Another Very Interesting Exponential Formula | Problem 381
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- เผยแพร่เมื่อ 5 ต.ค. 2024
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This problem was suggested by @RuleofThehyperbolic 🤩
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I feel so honored 💝
also I think its better to use the argument function even if its not as well defined as arctan
@@RuleofThehyperbolic glad to hear that! Keep up the good work 😍
I will try and memorise that. Never know when this general form will come in handy. 😂
@@mcwulf25 exactly, right? 😂😜
Beautiful formula
Nice, although messy!
Does it really work? If I said a, b, c, d. To equal 2, 0, 2, 0 then if I work through the formula in my head I get x = 1 and y = 0.... Don't understand what I'm doing wrong
Well arctan(b/a) with b=0 is 0 in first quadrant so with d=0 we get cos[]= 1 and sin[]=0.
The exponent becomes e^((1/2)lna^2) = e^clna = (e^lna)^c = a^c
Which is correct. If a=2,c=2 then x=4.
I understood the first 7 minutes and thought u kinda overcomplicated the start as we all know what r, tan equals to, yet then u idk just messed up my whole head and I have no clue how u calculated x+yi into the equation
why not generalize it even more? just kiddingbut it could be interesting 🤗 btw i really love your content ❤
@@sum2integral thank you! 😍
If A and B are both negative, then you will have the wrong Theta.
@@sdspivey exactly!