This is by far the most understandable explanation on this subject I have found so far. One thing to mention (you do so in a follow-up video, but I don't think it is here): this works on a dual supply op-amp, at least the negative rail needs to be able to get down to the Vf of the diode (I got all weird results with my LM358 connected to V+ and GND, but as a result I learned a lot). Thanks for this great video!
This is very useful. That "super-diode" circuit with a single diode is often shown as being correct, but the big mistake here is that the reverse-biased diode will open the feedback loop, and the op-amp might even misbehave if one of the inputs is out of the common-mode or differential mode range. Also, a too high impedance in the negative feedback loop is always a problem, and should be avoided at all costs, because the op-amp might oscillate (even if it apparently doesn't have any kind of positive feedback).
Wow what a great explanation. When you explained the use of the summation amp to make it a full wave rectifier, it immediately clicked in my head “oh duh” 😂
Note: one doesn't absolutely need precision resistors - 1 trimpot used in the feedback loop of the rectifier opamp *or* one trimpot to adjust the input weights into the inverting adder is enough to balance out any error in the other resistor pair.
Great explanation with practical demonstration. Which book you are referring in the video. Can you provide the book details. Also some suggested reading materials for experiment engineers.
you should show a op amp rectifier circuits witch uses only one Op and only like 5 resistors, to make it also very useful it only works on single rail supply which is very handy. This is interesting for Applications with a single rail supply, like in Sensors etc. one disadvantage is that the output is only 1/2 of an Ideal full way rectifier, if u are interested i can tell you i don't think it is a common known circuit, nice vid btw!
+davidbear1961 "Applications of Operational Amplifiers, 3rd Generation Techniques", by Jerald G. Graeme (Burr-Brown). It's an oldie, but a goodie; out of print unfortunately, but available as a PDF on archive.org: archive.org/details/ApplicationsOfOperationalAmplifiers-3rdGenerationTechniques
The drawing is different comparing to the schematic in the book. There is only one input connection at the beginning of the circuit. Where to connect the other wire, to ground? Same on the output.
If i have very low signal below the forward biased voltage of diode , can this configuartion rectify it with unity gain ? Or should i increase the gain then rectify it ?
Thanks for the video! At some point you said the fully rectified wave has double the original frequency. That's very interesting! I was looking for some way of obtaining half the frequency, maybe rectifying two halves up followed by two halves down. I think I would need some sort of memory trigger. Would you have some hint on how to achieve that?
The easiest way to divide the frequency of a signal by 2 is with a flip-flop: th-cam.com/video/OL52f-k3iIE/w-d-xo.htmlm28s . The output will be a square wave, so if you need a sine wave output, this would have to be low-pass filtered to remove the higher frequency content of the square wave.
Correct, mis-matches in the resistor ratios will cause error in the rectified output, as will imperfections in the op amp itself, such as input voltage offset errors.
Really great video, thanks for sharing:-) I hope that you'll please answer my noob question. To me it sounds like you have 2V peak to peak as AC input and 1V DC peak. Does that not mean that you loose 1 volt while rectifying?
so r1 and r2 becomes parallel with load resistor and forms a volt divider.r1 and r2 are in series since no current goes to i/p terminal of opamp . right?? NICE VIDEO
Nice. very good. what is the name of the book. and if you know a full wave rectifier with out diode and by op amps and can explained in tueb. thenk you a very mach.
Hi! Great video! Just discovered your channel it's great. I tried this circuit with a friend. The inverting half wave rectifier (in blue) seems to saturate 1.5V before reaching V-, even with a rail to rail OPamp. Is there a way to obtain such a swing? Maybe with your other circuit using a comparator and a relay? Thanks for reading.
+David Bernfeld Are you trying to run this circuit from a single supply? It's meant to be used with a dual supply; the rectifier circuit from my other video is a better choice for single supply operation. With that said, I'm not sure how a rail-to-rail op amp could be saturated if its output is 1.5V above V-? Could you provide some more details on your circuit and what you're seeing on the scope?
Thanks for the reply! It was in deed a single supply configuration. However, we did create a Vmid=Vcc/2 with 2 resistors and a buffer. The circuit should work exactly the same or are we missing something? We can't get closser to V- than 2 diode voltage drops. We tried your other circuit, works LIKE A CHARM! Thanks!
The resistor values at the frequencies typically used for this type of application aren't critical and are usually selected based on your desired input impedance for the circuit. Opamp selection is usually based on your requirements for the circuit; higher frequency signals will obviously need a faster op amp. For the examples here, IIRC, I used MCP601/602 op amps and 10K ohm resistors.
what if you use twoo opamps in parallel but one will use the non inverting input the sum of both in the output would be a fully rectified sinus to (just 2 cheap diodes extra to use)
You could do that, but you'd lose a diode of voltage on the output; if you're dealing with smaller signals, the diodes won't even turn on. Even if you're dealing with larger signals, the actual voltage drop across a diode is not precisely controlled, so you'd lose precision.
do i miss something? do you mean the half wave rectifier only suit for low resistance load? as the signal will have direct voltage division to the ouput
If you want half wave rectification with only one op amp and one diode as initially shown in the video, then yes, your load has to be much smaller than the series combination of R1 and R2. However, as shown at 7:56, the addition of a second diode fixes that particular issue, and you will get proper half wave rectification with both high and low resistance loads.
With the second diode in place the op amp can hold its inverting input at ground, since that diode is forward biased once the op amp's output drives ~0.6v negative. This makes the junction of R1 and R2 effectively grounded.
+Shawn Micheals Well it's a split supply design, which is usually undesirable for simplicity / low voltage operation. The circuit's primary performance disadvantage is that the slew rate of the op amp limits its frequency response. An alternative circuit that uses an op amp and a comparator helps to overcome both of these drawbacks: th-cam.com/video/1TLZBWx6BCc/w-d-xo.html
One common application is in the feedback loop of an automatic level control or automatic gain control circuit, say for an audio amplifier. By rectifying the audio signal, it is easy to detect the peak voltage of the signal and adjust the gain of the amplifier either up or down in order to maintain a constant amplitude output from the amplifier.
+Yuri Novais Araujo The circuits in this video are designed to be used with dual supplies (e.g., +-10V). I have another video on single supply rectifier circuits here: th-cam.com/video/1TLZBWx6BCc/w-d-xo.html
Book: Applications of Operational Amplifiers
This is by far the most understandable explanation on this subject I have found so far. One thing to mention (you do so in a follow-up video, but I don't think it is here): this works on a dual supply op-amp, at least the negative rail needs to be able to get down to the Vf of the diode (I got all weird results with my LM358 connected to V+ and GND, but as a result I learned a lot). Thanks for this great video!
I ran into the same problem during a simulation. Thanks for an excellent analysis and explanation of the behaviour of the circuit.
This is very useful. That "super-diode" circuit with a single diode is often shown as being correct, but the big mistake here is that the reverse-biased diode will open the feedback loop, and the op-amp might even misbehave if one of the inputs is out of the common-mode or differential mode range. Also, a too high impedance in the negative feedback loop is always a problem, and should be avoided at all costs, because the op-amp might oscillate (even if it apparently doesn't have any kind of positive feedback).
This has been EXTREMELY helpful!!! Very well explained. Thank you.
Thanks for sharing another excellent tutorial.
Wow what a great explanation. When you explained the use of the summation amp to make it a full wave rectifier, it immediately clicked in my head “oh duh” 😂
Thanks for taking the time to do this video. It is very educational.
At the end of the video, you explained about full wave rectifier but how does load affect the signal in the full wave rectifier?
Frequency doubling of triangle wave...wow, that's nice trick! :)
That was a very clear explanation....Thank You for the effort!!!! Loved it
Thanks for making this video. It is helping me to troubleshoot my own implementation which I am using a virtual ground.
Note: one doesn't absolutely need precision resistors - 1 trimpot used in the feedback loop of the rectifier opamp *or* one trimpot to adjust the input weights into the inverting adder is enough to balance out any error in the other resistor pair.
why can't any of my profs just fucking say this.
Good lord you make this easy. Well done.
Very useful And well explained sir
Great explanation with practical demonstration. Which book you are referring in the video. Can you provide the book details. Also some suggested reading materials for experiment engineers.
Very good video. Exactly the information I was looking for.
Can you please tell me which book is it?
Thank you so much for your explaination 🙏👑
you should show a op amp rectifier circuits witch uses only one Op and only like 5 resistors, to make it also very useful it only works on single rail supply which is very handy. This is interesting for Applications with a single rail supply, like in Sensors etc.
one disadvantage is that the output is only 1/2 of an Ideal full way rectifier, if u are interested i can tell you i don't think it is a common known circuit, nice vid btw!
+TecKonstantin Sounds interesting, I'd love to see a schematic!
What is the name of this book? Or what books you could recommend for better understanding of analog circuits?
You find out what is the name of the book?
@@huskialn2008 did you?
the book is by J.Graeme: applications of operational amplifiers
Excellent! Thank you.
Can't thank you enough for this video, brilliantly explained and super super helpful.
Awesome Explanation! keep up the good work.
@devttys0 can you please list the textbook you're using in the video?
Superb explanation. Thank you very much. TC.
At 10:10, why did the diodes flip direction?
Thanks for the well spoken demonstration ;-)
Brilliant, this video really helped!
Great explanation! Thanks a lot!
Great video, really helped!
Good enough to pass this test! Thanks!
This is great thanks! You made this very easy to grasp! I also like to see some practical examples of the results so thanks for that also.
What is the book that you are teaching from?
+davidbear1961 "Applications of Operational Amplifiers, 3rd Generation Techniques", by Jerald G. Graeme (Burr-Brown). It's an oldie, but a goodie; out of print unfortunately, but available as a PDF on archive.org: archive.org/details/ApplicationsOfOperationalAmplifiers-3rdGenerationTechniques
+devttys0 Thanks!
Thank you very much
www.introni.it/pdf/Graeme%20-%20Applications%20of%20Operational%20Amplifiers%203rd%20generation%20techniques%201973.pdf
Do you have suggestion what op amp ic that perform good with this circuit?
very clear explanation👍👍👍
The drawing is different comparing to the schematic in the book. There is only one input connection at the beginning of the circuit. Where to connect the other wire, to ground? Same on the output.
If i have very low signal below the forward biased voltage of diode , can this configuartion rectify it with unity gain ? Or should i increase the gain then rectify it ?
Very nicely explained
Thanks for the video! At some point you said the fully rectified wave has double the original frequency. That's very interesting! I was looking for some way of obtaining half the frequency, maybe rectifying two halves up followed by two halves down. I think I would need some sort of memory trigger. Would you have some hint on how to achieve that?
The easiest way to divide the frequency of a signal by 2 is with a flip-flop: th-cam.com/video/OL52f-k3iIE/w-d-xo.htmlm28s . The output will be a square wave, so if you need a sine wave output, this would have to be low-pass filtered to remove the higher frequency content of the square wave.
Dude great explanation!! Thumb up :)
Great video, I'am interested in that topic. So did we lost precision because R and R/2 resistors have not exactly values?
Correct, mis-matches in the resistor ratios will cause error in the rectified output, as will imperfections in the op amp itself, such as input voltage offset errors.
Really great video, thanks for sharing:-)
I hope that you'll please answer my noob question.
To me it sounds like you have 2V peak to peak as AC input and 1V DC peak. Does that not mean that you loose 1 volt while rectifying?
GOOD EXPLANATION.
Thank you. Great explanation especially with the screwdriver in your hand :D
so r1 and r2 becomes parallel with load resistor and forms a volt divider.r1 and r2 are in series since no current goes to i/p terminal of opamp . right??
NICE VIDEO
AGAIN: What is the name of the book?
mvp
whered u get that screwdriver from?! i love it
Awesome! What's that book btw?
Hi! Nice vid, and scope too :D
Nice. very good. what is the name of the book. and if you know a full wave rectifier with out diode and by op amps and can explained in tueb. thenk you a very mach.
beautiful.
awesome, thanks
Hi! Great video! Just discovered your channel it's great. I tried this circuit with a friend. The inverting half wave rectifier (in blue) seems to saturate 1.5V before reaching V-, even with a rail to rail OPamp. Is there a way to obtain such a swing? Maybe with your other circuit using a comparator and a relay? Thanks for reading.
+David Bernfeld Are you trying to run this circuit from a single supply? It's meant to be used with a dual supply; the rectifier circuit from my other video is a better choice for single supply operation. With that said, I'm not sure how a rail-to-rail op amp could be saturated if its output is 1.5V above V-? Could you provide some more details on your circuit and what you're seeing on the scope?
Thanks for the reply! It was in deed a single supply configuration. However, we did create a Vmid=Vcc/2 with 2 resistors and a buffer. The circuit should work exactly the same or are we missing something? We can't get closser to V- than 2 diode voltage drops. We tried your other circuit, works LIKE A CHARM! Thanks!
I am little late to the party, but can somebody send me a name of the book in the video ?
Thank you :)
Could you maybe use something plastic to point to the scope? The screwdriver makes my hairs stand up ;)
yeah, using the screwdriver as a pointer was just so cool lol! :)
Best explanation 👍👍 thanks
Hi!
What model was used Op Amp?
What are the resistor values?
The resistor values at the frequencies typically used for this type of application aren't critical and are usually selected based on your desired input impedance for the circuit. Opamp selection is usually based on your requirements for the circuit; higher frequency signals will obviously need a faster op amp. For the examples here, IIRC, I used MCP601/602 op amps and 10K ohm resistors.
Nice analysis. However 1:17 "passive diodes" are not passive. All semiconductors are active components by convention. HTH
+Smudger Dave Concurred, "passive" was a poor choice of words in an attempt to distinguish rectifiers that use amplifiers from those that don't.
what if you use twoo opamps in parallel but one will use the non inverting input the sum of both in the output would be a fully rectified sinus to (just 2 cheap diodes extra to use)
You could do that, but you'd lose a diode of voltage on the output; if you're dealing with smaller signals, the diodes won't even turn on. Even if you're dealing with larger signals, the actual voltage drop across a diode is not precisely controlled, so you'd lose precision.
thanks
do i miss something? do you mean the half wave rectifier only suit for low resistance load? as the signal will have direct voltage division to the ouput
If you want half wave rectification with only one op amp and one diode as initially shown in the video, then yes, your load has to be much smaller than the series combination of R1 and R2. However, as shown at 7:56, the addition of a second diode fixes that particular issue, and you will get proper half wave rectification with both high and low resistance loads.
devttys0 but i confuse that how does the addition of diode can fix the issue? there is still path along R2 and to the output
With the second diode in place the op amp can hold its inverting input at ground, since that diode is forward biased once the op amp's output drives ~0.6v negative. This makes the junction of R1 and R2 effectively grounded.
Oh,understood!!! thank you very much!!!
+devttys0 but its already grounded by virtual ground concept.right?
Hi !ggreat video ! can you list some of disadvantages of this FWR circuit.
thanks for reading!
+Shawn Micheals Well it's a split supply design, which is usually undesirable for simplicity / low voltage operation. The circuit's primary performance disadvantage is that the slew rate of the op amp limits its frequency response. An alternative circuit that uses an op amp and a comparator helps to overcome both of these drawbacks: th-cam.com/video/1TLZBWx6BCc/w-d-xo.html
Can you give me the name of that book you were using please?
+Josh Adams "Applications of Operational Amplifiers, Third-Generation Techniques": archive.org/details/ApplicationsOfOperationalAmplifiers-3rdGenerationTechniques
+devttys0 Thanks!
Which book..... Can u send me a soft copy
www.introni.it/pdf/Graeme%20-%20Applications%20of%20Operational%20Amplifiers%203rd%20generation%20techniques%201973.pdf
Diode 2 is the wrong way around, surely ?
very effective . thank u very much
What's a practical use of a precision rectifier?
One common application is in the feedback loop of an automatic level control or automatic gain control circuit, say for an audio amplifier. By rectifying the audio signal, it is easy to detect the peak voltage of the signal and adjust the gain of the amplifier either up or down in order to maintain a constant amplitude output from the amplifier.
interesting, thank you. appreciate the cool videos.
and the power supply ?
+Yuri Novais Araujo The circuits in this video are designed to be used with dual supplies (e.g., +-10V). I have another video on single supply rectifier circuits here: th-cam.com/video/1TLZBWx6BCc/w-d-xo.html
Book name please
thank you vary much......
can you please upload a video for "precision ac to dc converter using op amp"
The screwdriver on the screen is annoying.
Excellent, thank you very much!