Energy and Power Transmitted in Transverse Waves

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  • เผยแพร่เมื่อ 16 พ.ย. 2024

ความคิดเห็น • 8

  • @JosckyKoki
    @JosckyKoki 9 หลายเดือนก่อน

    Thanks ❤I really liked it

  • @petergoh5628
    @petergoh5628 ปีที่แล้ว +1

    Does this mean that if I want to find the total energy of the wave I just multiply the energy across one wavelength by the total number of wavelength that are formed across the length of the rope?

  • @ryanmiller7246
    @ryanmiller7246 10 หลายเดือนก่อน +1

    At what point in the wave does it have the most energy and at what point does it have the least?

    • @externalbehavior
      @externalbehavior 10 หลายเดือนก่อน +2

      KE, which depends on velocity (y direction) is highest near y=0 and is 0 at the amplitude (since velocity is 0)
      PE on the other hand, or to be more accurate EPE, is maximum at the amplitude, and 0 at the y=0.
      To conclude, near y=0 the particle (small portion of the rope) has KE > PE while near the amplitude the PE > KE.

    • @seemachoudhary4015
      @seemachoudhary4015 8 หลายเดือนก่อน

      But at y=A, dy/dx=0, so the EPE would be zero there too, right?

  • @jerven1128
    @jerven1128 ปีที่แล้ว

    can you integrate over the entire length of the string instead of just one wavelength to find the total energy stored in the string?

    • @PhysicsNinja
      @PhysicsNinja  ปีที่แล้ว +2

      Yes but if it extends to infinity you’ll run into problems.