EVALUATING MEAN, MEDIAN AND MODE OF A GROUP DATA

[@nativemuno]

Very helpful, thanks God bless you Sir.

[@kyyomuhendoScovia]

GOOD EXPLANATION ALL IS UNDERSTOOD WELL

[@mugalaasialexander3273]

i have watched a number of videos teaching his topic but this the most summarized and simplest video to understand. the explanation is just on point and the detailing of the meaning of each symbol in the formulas makes it easier for someone to understand better

[@begechorimaths2975]

Thank you so much, I really appreciate 🙏🙏🙏

[@clickdotcome1306]

God will bless you sir

[@BeatriceMuwowo]

❤

[@FaithJerotich-i1q]

Mean is=46.5

[@kaylarichards6700]

You miscalculated the 41-50 part, 45.5*11 is 500.5 , instead of 555.

[@kaylarichards6700]

610.5 *

[@begechorimaths2975]

thank you for the notice, will correct it.

[@Gullon613]

Thank You So Much Sir !

[@emmanuelbantai8135]

this was a very elaborative tutorial i have understood every thing thank you

[@begechorimaths2975]

thank you so much...

[@VishalKumar-qv7bv]

I appreciate you man..
You cleared
my doubt..

[@begechorimaths2975]

you are welcome bro..

[@Unknown-ko8ng]

Understood well❤🎉

[@NasaasiraDeogratius]

Ur doing it 👍👍

[@ShamimHassad-mz8hm]

Thank u sir its my exam 2morrow

[@begechorimaths2975]

wishing you the very best in your exams...

[@KimbowaDaisy]

Thank you sir.

[@chideraezenwaka5444]

Beautiful video🖤👏🏾

[@YaBoiVoid.]

thanks i was struggling with a project 💀

[@FaithJerotich-i1q]

I appreciate your doing but the mean is wrong sir

[@GiftyPeku]

Thanks

[@mohamedkamara6762]

Thank you for your good work , but you miscalculated the fx of 41-50

[@krishnank2711]

Mean is wrong i got 46.5

[@begechorimaths2975]

@@krishnank2711 yeah.. I noticed that, it's writing error but the steps are detailed and valid hence I kept it, I posted other videos on the same topic with such errors.
Thank you for the observation.

[@edwardmuriuki]

Thank uu

[@JusticeImolore]

According to my study, I found out there are inclusive and exclusive grouped data. Which I believe that the grouped data is inclusive, why didn't you convert it to exclusive grouped data before solving?

[@FirminohRobertoh]

Is it not important to first find the real class boundaries before finding the mean..like to close the gaps between the class limits??

[@EbenezeraAtubilaa]

Please interquartile deviation and mean deviation are the same or different

[@begechorimaths2975]

No they ate not...
Thanks

[@eseyinawe]

Good day. I thought the cumulative frequency is 20+11/2 but why did you start start with 4 when solving for the median

[@eseyinawe]

Good day. I thought the cumulative frequency is 20+11/2 but why did you start start with 4

[@ceciliaashuulu5717]

Tell me how did you get the "F"

[@deopraise5669]

great

[@begechorimaths2975]

thanks a lot

[@ceciliaashuulu5717]

Please tell me how you get the frequency please is very urgent

[@begechorimaths2975]

@@ceciliaashuulu5717 The frequency in this question was given already but I also have a video that I posted and showed how students can get frequencies when given raw data. you can check my videos on statistics to watch.

[@GetrudeMukanda]

For the mean the answer is 46.5 not 48.7

[@TulibasikaEsthermiracle]

Mean is very wronh
Its 46.5

[@begechorimaths2975]

@@TulibasikaEsthermiracle yeah I know about it after I posted it, the reason I left it is because of the beautiful explanation of the methods used.

[@AyanateNwogu]

Mean is wrong

[@ThomasNathanael-s9j]

I agree with you

[@WaliKuri-m8y]

Wrong ni hai

[@onwukavincent]

How is it wrong

[@DavidAkpan-k4t]

Please is it possible to approximately the mean to 49 instead of 48.7

[@begechorimaths2975]

Yeah, but it depends on the instruction from the question, so I advise you do as instructed.

[@NomenSojini]

What is 11×45.5 when calculating the m

[@chas_nomnom]

500.5 is the right answer, he miscalculated it ig that's why

[@estheranyanwu9627]

How did you get the class C

[@begechorimaths2975]

class width (C) can be found through different methods but one of the easiest is to subtract the upper limit and lower limit of the class boundaries of what you are looking for e.g for median class
50.5 - 40.5 = 10
hence C= 10
hope you are satisfied ?

[@Football10111-d]

bro 45.5*11= 55.0

[@ndithomas1958]

Please, I don't understand how you got 0.64 in the calculation for median

[@begechorimaths2975]

okkk... in the bracket you have 25-18=7, 7÷11=0.64 approximately.
Hope you are OK now?

[@ndithomas1958]

@@begechorimaths2975 yes, thanks

[@venkateshpani7814]

A facul Salim go 1 point also not understood go why are you doing the channel

[@eseyinawe]

Good day. I thought the cumulative frequency is 20+11/2 but why did you start start with 4 when solving for the median