Easy Steps to Draw A Hyperbola using Focus Directrix Method - Engg Curves - Engg Drawing
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- เผยแพร่เมื่อ 20 พ.ย. 2018
- This EzEd videos explains how to construct a HYPERBOLA using FOCUS DIRECTRIX METHOD when distance between the focus and DIRECTRIX is 50 mm and ECCENTRICITY is 3 by 2. Draw a TANGENT and NORMAL at any point on the hyperbola.
Solved Problem from University Questions
Instruments used are
Scale
French Curve
Geometric Compass
Protractor
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Very Useful For Last Minute Revisions 👌
Very ausome direct teaching no bakwaas👍
awesome explnation sir thank uh so much sir 😇😇
Thank you so much Sir🙏
Draw a hyperbola when the distance of its focus from directrix is 65 mm
and eccentricity is 4/3. Draw a tangent and normal to the curve at a distance
of 35 mm from directrix.
Try this one
Thank you so much
Thanks very much…please what app are you using to teach?
As of now I'm sitting in the engineering drawing lab at IIT kharagpur watching this cuz the TA's don't give a fuck
MMM hall just in case another kgpian is watching
Thanku very much sir
Please make a video to draw hyperbola by vertices focus method
Vertices and focus are given
@Abdul Majid Ali Muhammad. Thank You for your feedback. We will let our backend team know.
Draw a hyperbola when the distance its focus and directrix is
50mm and eccentricity is 3/2.
.Draw a conic curve when the distance of the focus from the vertex is 45 mm and
the eccentricity e = 3/2. Name the curv
Hyperbola
Construct Hyperbola Curve When Distance of Focus from Directrix is 45 mm and Eccentricity 2/1.
Thank you so much sir
Nyc
Kul
Aousam sir from
Gujrat...
What is answer it is 60mm
Ve distance
Very good
Why divide CF in 5 equal parts?
Because of 3+ 2 : 5
Abe parabola aur hyperbola ek hi jaisa tune nikala hai😂