How To Write The Equilibrium Expression For a Chemical Reaction - Law of Mass Action

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  • เผยแพร่เมื่อ 24 ธ.ค. 2024

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  • @TheOrganicChemistryTutor
    @TheOrganicChemistryTutor  ปีที่แล้ว +4

    Equilibrium - Free Formula Sheet: bit.ly/4eyKUeZ
    Chemistry 2 Final Exam Review: th-cam.com/video/lSmJN1_uVpI/w-d-xo.html
    Chemistry PDF Worksheets: www.video-tutor.net/chemistry-basic-introduction.html
    Next Video: th-cam.com/video/s0PnM_LlUp4/w-d-xo.html

  • @leonneer2221
    @leonneer2221 2 ปีที่แล้ว +51

    You are one of the main reasons my AP Chem is above 95% rn. Thank you so much for explaining everything so simply yet efficiently.

  • @parmisiguess
    @parmisiguess 3 ปีที่แล้ว +48

    you make chemistry not so scary

  • @vu6676
    @vu6676 6 ปีที่แล้ว +293

    Generally, this is an easy concept. However, what I didn't know until years after I took general chemistry is the fact that liquids and solids are not included in the equilibrium expression. I've gotten a question incorrect on an exam, and now I cannot forget it. Ingrain this fact into your memory guys!

    • @nicholasdsilva1832
      @nicholasdsilva1832 5 ปีที่แล้ว

      For heterogeneous reactions thats is

    • @dorsia6938
      @dorsia6938 4 ปีที่แล้ว +20

      This is not entirely correct. In a heterogenous system where the substances are in more than one phase, solids and liquids are not included in the equilibrium expression. In a homogenous system, where all substances are in the same phase, solids and liquids are included because the relative proportions are important.

    • @vd9420
      @vd9420 4 ปีที่แล้ว +5

      @@dorsia6938 Thank you for this info!!

    • @shreenidhhi8633
      @shreenidhhi8633 3 ปีที่แล้ว +2

      @@dorsia6938 thank you for this!! and btw the term 'relative proportion' how much of one thing you have relative to something else.
      where the 'one thing'= reactant, 'something else' = product.. right?

    • @1alex92
      @1alex92 2 ปีที่แล้ว +2

      I'm currently taking general chemistry... finally took the plunge to go back to school and get my bachelor's degree 🤓

  • @sajidrebellious7296
    @sajidrebellious7296 4 ปีที่แล้ว +33

    I did not understand in 40 min class and got confused but you understood that in first 2 min
    Thanks alot sir

  • @georgesadler7830
    @georgesadler7830 2 หลายเดือนก่อน +1

    Professor Organic Chemistry Tutor, thank you for showing How to write the Equilibrium expression for a Chemical Reaction in AP/General Chemistry. The concept is simple to follow and understand provided that students/nonstudents realize that liquids and solids are not included in the equilibrium constant expression. This is an error free video/lecture on TH-cam TV with the Organic Chemistry Tutor.

  • @initialdluvr
    @initialdluvr 2 ปีที่แล้ว +4

    I'm taking General Chemistry in an accelerated program. I use my textbook as an itinerary and this TH-cam channel to do my learning.

  • @aimbotbob5056
    @aimbotbob5056 7 ปีที่แล้ว +38

    I literally just learned this in chem today lol. Good review

    • @srirachasoldier3417
      @srirachasoldier3417 3 ปีที่แล้ว +2

      I literally have a test tomorrow about this, and I am only learning about it now lol

    • @Felix-pw5gz
      @Felix-pw5gz 2 ปีที่แล้ว

      @@srirachasoldier3417same here haha

  • @JustHalima
    @JustHalima 3 ปีที่แล้ว +10

    Watching this now because I have a Chemistry exam tomorrow 😩

  • @frankvalenti8350
    @frankvalenti8350 5 ปีที่แล้ว +12

    This dude is always good with his explanations

  • @ShahmeerKhanGamer
    @ShahmeerKhanGamer 4 ปีที่แล้ว +11

    *The Organic Chemistry Tutor* > 90% of Chemistry teachers

  • @yosithegamer1104
    @yosithegamer1104 2 ปีที่แล้ว +3

    who else is watching this at 1.5x speed

  • @Rrrx1199
    @Rrrx1199 3 ปีที่แล้ว +2

    Very useful simply explained
    Thank you

  • @dido173
    @dido173 ปีที่แล้ว +4

    When your chem teacher does everything else EXCEPT for teaching so you gotta re-teach yourself everything he “teaches” 🙄🙄

  • @MariyamathShaniba
    @MariyamathShaniba หลายเดือนก่อน

    Thank you it’s clear now👍

  • @foxtrotalpha7119
    @foxtrotalpha7119 3 ปีที่แล้ว +2

    Thanks a lot this was really helpful

  • @N.Afridi
    @N.Afridi 2 ปีที่แล้ว +1

    Why we take the ratio of products to reactants not by the ratio of reactants to products?

  • @jodifrye8877
    @jodifrye8877 4 ปีที่แล้ว +9

    Thank you! This breaks down the essence of the topic while giving you all of the details you need to solve problems!

  • @yosithegamer1104
    @yosithegamer1104 2 ปีที่แล้ว +2

    I wish I would subscribe him 2 times

  • @santosh.s8693
    @santosh.s8693 4 ปีที่แล้ว +1

    It was very useful thankyou sir

  • @veganwaffle
    @veganwaffle 3 ปีที่แล้ว

    You made it so easy

  • @prinseslutfia8737
    @prinseslutfia8737 2 ปีที่แล้ว

    Wowwwwwwww proud of you

  • @christinapajudpud-tl9ey
    @christinapajudpud-tl9ey ปีที่แล้ว

    Thank you for clarification 💗

  • @Samruddhi-go7mk
    @Samruddhi-go7mk 2 ปีที่แล้ว

    thank you so much this helped a lot :)

  • @talhashakeel7089
    @talhashakeel7089 3 ปีที่แล้ว

    Is Kc used for solid & liquid phase??

  • @jakevehar
    @jakevehar 4 ปีที่แล้ว +2

    U literally saved me

  • @waseemafridi1858
    @waseemafridi1858 3 ปีที่แล้ว

    It means we will put product upside and reacrants below....

  • @taekookandot7601
    @taekookandot7601 2 ปีที่แล้ว

    nice video but can you raise your volume if u have some time

  • @bhx_5912
    @bhx_5912 2 ปีที่แล้ว

    Didn't know it was this easy😹tnx

  • @arliinroze7618
    @arliinroze7618 4 ปีที่แล้ว +1

    the explantion was good but i got stuck on where did he get the coefficients?? the 1,1,2 & 1,3,2

    • @arliinroze7618
      @arliinroze7618 4 ปีที่แล้ว

      @Yu Katsuragii nah i think it depends if it was given as for my problem there were no coefs sooo i solved w/o coefs coz there was no indicated..🙂🙂

    • @arliinroze7618
      @arliinroze7618 4 ปีที่แล้ว

      thank u..

  • @linsdesk7240
    @linsdesk7240 3 ปีที่แล้ว

    Thank u so so much!!

  • @vinnamaealegado1366
    @vinnamaealegado1366 4 ปีที่แล้ว +2

    Just wow. Mas magaling pa magturo to

  • @airrroults1727
    @airrroults1727 5 ปีที่แล้ว

    Sir if we consider x mole of N2 than want be

  • @carlossmith2315
    @carlossmith2315 2 ปีที่แล้ว

    you're my hero

  • @rhaizaandreaparala6682
    @rhaizaandreaparala6682 3 ปีที่แล้ว

    Thank you so much ❤️

  • @mrfactman9952
    @mrfactman9952 4 ปีที่แล้ว +4

    Legends are watching in nov and dec

  • @1alex92
    @1alex92 2 ปีที่แล้ว

    Can I submit questions to you? LORD knows I struggle a bit in this... like... I kinda like chemistry... I just need more help to fully grasp it.

  • @brandonmarrs8448
    @brandonmarrs8448 ปีที่แล้ว

    Thank you!!!!

  • @totorabby3286
    @totorabby3286 2 ปีที่แล้ว

    Thank you bro

  • @nishagaihre6463
    @nishagaihre6463 2 ปีที่แล้ว

    Thank you ❤️❤️❤️

  • @dolocabaip
    @dolocabaip 3 ปีที่แล้ว

    Thank you for this♥️

  • @mariamjoyced.tanjay2047
    @mariamjoyced.tanjay2047 3 ปีที่แล้ว

    thank you!

  • @meliachanel8062
    @meliachanel8062 5 ปีที่แล้ว

    Amazing thank you so much

  • @troll_ac
    @troll_ac 2 ปีที่แล้ว

    My teacher is a newbie to this chemistry subject so we have a hard life

  • @khuuus5994
    @khuuus5994 2 ปีที่แล้ว +1

    Dont why techers make it uncessesary tough

  • @claytonmcdonald8603
    @claytonmcdonald8603 4 ปีที่แล้ว

    You my boy blue !

  • @ravikumar-sq3bh
    @ravikumar-sq3bh 3 ปีที่แล้ว

    Thanks

  • @suleimanyusufabubakar6312
    @suleimanyusufabubakar6312 10 หลายเดือนก่อน

    You the best

  • @rodicavakulich6304
    @rodicavakulich6304 4 ปีที่แล้ว +1

    you are a genius! thank you!

  • @dovelybora001
    @dovelybora001 4 ปีที่แล้ว

    Thanks.

  • @hxh2000
    @hxh2000 4 ปีที่แล้ว +1

    thx

  • @komalsaini8963
    @komalsaini8963 3 ปีที่แล้ว +1

    Sulphur trioxide decomposes at high temperature in a sealed container:
    2S03(g) ⇌ 2SO2(g)+ O2(g)
    Initially the vessel is charged at 1000 K with S03(g) at a concentration of 6.09 x 10-3 M. At equilibrium, the concentration of S03(g) was 2.44 x 10-3 M. Calculate the value of Kc
    Can someone pls help me out with this

    • @Chuck-Noris
      @Chuck-Noris 2 ปีที่แล้ว +9

      man you took an L. 7 months and nothing. Sorry

  • @rRennnnn
    @rRennnnn 2 ปีที่แล้ว

    HOW DO YOU KNOW WHEN THE REACTION IS BALANCED OR NOT HELP😭

    • @mrcrispycocoa
      @mrcrispycocoa 2 ปีที่แล้ว +1

      Might be a bit late, but basically a balanced equation is when both sides have an equal amount of each element. And basically you check that to see if it's balanced or not.
      *Note, just in case: if an element doesn't have number to it's right, that means there's just 1 of it. Ex: NH3 is just N1H3
      For example, the first example shown in the video is: N2 + H2 = NH3
      However, this equation is not balanced as the left side contains 2 Nitrogen and 2 Hydrogen, while the right only contains 1 Nitrogen and 3 Hydrogen.
      So, in order to balance them, or make the amounts of elements equal on both sides, this happens:
      1(N2) + 3(H2) = 2(NH3) --> N2 + H6 = N2H6
      or basically: N2 + H6 = N2 + H6
      *Second note: the 2 on the right gets distributed to both N and H.
      This whole process of balancing is basically trying to find the least common "multiple" between both sides.
      I hope this helps, and if you've already figured it out by now that's equally as great.
      I also wrote this reply on desktop, so it might look weird if you're viewing it through mobile.

    • @rRennnnn
      @rRennnnn 2 ปีที่แล้ว

      @@mrcrispycocoa your late BUT TYSM i actually understand now lol TYYY

  • @vidiomania2268
    @vidiomania2268 6 ปีที่แล้ว

    Thnx alot ✔💕👌💯

  • @aaronpayton7547
    @aaronpayton7547 3 ปีที่แล้ว +1

    I love you

  • @shexthhazalobroak1333
    @shexthhazalobroak1333 ปีที่แล้ว

    ❤❤❤❤❤❤

  • @Erdbeeren_
    @Erdbeeren_ 2 ปีที่แล้ว

    Thanks a lot.

  • @erfankarami9586
    @erfankarami9586 3 ปีที่แล้ว

    Thx for video

  • @dumb8453
    @dumb8453 2 ปีที่แล้ว

    Thanks