Bernoulli's Differential Equation | Reducible to linear Differential Equation | Problem 1 | Maths

problem on Bernoulli's Differential Equations
numerical on Reducible to linear differential equation
first order differential equations
#Maths2
#differentialequations
‪@gautamvarde‬

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All the best dear Sumit

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Bechari

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Thanku Sir pura basic Se samjhane Ke liye

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Welcome dear

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Thanku Sir ! you are cleared almost all basic doubts for bernoulli's

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It's my pleasure dear

[@AltheaKhemBermas]

Thank you for this video.....❤

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My pleasure 😊

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Great Explanation sir 👍

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Thank you sir

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Welcome dear

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Thank you 🙏

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Welcome

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Itna clear concept to koi nahi btata😮😮

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💖

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Agree👌

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Many many thanks dear

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Thankyou sir from NASA ❤

[@Randomshorts2701]

1/y2 = y-2 not y-1

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💞🇮🇳

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Ye theorem kisi ne nahi samjhaya mere ko 😢 thank you sir 😊

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Thanks dear for your appreciation

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Thank you sirji🥰

[@NickSJ24]

Finally, the one video that made me understand Bernouli's Equation. Thank you so much sir. Much Love

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All the best dear

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@@rajeshkk2942 Chandigarh University

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Same to you dear ❤️

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6:00 Sir 😢 -1y^-1-1 likh ke kyun phir se dy/dx likh rehe ho ?

[@architakaushal2728]

Jaise hum x^2 differentiation krte hai dx^2/dx=2xdx/dx
dx/dx=1 hota hai isiliye hum keval 2x likh dete hai

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Thnk u🤗

[@VijayMishra-q8n]

Y^n se divide karna hai

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Sir hr question m y^2 se hi divide krna h kya?

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Nhi brother y^n se divide krna hota hai mtlb jaha pr bhi y ki greatest power ho usse divide krdo

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👍

[@MANASJOWD]

Sir divide by y^n hoga not y^2

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Sir
Solution mae mistake ha..

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Yes dear
It will take time

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Kal m2 hai aur aaj mai ya padh rha hu

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All the best dear

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Sir mistake hai todi apke Solution me

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Sir yeah sahii method ha naa isme v ki value put nhi krenge toh bhi sahi rahega kya

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sir method ke step galat he ek baat check kijiye

[@76sudha]

If 4(y d_{w} + p(x) * y = Q(x) * y ^ n is a Bernoulli differential equation then tick the correct statement(s).
(a) For n = 1 given differential equation can be solved by variable separable.
dv b) For n ne1 on substituting y^ n-1 =v gives (- v)/(dx) + (1 - n) * p(x) * v = (1 - n) * Q(x)
(c) * Forn = 1 given differential equation can be written as y^ prime prime (uy)/(dx) + p(x) * y ^ (1 - u) = Q(x)
(d) For 1 given differential equation can be written as y ^ (- n) * (ay)/x + p(x) * y ^ (- (n - 1)) = Q * (x)
Plzz ans 🙏

[@76sudha]

Please reply sir

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kahe padha rahe ho😭😭

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😊

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😂😂ky padha rhe ho sir

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Mathematics 😅

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Thank you sir

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Welcome dear

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Thank you sir ❤🎉

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Most welcome 😊

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Thank you sir

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Welcome dear