Excellent presentation I like to present this video to my students in electricity, as they learn the concept of voltage considerations for the output of a full wave rectifier set up . Thank you , love this.
Hi. I think that at the series of measurements you are making at 3:00 are not an apples to apples comparison. E.g., the measurement at 2:54 with the DMM is 13.4 V but that is an RMS measurement corresponding to a peak voltage (Vp) 0f 18.95 V. The average value of a fullwave rectified signal is equal to 2*Vp/pi in this case being 12.06 V. The Rigol measures 11.7 average (corresponding to Vp of 18.4 V) which is only a fall of 0.4 - 0.5 volts through the diodes not 1.4 volts. This can also be seen when comparing peak voltages. Peak on the secondary is 18.95 V and peak on the Rigol is 18.6 volts corresponding to only a 0.4 V loss. So it appears that the actual voltage drop across the diodes is only on the order of 0.4 - 0.5 V total.
I'm watching you back catalog and enjoy your work ! from the secondary I multiply the RMS value by 1.414 to get the peak but cant remember why ! could you explain please ? ...cheers.
Yeah, RMS is a bit weird and can be confusing at first. We use RMS to have a useful numerical value when dealing with AC signals. With an AC signal, you can't get an average value, as it's typically 0, so that doesn't mean anything. And if you use the peak value to calculate average power dissipation, it will give you skewed numbers, as you aren't constantly dissipating that much power since the AC signal is typically much lower than the peak value. So, we get the Root Mean Square value to give us something to work with. To save ourselves a lot of trouble, some of the typical waveforms already have their values calculated out so you're not doing the entire RMS calculation each time. Sine waves are divided by the square root of two to get the RMS values (square waves/triangle waves/sawtooth waves all have a different value, if I remember correctly - this should make sense intuitively that different shapes yield different RMS values). SO! To get back from the RMS to the peak-to-peak values, you simply multiply it by the square root of 2 again (1.414). That was a bit long-winded but hopefully it helps!
Hi Raheela! I think this is an issue of us publishing these two videos out of order - check out our conceptual video on full wave rectifiers, that goes over the diagram and operation. Our thought was that you could learn how it works conceptually and then come and watch this video to see it in actual operation.
We absolutely can use a function generator in a full wave rectifier experiment. In real life applications, however, you're almost always using a transformer of some sort. But for experimentation, if you have a function generator, as long as you don't exceed the output restrictions (which function generators have a relatively high impedance output) you should be fine.
No, but we've talked about how once we actually start showing an income via CircuitBread that we'd like to start translating all of our content and providing subtitles in other languages as well. That would be very expensive, though, so I'm not sure when we'll be at that point. At the moment, CircuitBread is still a passion project that we do in our "free time" and is paid for by our client work. We're trying to change that now, though.
Excellent presentation I like to present this video to my students in electricity, as they learn the concept of voltage considerations for the output of a full wave rectifier set up . Thank you , love this.
u should have done all three rectifiers (half wave, full wave and full wave bridge) in three separate videos.. but, this was awesome
Hi. I think that at the series of measurements you are making at 3:00 are not an apples to apples comparison. E.g., the measurement at 2:54 with the DMM is 13.4 V but that is an RMS measurement corresponding to a peak voltage (Vp) 0f 18.95 V. The average value of a fullwave rectified signal is equal to 2*Vp/pi in this case being 12.06 V. The Rigol measures 11.7 average (corresponding to Vp of 18.4 V) which is only a fall of 0.4 - 0.5 volts through the diodes not 1.4 volts. This can also be seen when comparing peak voltages. Peak on the secondary is 18.95 V and peak on the Rigol is 18.6 volts corresponding to only a 0.4 V loss. So it appears that the actual voltage drop across the diodes is only on the order of 0.4 - 0.5 V total.
I'm watching you back catalog and enjoy your work ! from the secondary I multiply the RMS value by 1.414 to get the peak but cant remember why ! could you explain please ? ...cheers.
Yeah, RMS is a bit weird and can be confusing at first. We use RMS to have a useful numerical value when dealing with AC signals. With an AC signal, you can't get an average value, as it's typically 0, so that doesn't mean anything. And if you use the peak value to calculate average power dissipation, it will give you skewed numbers, as you aren't constantly dissipating that much power since the AC signal is typically much lower than the peak value. So, we get the Root Mean Square value to give us something to work with. To save ourselves a lot of trouble, some of the typical waveforms already have their values calculated out so you're not doing the entire RMS calculation each time. Sine waves are divided by the square root of two to get the RMS values (square waves/triangle waves/sawtooth waves all have a different value, if I remember correctly - this should make sense intuitively that different shapes yield different RMS values). SO! To get back from the RMS to the peak-to-peak values, you simply multiply it by the square root of 2 again (1.414). That was a bit long-winded but hopefully it helps!
@@CircuitBread Perfect ! thank you and yes that does make sense, I'm simply undoing the RMS calculation, great style for lectures...cheers.
Sir you haven't shared circuit's diagram!
Hi Raheela! I think this is an issue of us publishing these two videos out of order - check out our conceptual video on full wave rectifiers, that goes over the diagram and operation. Our thought was that you could learn how it works conceptually and then come and watch this video to see it in actual operation.
Thanks 👍 so much.
Thank you so much!
U are best physician
I have a doubt, Why do we use Transformer only for RECTIFIERS experiments?
Why can't we use a FUNCTION GENERATOR??
We absolutely can use a function generator in a full wave rectifier experiment. In real life applications, however, you're almost always using a transformer of some sort. But for experimentation, if you have a function generator, as long as you don't exceed the output restrictions (which function generators have a relatively high impedance output) you should be fine.
Do you make video in Hindi or Urdu language
No, but we've talked about how once we actually start showing an income via CircuitBread that we'd like to start translating all of our content and providing subtitles in other languages as well. That would be very expensive, though, so I'm not sure when we'll be at that point. At the moment, CircuitBread is still a passion project that we do in our "free time" and is paid for by our client work. We're trying to change that now, though.
*electroboom has entered the chat*
Haha! Electroboom is nuts - and a ton of fun to watch.