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Thank you, as always, for your enjoyable questions!log(2^x * (3^(x^2) ) = log(2*3)log(2^x) + log(3^(x^2)) = log2 + log3xlog2 + (x^2)* log3= log2 + log3let A=log3, B=log2Ax^2 + Bx - A - B = 0(Ax + (A+B))(x-1)=0x = 1orAx = -A+Bx = -(A+B)/A = -log6/log3
Always welcome 😊🙏👏✅😎💕
I think that a×b=c×d iff a÷c=d÷b, therefore the first statement doesn't imply the second; it's equivalent statement of it, a restatement actually achieved by dividing both sides by b×c. Thanks for the elaborate demonstration
You're welcome 💯✅🥰💕😎
X=1
(2)^2× (3x)^2={4×9x^2}=36x^2 6^6x^2 2^3^2^3x^2 1^1^1^3x^2 3x^2 (x ➖ 3x+2).
2^(x-1)*3^(x^2-1)=1(x-1)log2+(x^2-1)log 3=0(x-1)*(log2+log3)+(x+1)log3=0xlog6-log6+xlog3+log3=0x log18=log2x = log2/lo18
Thank you, as always, for your enjoyable questions!
log(2^x * (3^(x^2) ) = log(2*3)
log(2^x) + log(3^(x^2)) = log2 + log3
xlog2 + (x^2)* log3= log2 + log3
let A=log3, B=log2
Ax^2 + Bx - A - B = 0
(Ax + (A+B))(x-1)=0
x = 1
or
Ax = -A+B
x = -(A+B)/A = -log6/log3
Always welcome 😊🙏👏✅😎💕
I think that a×b=c×d iff a÷c=d÷b, therefore the first statement doesn't imply the second; it's equivalent statement of it, a restatement actually achieved by dividing both sides by b×c. Thanks for the elaborate demonstration
You're welcome 💯✅🥰💕😎
X=1
(2)^2× (3x)^2={4×9x^2}=36x^2 6^6x^2 2^3^2^3x^2 1^1^1^3x^2 3x^2 (x ➖ 3x+2).
2^(x-1)*3^(x^2-1)=1
(x-1)log2+(x^2-1)log 3=0
(x-1)*(log2+log3)+
(x+1)log3=0
xlog6-log6+xlog3+
log3=0
x log18=log2
x = log2/lo18