L1.2 Setting up the perturbative equations
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- เผยแพร่เมื่อ 19 ม.ค. 2025
- MIT 8.06 Quantum Physics III, Spring 2018
Instructor: Barton Zwiebach
View the complete course: ocw.mit.edu/8-...
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L1.2 Setting up the perturbative equations
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What a wonderful lecturer Professor Zwiebach is - I'm not sure I've come across a teacher so clear and engaging.
Gotta love this guy. Great lectures.
Sir it's my humble request to make videos on the course of relativistic quantum mechanics..... your lecture is awesome sir..just awesome .....its my request to mit.... it'll help a lot
Khali nhi baithe hai sir! Too busy
What a professor and what a lecture. ❤
thanks, this is so clear and concise
indeed very straight to the point and concise, you get exactly what you come here for
thank you for ur clearly explanation, wonderful
Thank you. They're very helpful and so good to watch!
Wow great lecture👌👌thanks professor
|n> (subone) + C |n> (subzero) is going to be a linearly dependent solution isn't it?
Is the course of string theory for undergraduates by Prof. B. Zwiebach is available in video format. @MITOpenCourseWare reply
Currently not available in video format but is available in written at: ocw.mit.edu/courses/physics/8-251-string-theory-for-undergraduates-spring-2007/. There is video of a string theory course that focuses on holographic duality (Hong Liu. 8.821 String Theory and Holographic Duality. Fall 2014)-- TH-cam playlist: th-cam.com/play/PLUl4u3cNGP633VWvZh23bP6dG80gW34SU.html MIT OCW materials: ocw.mit.edu/8-821F14. Best wishes on your studies!
Whats the delta, he wrote before the Halitonian H ?
It is to denote the perturbed hamiltonian u can write H' instead...its not the dirac delta.
It change in Hamilton
The assumption of the series seems quite random to me. I don't know why exactly this works...
I've wondered the same thing. Must be derived from QFT or some higher-level quantum theory I don't know yet.
I think I might know why, but correct me if I missed something.
Lambda is just a parameter that changes the Hamiltonian slightly, so it makes sense that for each energy of the original Hamiltonian and its corresponding eigenstate, a small change in lambda will result in a small change in both said energy and state. Therefore you can think of the energy and state as functions of lambda: you input a value of lambda between zero and one, and you get the corresponding energy and state. Regardless of what these functions are (ie how changing lambda affects things), every function has a power series expansion, which will be a constant plus a lambda term plus a lambda squared term etc.
If you need a refresher, watch this th-cam.com/video/3d6DsjIBzJ4/w-d-xo.html
@@johnmccrae2932 thanks for your coment John, now i get it much better! :D
Great lecture!
lol 14:32 Professor trying to clear the parentheses but only making them thicker
You are the Best ❤️
Thank you Sir!
Thank you so much.
i wish you are my teacher ❤
Thanks
Why am I here, I don't even study physics
You do now. Get to work calculating the kets in the perturbative expansion. At once!
I didn't understand anything coz I'm a med student 😂😂😂
lol what are you doing here?
@@Egonkiller was curious as he seems a good teacher, lol
he's good especially if your prof in this subject just reads what's written in the book
Me too, but I'm a physics student 😂😂
Lamda Lamda Lamda is discussed more clearly in Revenge of the Nerds