@@readingnlearning176 The question is to calculate probability of atmost two tails P(E), given that we already have at least one tail P(F). The probability of having atmost two tails when a coin is tossed 3 times is 7/8. The probability of having at least one tail is also 7/8 and their intersection (E and F) is 6/8. When we calculate P(E|F) we get (6/8)/(7/8), hence answer is 6/7
Sir will the interdisciplinary data science courses in top iit will not be a interdisciplinary from 2024 as data science is a new gate paper so will they take admission from that gate score only ??
@@Niveditha_Ramesh take the common value of E and F For an example in (ii) E contains 4 different values and F contains 7 different values but the common values are only 3 which are {HHT, HTH, THH} Follow the Same concept in (iii) also
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Awesome. I have attended many sessions on Conditional Probability but this one is what I liked best.
Thanks for positive feedback. And keep watching
thank you so much sir for best approach to finding conditional probability
Q2): ii) 3/7 and iii) 6/7
Finally understood what is conditional probability in btech 3rd year😢
so wht you did in 2nd year....forgot utube?
@@wendelfernandes8397😂😂
@@wendelfernandes8397 backlog bro :(
@@nonstopcodingcodewithadity8238 😞
Ab 4th year ?
Clearly understood 💯
Learned a new approach to solve questions of Conditional Probability sir.
Q2 (ii) 3/7 (iii) 1
Great 👍
Your answer to (iii) is wrong, it should be 6/7
@@sanyogjain9195coulr you explain me how this answrr is calculatdd
@@readingnlearning176 The question is to calculate probability of atmost two tails P(E), given that we already have at least one tail P(F). The probability of having atmost two tails when a coin is tossed 3 times is 7/8. The probability of having at least one tail is also 7/8 and their intersection (E and F) is 6/8. When we calculate P(E|F) we get (6/8)/(7/8), hence answer is 6/7
@@sanyogjain9195 read the q correctly
nice explanation
sir
I am jee aspirant good explains❤❤❤❤❤❤❤❤
Sir one question when will the live classes held ?
I although turned on notifications but didn't get 🥲
Sir please provide notes also ❤
Ye smajh nhi aaya k coin k teen dfa toss hone pr outcomes 8 kese?
2^n, number lf coins= 3, so 2^3 = 8
Bhai soya q rehta hai ?
He is the type of person who always sit with me at the last bench of the class and do things when times is short i.e. one night full fight
WHERE IS THE LIVE CLASSES?
Bhai pata chala to mujhe bhi batana 😅
Sir will the interdisciplinary data science courses in top iit will not be a interdisciplinary from 2024 as data science is a new gate paper so will they take admission from that gate score only ??
Q) 2.(ii) E = {HHT, HTH, THH, HHH}
P(E) = 4/8
F = {HHT, HTH, THH, HTT, THT, TTH, TTT}
P(F) = 7/8
E ∩ F = {HHT, HTH, THH}
P(E ∩ F) = 3/8
now : P(E/F) = P(E ∩ F)/P(F) = (3/8)/(7/8) = 3/7
(iii) E = {HHT, HTH, THH, HTT, THT, TTH, HHH}
F = {HHT, HTH, THH, HTT, THT, TTH, TTT}
P(F) = 7/8
E ∩ F = {HHT, HTH, THH, HTT, THT, TTH}
P(E ∩ F) = 6/8
now : P(E/F) = P(E ∩ F)/P(F) = (6/8)/(7/8) = 6/7
Correct 👍 👍 . Keep watching.
Please tell how to take common P(E ∩ F) ???
@@Niveditha_Ramesh take the common value of E and F
For an example in (ii) E contains 4 different values and F contains 7 different values but the common values are only 3 which are {HHT, HTH, THH}
Follow the Same concept in (iii) also
@@MARK97GAMING Thankyou☺️
Hum F me TTT bhi count krein ge?
Coin wala toh lg rha hai aapne 3coins simultaneously toss kiya rather than one coin 3times
❤
A coin is tossed 3 time... 3 coins toss kb bola
varun sir kaha he T_T
Ap Sahi nhi smjha rhy Kuch Kuch theak nhi h apky smjhny m ab 1/4 kha se lay ay h ap