Formation of an Oxime from an Aldehyde

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  • เผยแพร่เมื่อ 2 ม.ค. 2025

ความคิดเห็น • 32

  • @vipulvaibhav3155
    @vipulvaibhav3155 4 ปีที่แล้ว +7

    Better than many educator of india.... LOVE Ur explanation

    • @abhijeetattri3483
      @abhijeetattri3483 ปีที่แล้ว +1

      That means you never reached to right person 😌

    • @kawaichanx3
      @kawaichanx3 2 หลายเดือนก่อน

      ​@@abhijeetattri3483 he said many dumbass

  • @manoharnath3025
    @manoharnath3025 ปีที่แล้ว +1

    Beautifully explained

  • @jongseokchoi4038
    @jongseokchoi4038 8 ปีที่แล้ว +2

    Wow so purified lecture with great detail.

    • @sarahchem4219
      @sarahchem4219  8 ปีที่แล้ว

      +jong seok choi - thank you!

  • @clintonkimathi7070
    @clintonkimathi7070 7 ปีที่แล้ว +3

    thank you sarah,you really helped me within minutes,,

    • @sarahchem4219
      @sarahchem4219  7 ปีที่แล้ว +1

      Thank you! Happy to hear that!

  • @jamiewatt6814
    @jamiewatt6814 7 ปีที่แล้ว +4

    Thanks this really helped with my chemistry project due tomorrow

  • @M10-r8q7h
    @M10-r8q7h 5 ปีที่แล้ว +1

    what an amazing explanation with beauty

  • @06aditya29
    @06aditya29 2 ปีที่แล้ว

    Ain't she the best🥺

  • @MakeupWithThea
    @MakeupWithThea 6 ปีที่แล้ว +3

    Thank you so much Sara! :)

  • @gktech.4321
    @gktech.4321 2 ปีที่แล้ว

    Nice video mam 😘😘😘😀 💐💐💐

  • @stonedandhammered
    @stonedandhammered 3 ปีที่แล้ว

    shouldn't the oh be protonated forming an h2o group, water is a good leaving group but oh is not?

  • @SportifyTVofficial
    @SportifyTVofficial 6 ปีที่แล้ว

    is this sn2 reaction?

  • @aijazzakiri1751
    @aijazzakiri1751 ปีที่แล้ว

    how to make Copper aldoxime? plz make a video for this.

  • @sarasara-ct6ro
    @sarasara-ct6ro 8 ปีที่แล้ว +3

    nice sara

  • @tinuthomaspunnackal5975
    @tinuthomaspunnackal5975 5 ปีที่แล้ว +2

    Thanku ma'am

  • @abangtikur3848
    @abangtikur3848 4 ปีที่แล้ว +1

    Sorry mrs, -OH is bad leaving group, I think OH can attack H in NH and than can be leave.
    Thank you mrs

  • @Aizen_Suigetsu__
    @Aizen_Suigetsu__ 5 ปีที่แล้ว

    Why nitrogen lone pair attacked to aldehyde
    Not of oxygen
    Oxygen has also lone pair of electrons

  • @RaviRanjankumar-iw8nz
    @RaviRanjankumar-iw8nz 4 ปีที่แล้ว

    Thanxxxx Sarah....

  • @nilabjamajumder110
    @nilabjamajumder110 4 ปีที่แล้ว

    THANKYOU MA'AM

  • @Azharkhan-wo2lj
    @Azharkhan-wo2lj 4 ปีที่แล้ว

    So attractive 😍😍

  • @mohsinali6681
    @mohsinali6681 6 ปีที่แล้ว +1

    Thanks.

  • @paulsigrist9360
    @paulsigrist9360 3 ปีที่แล้ว

    You forgot the positiv charge of the nitrogen group in the First intermediate

  • @kingkiran4015
    @kingkiran4015 2 ปีที่แล้ว

    Super

  • @owl49993
    @owl49993 2 หลายเดือนก่อน

    u ate

  • @LinhPham-4568
    @LinhPham-4568 2 ปีที่แล้ว

    x

    • @LinhPham-4568
      @LinhPham-4568 2 ปีที่แล้ว

      we're going to kick that up and dump those electrons on to this oxygen so now whenever you've got a tetrahedral intermediate which is what this is which is where a carbon is sp3-hybridized intermediate because this carbon here is attached to more than one electronegative group so we're going to know that that's not a very stable compound and we're altom utley going to have to continue the reaction until we're able to get it back down to an sp2 hybrid now the way that this will always transpire is once you've opened up the tetrahedral intermediate you're gonna protonate the group that you want to leave and you're gonna deprotonate the group that you want to stay so in this case here I'm not going to want the nitrogen group to leave as they just added it so what's gonna happen is I want to get rid of this group here ultimately and I want to keep this group on so what will happen is
      I need to protonate this group here protonation makes groups better at being kicked off or better leaving groups so this O we'll come and deprotonate the nitrogen here and this bond set will be turned into a lone pair sitting on top of that nitrogen so at the end of it here you have a neutral tetrahedral intermediate still even though it's neutral it's not particularly stable so this reaction onward so we need to shut this back down to an sp2 carbon so what will happen is that this the nitrogen with that lone pair is gonna push its lone pair down to reform the PI bond once again this carbon would have too many bonds if we left it like that so that means another bond will have to and over here because we've made this a relatively decent leaving group when this one shuts down we're going to be able to kick that OS group off so at the end here we've regained that sp2 hybrid and now we've kicked off this group here the last step is you typically want to eliminate charges that are left on your final product so this will act as a very good bazo it'll come and it will de protonate the nitrogen here forming water and then giving us our neutral oxime at the very end so that's how you would form an oxime from an aldehyde