Week 7 : MCNEMAR TEST

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  • เผยแพร่เมื่อ 12 ก.ย. 2024

ความคิดเห็น • 8

  • @bcr07pzu
    @bcr07pzu 10 ปีที่แล้ว +30

    thank you for the video. it would be more helpful if the null and alternative hyptheses and interpretation were clearly stated. everyone is using computers to do the maths now. its important we understand how it works but the most practical benefit would be explanation of the above.

  • @blackV199
    @blackV199 3 ปีที่แล้ว +4

    you sound like Al pacino.. great voice

  • @ia0o0ia
    @ia0o0ia ปีที่แล้ว +2

    I still couldn't figure out how to set up the 2x2 for McNemar's test, how do you get the number of pairs in each cell?

  • @Jackmc-du6el
    @Jackmc-du6el 8 ปีที่แล้ว +20

    The weird thing is my last name is McNemar

    • @nykytakudrya7741
      @nykytakudrya7741 4 ปีที่แล้ว +3

      @Haylee McNemar ur test is useful thanks

  • @meljonbisco567
    @meljonbisco567 4 ปีที่แล้ว +1

    Good afternoon. How did you get the result of 6.33 and 10.83?
    I'm just lost. Thank you.

    • @raterake
      @raterake 3 ปีที่แล้ว +2

      They are coming from the chisquare distribution. We would like to know what value of our test statistic produces a p-value of 0.01. The test statistic follows a chi-square distribution with degrees of freedom=1. So, if you look at a chi-square distribution with df=1, you will find that, when the value is 6.63, you get a p-value of 0.01 (you can use a computer to get this, or look it up on a table).
      Similarly, you will find that, when the value is 10.83, you get a p-value of 0.001.

    • @batlefieldproes
      @batlefieldproes 11 หลายเดือนก่อน

      because the value he got was for the test was 7.55 which if you look at the chi-square distribution table you cant find p value for it however the values 6.33 and 10.83 you can find and then what he has done is just took the middle p value of those two to estimate the p value for 7.55. if you have a calculator you just need the 7.55 value dont worry about the 6.33 and 10.83. He only did that cause the p value is going to be so small regardless .