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5(5^a) = 5^(a + 1) = 56 = 8 x 7(a + 1)log5 = 3log2 + log7a = [(3log2 + log7)/(log5)] - 1
5제곱a=56÷4=5제곱a=145*x×5*x=14X*x=14÷25=0.56X=루트0.56X=0.7485×0.748×5×0.748=14---------------------------=???????
a= log14 base 5
That’s all you need to know
Would it be necessarily to break log(14)base5 down like that in an exam or is it something you do to demonstrate how it could be written differently?
Sometimes easier to actually come to a number or then use to double check work but for an exam your instructor should let you know what they expect for an answer.
Frage und wie hilft das in Leben weiter ?? Kann man so Handwerkliche Leistungen umsetzen ?? Nein!!!
a=log(56/4)/log(5)
5(5^a) = 5^(a + 1) = 56 = 8 x 7
(a + 1)log5 = 3log2 + log7
a = [(3log2 + log7)/(log5)] - 1
5제곱a=56÷4=
5제곱a=14
5*x×5*x=14
X*x=14÷25=0.56
X=루트0.56
X=0.748
5×0.748×5×0.748=14
---------------------------
=???????
a= log14 base 5
That’s all you need to know
Would it be necessarily to break log(14)base5 down like that in an exam or is it something you do to demonstrate how it could be written differently?
Sometimes easier to actually come to a number or then use to double check work but for an exam your instructor should let you know what they expect for an answer.
Frage und wie hilft das in Leben weiter ?? Kann man so Handwerkliche Leistungen umsetzen ?? Nein!!!
a=log(56/4)/log(5)