200 and could be a square of only a number ending in 1 or 9. So I began the test with 199, and it fitted. Result was 5*67*199

  • @НатальяТкаченко-ъ1з
    @НатальяТкаченко-ъ1з วันที่ผ่านมา +1

    Очень красивое решение. Спасибо большое

    • @superacademy247
      @superacademy247  23 ชั่วโมงที่ผ่านมา

      You're welcome 😍😍🤩🙏

  • @SrisailamNavuluri
    @SrisailamNavuluri 11 ชั่วโมงที่ผ่านมา

    Answer ends with 5
    Find the square root of 44442222 which lies between 6666 and 6667
    So answer is 66665
    Or
    44442222=22(2020101=22+3×673367
    =66×101×6667=6666×6667
    (a5)^2=a(a+)×100+25
    Square root of a(a+1)×100+25=a5

  • @mrinaldas9614
    @mrinaldas9614 21 ชั่วโมงที่ผ่านมา +1

    I found out the result by conventional method in 7minutes in10 steps.
    May be the university wants to find how strong one is in basic methods.

    • @superacademy247
      @superacademy247  20 ชั่วโมงที่ผ่านมา

      That's an excellent time, well done!You're exactly right, it's about the process, not the speed.🙏👏💕💯

  • @コレクター老人
    @コレクター老人 วันที่ผ่านมา +1

    I have no idea to solve this question, I used a method of calculation to extract the square root.

    • @superacademy247
      @superacademy247  วันที่ผ่านมา

      It requires patience to solve this type of question.

    • @michaeledwards2251
      @michaeledwards2251 วันที่ผ่านมา

      @@superacademy247
      Fortunately for the students, no real world root problems are being solved. Even if the numbers in real world problems appear convenient, caution has to be used. Hidden human error is often the dominant error with the only knowledge of the error values being they follow a gaussian curve. (Studies of Human Performance. )

  • @raghvendrasingh1289
    @raghvendrasingh1289 วันที่ผ่านมา

    Expression under square root is
    4 (10^9+10^8+10^7+10^6) + 2 (10^5+10^4+103+10^2+10) + 5
    4 × 10^6 (10^4-1)/9 + 2×10 (10^5-1)/9 +5
    { 4 ×10^10-4 ×10^6+
    2 ×10^6-20+45 } /9
    (4 × 10^10 -2× 10^6 +25)/9
    hence square root is
    (2×10^5-5)/3
    { 2 × 10 (10^4-1) +15 }/3
    6 × 10 (10^4-1)/9 +5
    6 ( 10^4+10^3+10^2+10 ) +5
    = 66665