Does this mean that if I want to find the total energy of the wave I just multiply the energy across one wavelength by the total number of wavelength that are formed across the length of the rope?
KE, which depends on velocity (y direction) is highest near y=0 and is 0 at the amplitude (since velocity is 0) PE on the other hand, or to be more accurate EPE, is maximum at the amplitude, and 0 at the y=0. To conclude, near y=0 the particle (small portion of the rope) has KE > PE while near the amplitude the PE > KE.
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Does this mean that if I want to find the total energy of the wave I just multiply the energy across one wavelength by the total number of wavelength that are formed across the length of the rope?
Yes
At what point in the wave does it have the most energy and at what point does it have the least?
KE, which depends on velocity (y direction) is highest near y=0 and is 0 at the amplitude (since velocity is 0)
PE on the other hand, or to be more accurate EPE, is maximum at the amplitude, and 0 at the y=0.
To conclude, near y=0 the particle (small portion of the rope) has KE > PE while near the amplitude the PE > KE.
But at y=A, dy/dx=0, so the EPE would be zero there too, right?
can you integrate over the entire length of the string instead of just one wavelength to find the total energy stored in the string?
Yes but if it extends to infinity you’ll run into problems.