Resolution of enantiomers | Chemical processes | MCAT | Khan Academy

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  • เผยแพร่เมื่อ 5 ม.ค. 2025

ความคิดเห็น • 13

  • @Mariyakhan6642
    @Mariyakhan6642 4 หลายเดือนก่อน +1

    Thanks

  • @Moxormog
    @Moxormog 10 ปีที่แล้ว +2

    I love you! This is going to help me on my orgo I exam :)

  • @wrednykocurek
    @wrednykocurek 4 ปีที่แล้ว +2

    also chiral stationary phase reacts with both enantiomers, but with a different strenght of binding. Guy who is stronger interacting will come later, guy who is weaker interacting will come first, I think there is over statement in your video, nevertheless pretty good

  • @adventurevloggeradnanahmedusa
    @adventurevloggeradnanahmedusa 8 หลายเดือนก่อน

    In this example, is the chiral stationary phase R?

  • @kachingchan9228
    @kachingchan9228 10 ปีที่แล้ว

    thanks very much!!

  • @avirajsarkar5846
    @avirajsarkar5846 10 ปีที่แล้ว +1

    plz explain the apparatus in the experiment......

  • @pharmedutainment
    @pharmedutainment 7 ปีที่แล้ว

    What program is used to produce the drawing in concert with the discussion?

  • @taylorclarke2550
    @taylorclarke2550 6 ปีที่แล้ว

    Wouldnt the molecules at the beginning of the video be diastereomers not enatiomers because the configuration of one of their chiral centers is different?

    • @romainrabany8278
      @romainrabany8278 5 ปีที่แล้ว +3

      recall: diastereomers are not superimposable and not mirror images of each other. Enantiomers on the other hand are not superimposable; however, they are mirror images of each other. I think what you are mistaking with is what is called an epimer, where one chiral center differs in both molecules; however, epimers are a type of diastereomer and not an enantiomer of eachother. if you imagine putting one of the molecule in the beginning of the video in front of a mirror we would obtain the other molecule.

  • @wrednykocurek
    @wrednykocurek 4 ปีที่แล้ว +2

    Not S or R conformation, configuration is the proper word

  • @trollmcclure1884
    @trollmcclure1884 4 ปีที่แล้ว

    so there'S no easy way I can test my L-ascorbic acid without chiral stationary phase? That's what I thought

    • @creillyucla
      @creillyucla 3 ปีที่แล้ว +2

      what do you mean by test? If you want to check whether or not it is racemic (equal parts L and R), you can measure it's optical activity (whether or not it rotates polarized light)