Von Mises 2 - Brain Waves.avi

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  • เผยแพร่เมื่อ 15 ต.ค. 2024
  • Here's an example of how to calculate Von Mises stress starting with a stress element. I start by drawing Mohr's circle and finding the principal stresses. Then I use those principal stresses to calculate Von Mises stress.

ความคิดเห็น • 69

  • @kamraman123
    @kamraman123 8 ปีที่แล้ว +22

    its so easy when you explain it like that! i wish we had more lecturers like you at my uni. i would actually enjoy mech eng more

  • @purdueMET
    @purdueMET  11 ปีที่แล้ว +3

    You are most welcome. My hobby these days is collecting hits on the TH-cam channel. If these videos are particularly helpful to you, please spread the word. I think it would be really cool to get 1 million hits on the channel.

  • @Digressionify
    @Digressionify 11 ปีที่แล้ว

    2nd year Mechanical Systems student here from Canada - Your video's have been very helpful to me and a great supplement to my lectures, THANKS!

  • @CareBear00031
    @CareBear00031 11 ปีที่แล้ว

    This is the most helpful thing ever. I can't thank you enough! I learned more from this video than I have in any of my lectures. Thank you for being so clear and not trying to just confuse us like so many teachers do!!!!!

  • @jeophilip4353
    @jeophilip4353 4 ปีที่แล้ว

    i feel so happy listening to your lectures

  • @muchen303
    @muchen303 10 ปีที่แล้ว +6

    The fact here is that Tresca criterion( 85+45 > 125) predicts a yielding but Von Mises says no. Therefore Tresca is more conservative!

  • @defendermodsandtravels
    @defendermodsandtravels 2 ปีที่แล้ว

    I think you have drawn the shear stresses in the negative direction. The normal convention is that a +ve stress acts on a +ve face in a +ve direction. You have used this convention for the normal stress components.

  • @skvetny
    @skvetny 11 ปีที่แล้ว

    Amazing... I was just killing myself over this issue untill i came across your video. Thank you Mark, you've made another Mech Engineering student's life more easy =]

  • @naveenkumaruthamanthil3579
    @naveenkumaruthamanthil3579 11 ปีที่แล้ว

    Thank you for the interesting insight into von Mises failure criteria.

  • @rosschambers1987
    @rosschambers1987 11 ปีที่แล้ว

    I'll do just that, I'll share with friends on my course. We're studying Aerospace Engineering at the University of Liverpool, 2nd year. Thanks again :-)

  • @Danbarnes92
    @Danbarnes92 12 ปีที่แล้ว

    this is a massive help for me doing my degree in the UK! thanks!

  • @eugenesmitsmit4781
    @eugenesmitsmit4781 7 ปีที่แล้ว +3

    Legend this guy!! I love him!!

  • @dannycheng7819
    @dannycheng7819 9 ปีที่แล้ว

    wonderful and clear review on von mises! thanks!

  • @madeinindia20
    @madeinindia20 4 ปีที่แล้ว

    You are the best! Thank you so much!

  • @attaponcharoenpon1890
    @attaponcharoenpon1890 7 ปีที่แล้ว

    Thank for sharing. I got more clearly in vonmises stress. Do you have other video like cauchy stress explanation or derivation?

  • @stooncol619
    @stooncol619 6 ปีที่แล้ว

    Sir thank you very much it is way clearer than before... just one question in case of pure shear what would be the approach to find von Mises stress

  • @purdueMET
    @purdueMET  11 ปีที่แล้ว +2

    Wow. I'm glad the video helped.

    • @raj144529
      @raj144529 4 ปีที่แล้ว

      Sir can I use your video for translating it to Hindi ( Regional Language of India). So that more students get's benefit.

  • @markmcpeake715
    @markmcpeake715 10 ปีที่แล้ว

    Hi.Quick question: I have never before come across your von Mises equation. I am more used to seeing and using the one which takes into account all 3 principal stresses. Can you point me to where the one you have used comes from please? Also, it seems that you left out the -ve sign when multiplying stress1 and stress2, but your answer is correct.I want also to thank you for all your videos which I have used extensively in my studies and have found extremely helpful and well presented. As a mature student of Open University, your input is invaluable and very welcome. Thank you.

    • @Bunk_Moreland
      @Bunk_Moreland 9 ปีที่แล้ว

      because we are working on a 2 dimension problem, component 3 values are zero. so if you substitude σ3 with 0 in the general von mises equation and calculate the bracket squares and add them up, you will get that equation.

    • @markmcpeake715
      @markmcpeake715 9 ปีที่แล้ว

      Thank you. I got a distinction in my final which Brain Waves helped me achieve.

  • @juamascf
    @juamascf 9 ปีที่แล้ว

    Using Tresca, would we say the element yields since |Sigma1 - Sigma2| = 130MPa which is greater than our yield strength (125MPa)?

  • @joelklopstein106
    @joelklopstein106 9 ปีที่แล้ว

    This guy makes me want to go to Purdue. I would definitely go to his office hours.

  • @uppalapusrinivasaraju1016
    @uppalapusrinivasaraju1016 7 ปีที่แล้ว

    One question. The obtained vonmiser stress must be within von miser oval drawn by principal stresses to say that it is safe. but here the vonmiser stress is off course closer to yield stress but not within oval shape. Is that safe?

  • @mustafahlal5533
    @mustafahlal5533 5 ปีที่แล้ว

    Are you can estimate the radius(maxi shear) by use ruler and multiple the gage in scale????? Without using the law !!!

  • @albertozanardi1
    @albertozanardi1 10 ปีที่แล้ว +1

    Great explanation, thanks!

  • @Megan-os5qt
    @Megan-os5qt 9 ปีที่แล้ว +1

    thank you! you are always very helpful!

  • @parkwaydriven92
    @parkwaydriven92 11 ปีที่แล้ว

    great videos! but do you have any examples on how to figure out the maximum shear stress when you only have the minimum principal stress and the failure envelope details?

  • @purdueMET
    @purdueMET  11 ปีที่แล้ว +1

    Thanks a bunch.

  • @kamatchikarthik8129
    @kamatchikarthik8129 6 ปีที่แล้ว

    Good explanation. Thank you

  • @rosschambers1987
    @rosschambers1987 11 ปีที่แล้ว

    Thank you for the excellent video. There are many more which I have found very useful as well which I have not liked or commented on (just because I have forgotten to).
    Thanks +++

  • @ladieman050893
    @ladieman050893 7 ปีที่แล้ว

    Thanks professor! Very helpful!

  • @11Winfield
    @11Winfield 12 ปีที่แล้ว

    sign convention is arbitrary?? cause i get neg for my shear

  • @joseemanuelrangelescalante7375
    @joseemanuelrangelescalante7375 8 ปีที่แล้ว

    hello , i would like to know if i can work von misses stress in 3d ?with a triaxial test?

  • @norestnomercy88
    @norestnomercy88 10 ปีที่แล้ว

    Thank you! That will be very useful for my exam! :D

  • @Ghulumasa101
    @Ghulumasa101 8 ปีที่แล้ว

    thank you sir, you saved my life

  • @luisahumada6081
    @luisahumada6081 2 ปีที่แล้ว

    I work as a Civil Engineering, and when people consider a Von mises stress analysis, people normally consider 0,6 Fy. I believe that this conservative criterion is wrong, and we need to consider just Fy or, maybe, 0,9 Fy if we want to be a little bit conservative...
    Any comments about it? I'd appreciate them a lot amigos.

  • @luisconradoalcalabecerra3559
    @luisconradoalcalabecerra3559 4 ปีที่แล้ว

    Great video thank you

  • @pavithrac6922
    @pavithrac6922 10 ปีที่แล้ว +1

    how do you say that maximum shear stress is zero. it is not 65MPa

  • @purdueMET
    @purdueMET  11 ปีที่แล้ว +1

    Thanks!

  • @ashishanand2662
    @ashishanand2662 11 ปีที่แล้ว

    Nice Explanation!!

  • @funtastictv9765
    @funtastictv9765 10 ปีที่แล้ว

    Thank you sir,It was a great explanation

  • @bertverschueren459
    @bertverschueren459 4 ปีที่แล้ว

    Thank you so much!

  • @adityamorey5662
    @adityamorey5662 11 ปีที่แล้ว

    though you didnt use the deviotoric stress tensor to come up with the criterion .. still amazingly explained .. thanks alot ..

  • @lhmissio
    @lhmissio 5 ปีที่แล้ว

    this is so good

  • @taseerbashir2334
    @taseerbashir2334 8 ปีที่แล้ว

    Thank you Sir you explanation is great, 5*****

  • @mistrysun1
    @mistrysun1 9 ปีที่แล้ว

    thanks that was very helpful!

  • @Souliee
    @Souliee 12 ปีที่แล้ว

    Really great! Thanks! :]

  • @han34han34
    @han34han34 4 ปีที่แล้ว

    You are fucking AWESOME!

  • @cemdemir536
    @cemdemir536 10 ปีที่แล้ว

    Many thanks :)

  • @Learning_for_life137
    @Learning_for_life137 6 ปีที่แล้ว

    Thank you sir

  • @PkBk2020
    @PkBk2020 9 ปีที่แล้ว

    Thanks alot....

  • @yannseillier3801
    @yannseillier3801 8 ปีที่แล้ว

    Super video ! thank you

  • @yamilduran6735
    @yamilduran6735 9 ปีที่แล้ว

    thanks!

  • @Tee.NZ.07
    @Tee.NZ.07 8 ปีที่แล้ว

    Don't know why I get 95 MPa instead of 114.3 MPa..

    • @danpt2000
      @danpt2000 7 ปีที่แล้ว

      maybe check your Mohr 's circle

  • @aadithyajeyaranjan6962
    @aadithyajeyaranjan6962 10 ปีที่แล้ว +5

    Isn't that shear -25 Mpa ?

    • @TheAusrali
      @TheAusrali 10 ปีที่แล้ว

      yeh he got it wrong but i guess it doesnt matter

    • @benejeneb
      @benejeneb 9 ปีที่แล้ว

      I was worried that I had it wrong. Cheers! All the rest is great though :) I can't believe he has the time, so useful!

    • @kristianSilva95
      @kristianSilva95 7 ปีที่แล้ว

      Yeah i spotted that at well, turns out im smarter than the lecturer

    • @emrage
      @emrage 4 ปีที่แล้ว

      @@kristianSilva95 Yeah you all sound super smart.. It's the way he's defined his sign convention hence Shear is +ve and his graph Tau is positive up.

  • @darrowshire11
    @darrowshire11 11 ปีที่แล้ว

    subscribed!

  • @265HITMAN265
    @265HITMAN265 12 ปีที่แล้ว

    i love you

  • @samarsawant6116
    @samarsawant6116 4 ปีที่แล้ว

    sigma bar= (sigmaX + sigmaY)/2, then it must be (80+40)/2= 60 MPa but you got 20MPa, everything in further calculations is ruined.

    • @christophermusso
      @christophermusso 4 ปีที่แล้ว

      @samar sawant sigmaY is a compression load and is therefore negative. (80 + (-40))/2 = 20 MPa

  • @hasben0
    @hasben0 11 ปีที่แล้ว

    Well fucking done.
    thanks alot

  • @gaylordrama
    @gaylordrama 12 ปีที่แล้ว

    Double like...

  • @junmingchen8787
    @junmingchen8787 4 ปีที่แล้ว

    thank you so much!

  • @johnnyodwyer7951
    @johnnyodwyer7951 7 ปีที่แล้ว

    Thank you sir!