It sounds like you got what looks like a good fit from a 3rd order polynomial. You can fit anything if you use a high enough power polynomial, but that does not mean that there is any physical meaning to it. In this case, there is no point to linearizing.
If P=ah^n, then when we take the log of both sides we get log P = nlog h + log a. Log P is he y-variable, n is the slope, log h is the x-variable, and log a is the y-intercept.
@@donerphysics thanks, but what I mean is finding the actual physical meaning of a slope through logarithms after deriving the formula. Like in this pendulum case, you found the physical meaning of the slope to be 2pi/g^0.5, so how would you be able to do that with logarithms?
What I said is how you do it. For the pendulum, T^2=4 pi^2/g xL. Take the log of both sides. Let log T be your y-variable and log L be your x-variable.
Hello, what if my data shows a sigmoid curve? And the trend lines I get from excel seemed not to fit with the data. Do I need to find the sigmoid equation manually? As well as it does not seem to be able to be linearized, what do I do then? Thanks kindly for your reply before hand!
Not all curves can be linearized. Make the graph, fit by hand, and explain why you got the curve that you got. Linearization is a nice way to show off but is not at all necessary to score high marks.
I created an exponential decay function, between initial temperature of an obect, and the time it takes for it to cool down in 3 hours, my teacher is asking me to linearize it, but do I really need to?
Your videos are excellent.
if i have a cubic graph in the function of ax^3 +bx^2 + cx + d can you linearise it?
It sounds like you got what looks like a good fit from a 3rd order polynomial. You can fit anything if you use a high enough power polynomial, but that does not mean that there is any physical meaning to it. In this case, there is no point to linearizing.
how do we determine the general equations in the examples? and what exactly are we trying to find?
Could you be more specific?
Hi Chris, could you please explain how to find the meaning of the slope that was linearized through logarithms? Like pressure vs height for example.
If P=ah^n, then when we take the log of both sides we get log P = nlog h + log a. Log P is he y-variable, n is the slope, log h is the x-variable, and log a is the y-intercept.
@@donerphysics thanks, but what I mean is finding the actual physical meaning of a slope through logarithms after deriving the formula. Like in this pendulum case, you found the physical meaning of the slope to be 2pi/g^0.5, so how would you be able to do that with logarithms?
What I said is how you do it. For the pendulum, T^2=4 pi^2/g xL. Take the log of both sides. Let log T be your y-variable and log L be your x-variable.
Great explanation. I shall be grateful to have your comment on my video with the same title.
Hello, what if my data shows a sigmoid curve? And the trend lines I get from excel seemed not to fit with the data. Do I need to find the sigmoid equation manually? As well as it does not seem to be able to be linearized, what do I do then? Thanks kindly for your reply before hand!
Not all curves can be linearized. Make the graph, fit by hand, and explain why you got the curve that you got. Linearization is a nice way to show off but is not at all necessary to score high marks.
Thanks for video
Chris, how do i linearize hyperbolic functions
If you think a shape is y=x^2, you make a plot of y against x^2. Similarly, if you think the shape is y=sinh x , try a plot of y versus sinh x.
I created an exponential decay function, between initial temperature of an obect, and the time it takes for it to cool down in 3 hours, my teacher is asking me to linearize it, but do I really need to?
You have experimental data that seems to be exponential?
@@donerphysics Yes, and I created an exponential model to model it.
It is not necessary. Linearization is a nice skill to show off when used appropriately.
How would you find the specific equation?
You would find the slope and y-intercept of the linearized graph, then y-var = slope x x-var + y intercept.
is this for externals or internals?
You no longer have a paper 3 because of covid, so it will not be on the external exam.