You are most welcome. My hobby these days is collecting hits on the TH-cam channel. If these videos are particularly helpful to you, please spread the word. I think it would be really cool to get 1 million hits on the channel.
This is the most helpful thing ever. I can't thank you enough! I learned more from this video than I have in any of my lectures. Thank you for being so clear and not trying to just confuse us like so many teachers do!!!!!
Amazing... I was just killing myself over this issue untill i came across your video. Thank you Mark, you've made another Mech Engineering student's life more easy =]
I'll do just that, I'll share with friends on my course. We're studying Aerospace Engineering at the University of Liverpool, 2nd year. Thanks again :-)
great videos! but do you have any examples on how to figure out the maximum shear stress when you only have the minimum principal stress and the failure envelope details?
Hi.Quick question: I have never before come across your von Mises equation. I am more used to seeing and using the one which takes into account all 3 principal stresses. Can you point me to where the one you have used comes from please? Also, it seems that you left out the -ve sign when multiplying stress1 and stress2, but your answer is correct.I want also to thank you for all your videos which I have used extensively in my studies and have found extremely helpful and well presented. As a mature student of Open University, your input is invaluable and very welcome. Thank you.
because we are working on a 2 dimension problem, component 3 values are zero. so if you substitude σ3 with 0 in the general von mises equation and calculate the bracket squares and add them up, you will get that equation.
One question. The obtained vonmiser stress must be within von miser oval drawn by principal stresses to say that it is safe. but here the vonmiser stress is off course closer to yield stress but not within oval shape. Is that safe?
Thank you for the excellent video. There are many more which I have found very useful as well which I have not liked or commented on (just because I have forgotten to). Thanks +++
I think you have drawn the shear stresses in the negative direction. The normal convention is that a +ve stress acts on a +ve face in a +ve direction. You have used this convention for the normal stress components.
I work as a Civil Engineering, and when people consider a Von mises stress analysis, people normally consider 0,6 Fy. I believe that this conservative criterion is wrong, and we need to consider just Fy or, maybe, 0,9 Fy if we want to be a little bit conservative... Any comments about it? I'd appreciate them a lot amigos.
its so easy when you explain it like that! i wish we had more lecturers like you at my uni. i would actually enjoy mech eng more
You are most welcome. My hobby these days is collecting hits on the TH-cam channel. If these videos are particularly helpful to you, please spread the word. I think it would be really cool to get 1 million hits on the channel.
This is the most helpful thing ever. I can't thank you enough! I learned more from this video than I have in any of my lectures. Thank you for being so clear and not trying to just confuse us like so many teachers do!!!!!
2nd year Mechanical Systems student here from Canada - Your video's have been very helpful to me and a great supplement to my lectures, THANKS!
i feel so happy listening to your lectures
Amazing... I was just killing myself over this issue untill i came across your video. Thank you Mark, you've made another Mech Engineering student's life more easy =]
Thank you for the interesting insight into von Mises failure criteria.
this is a massive help for me doing my degree in the UK! thanks!
Legend this guy!! I love him!!
wonderful and clear review on von mises! thanks!
I'll do just that, I'll share with friends on my course. We're studying Aerospace Engineering at the University of Liverpool, 2nd year. Thanks again :-)
You are the best! Thank you so much!
The fact here is that Tresca criterion( 85+45 > 125) predicts a yielding but Von Mises says no. Therefore Tresca is more conservative!
Thank for sharing. I got more clearly in vonmises stress. Do you have other video like cauchy stress explanation or derivation?
Sir thank you very much it is way clearer than before... just one question in case of pure shear what would be the approach to find von Mises stress
Using Tresca, would we say the element yields since |Sigma1 - Sigma2| = 130MPa which is greater than our yield strength (125MPa)?
Wow. I'm glad the video helped.
Sir can I use your video for translating it to Hindi ( Regional Language of India). So that more students get's benefit.
Are you can estimate the radius(maxi shear) by use ruler and multiple the gage in scale????? Without using the law !!!
great videos! but do you have any examples on how to figure out the maximum shear stress when you only have the minimum principal stress and the failure envelope details?
thank you! you are always very helpful!
Hi.Quick question: I have never before come across your von Mises equation. I am more used to seeing and using the one which takes into account all 3 principal stresses. Can you point me to where the one you have used comes from please? Also, it seems that you left out the -ve sign when multiplying stress1 and stress2, but your answer is correct.I want also to thank you for all your videos which I have used extensively in my studies and have found extremely helpful and well presented. As a mature student of Open University, your input is invaluable and very welcome. Thank you.
because we are working on a 2 dimension problem, component 3 values are zero. so if you substitude σ3 with 0 in the general von mises equation and calculate the bracket squares and add them up, you will get that equation.
Thank you. I got a distinction in my final which Brain Waves helped me achieve.
One question. The obtained vonmiser stress must be within von miser oval drawn by principal stresses to say that it is safe. but here the vonmiser stress is off course closer to yield stress but not within oval shape. Is that safe?
sign convention is arbitrary?? cause i get neg for my shear
Thank you for the excellent video. There are many more which I have found very useful as well which I have not liked or commented on (just because I have forgotten to).
Thanks +++
I think you have drawn the shear stresses in the negative direction. The normal convention is that a +ve stress acts on a +ve face in a +ve direction. You have used this convention for the normal stress components.
Thanks a bunch.
hello , i would like to know if i can work von misses stress in 3d ?with a triaxial test?
thank you sir, you saved my life
Great explanation, thanks!
how do you say that maximum shear stress is zero. it is not 65MPa
This guy makes me want to go to Purdue. I would definitely go to his office hours.
Great video thank you
Thanks!
Thank you! That will be very useful for my exam! :D
thank you so much!
Thanks professor! Very helpful!
Good explanation. Thank you
I work as a Civil Engineering, and when people consider a Von mises stress analysis, people normally consider 0,6 Fy. I believe that this conservative criterion is wrong, and we need to consider just Fy or, maybe, 0,9 Fy if we want to be a little bit conservative...
Any comments about it? I'd appreciate them a lot amigos.
Thank you sir,It was a great explanation
this is so good
Nice Explanation!!
though you didnt use the deviotoric stress tensor to come up with the criterion .. still amazingly explained .. thanks alot ..
Thank you sir!
thanks that was very helpful!
Thank you Sir you explanation is great, 5*****
Thank you sir
Really great! Thanks! :]
Thanks alot....
Many thanks :)
thanks!
Isn't that shear -25 Mpa ?
yeh he got it wrong but i guess it doesnt matter
I was worried that I had it wrong. Cheers! All the rest is great though :) I can't believe he has the time, so useful!
Yeah i spotted that at well, turns out im smarter than the lecturer
@@kristianSilva95 Yeah you all sound super smart.. It's the way he's defined his sign convention hence Shear is +ve and his graph Tau is positive up.
Don't know why I get 95 MPa instead of 114.3 MPa..
maybe check your Mohr 's circle
Super video ! thank you
You are fucking AWESOME!
subscribed!
i love you
Well fucking done.
thanks alot
sigma bar= (sigmaX + sigmaY)/2, then it must be (80+40)/2= 60 MPa but you got 20MPa, everything in further calculations is ruined.
@samar sawant sigmaY is a compression load and is therefore negative. (80 + (-40))/2 = 20 MPa
Double like...
Thank you so much!