Hello. Firstly great videos, it has really helped my understanding! Also, in composing relations example how can we have something that maps (2,1) and (2,2) if there is no relation in R1 that maps to 2? Thanks for clarification I may be missing something.
I went through R2 composed with R1 in the video. The answer is valid and I gave it in the video. R1 composed with R2 would be invalid because their sets don't match up. R2 maps to {0, 1, 2} and R1 maps from {1, 2, 3} so this would be invalid.
If neither of the original sets have the number 4, how can R have the tuple (4, 3)? In timestamp 11:34
Hello. Firstly great videos, it has really helped my understanding! Also, in composing relations example how can we have something that maps (2,1) and (2,2) if there is no relation in R1 that maps to 2? Thanks for clarification I may be missing something.
Thank you soooooooo much! You really are amazing at teaching... that's really rare to say. You saved me from my bad teach of DM!
Thank you for covering this book so well...
Will composing a relation (over a finite set) with itself always eventually yeild a fix-point?
Thank you very much, These videos are really useful, great presentation and pace
Thankyou so much it helped me for my DM exam
Essentially, would I be right to say that the R1 XOR R2 is the same as (R intersection R2)'
i.e (R1 intersection R2) all complement ???
you are lifesaver dude
Hello. Is there a video for 9.2 n-ary relations? Thank you!
You are a life saver!
Is there a video for 9.4?
thank you so much everything makes sense now
Question though I got a given of
{(1,1)(1,3)(2,3)(2,4)(3,1)}
How am i gonna map out (2,4)
Not a relation then. Maybe its a function but not a relation.
Thank you..☺
This videos will help me a lot.
Hi! This is also Rosen book??
Yes. Still the 7th edition.
@@SawFinMath@11:00 ma'am clarify here, the two sets are not same?
life saver!
thanks a lot great lessons from you!
Thank you 🤩
thank you so much .god bless
what is the answer for R2 o R1!!
and why the answer is invalid!!!
I went through R2 composed with R1 in the video. The answer is valid and I gave it in the video. R1 composed with R2 would be invalid because their sets don't match up. R2 maps to {0, 1, 2} and R1 maps from {1, 2, 3} so this would be invalid.
@@SawFinMath at 11:00 you composed the relation by itself but the first R maps to {0,1,2,3} and second R maps from {1,2,3}. The sets are not the same.
thanks alot maam god bless you
waytoodank
lil bros using twitch emotes on a discrete math video OMEGALUL
theres a mistake in R^2, R^3, and R^4, the last one shuld be (4,2)
Correct.