Solution - Given - 1) Mass = 💯 kg 2) Velocity= 2.5 m/s P (Momentum) = m (mass) × v (Velocity) = 💯 × 2.5 = 250 kg m/s Conservation of momentum of ball A is = Mass of A * initial velocity of. A = Mass of A * Final velocity of A
Mass(m) = 1000kg Velocity(v) = 2.5m/s Momentum(p) = mass(m)X velocity(v) =100kg X 2.5m/s My name is Mahesh. I am practise many times this chapter. Your explanation is great sir . Sir you explain diply.
Newton's fourth law of motion Every book continues to be in state of rest and covered with dust until and unless internal and external exam appears and the speed of page turning is directly proportional to the syllabus to be covered and tension in mind remain constant.😂😂😂
250 answer. Sir you have teach very legendary I can understand the topics of your video. You are very good teacher.I hope your channel will be billion of views and subscribe
Steps to get Notes, Sample paper, and Shout-out 1. Click on the link th-cam.com/channels/MIgfomhGEqdWVMAzU5i13w.htmljoin 2. Become a member 3. Go to the community tab on the TH-cam channel itself. There you will find a link to notes. Thanks and good luck 👍
Mass of stone is - 100 kg Stone thrown with velocity - 2.5 m/s Momentum = Mass x Velocity P = mv Now , 100 × 2.5 = 250 kg m/s Momentum = 250 kg m/s[where is my samosa]
Mass of stone is - 100 kg Stone thrown with velocity - 2.5 m/s Momentum = Mass x Velocity P = mv Now , 100 × 2.5 = 250 kg m/s Momentum = 250 kg m/s Sir I like samosa but Sir don't give me it .. Only Sir plzzzzz give me wishes that Aarya will definitely get good marks . Mare than 35 ..
Mass (m)=100kg
Velocity (v)=2.5m/s
Momentum (p)=(m) × (v)
=100kg ×2.5m/s
Momentum(p)= 250kg m/s
bhai samos mila?
Ultra ledgends are watching from van uncle's phone😂😂
Frrrr😂
final momentum - initial momentum
Therefore,80kg m/s - 20kg m/s =60 kg m/s
very good explanation!!
😊
Q. Find change in momentum
p1=20 kg m/s
p2=80 kg m/s
Change in momentum=mv(p2) - mu(p1)
=80 kg m/s - 20 kg m/s
=60 kg m/s
Third law of motion=karma😂
😂😂❤
Solution - Given - 1) Mass = 💯 kg
2) Velocity= 2.5 m/s
P (Momentum) = m (mass) × v (Velocity)
= 💯 × 2.5
= 250 kg m/s
Conservation of momentum of ball A is
= Mass of A * initial velocity of. A = Mass of A * Final velocity of A
bechara samosa nhi mila :(
Mass(m) =100kg
Velocity(v) =2.5m/s
Momentum(p) = mass × velocity
P=100kg x 2.5m/s
P=250kg m/s
🥇
😍😍❤
Initial velocity, (p1) = 20 kg m/s
Final velocity, (p2) = 80 kg m/s
Change in momentum = p2 - p1
= 80 kg m/s - 20 kg m/s
= 60 kg m/s
Sir samosa diya😂😂😂
Konsa samosa
@@bossgamer4699 are sir ne kaha tha ki agar koi bataega to mai use samosa dunga
Legends are watching one day before exam 🤣
one day before midterm exam🥲
One hour before exam😂😂
30 minute before exam😂😂
@@SunilChaudharyChaudhary-oe8uc I'm watching it one day before my half yearly , mid term exam !! 😂
Me
😂
11:39 Tap continuely
Mass - 100kg
Velocity - 2.5
P = m×v
= 100 × 2.5
=250 kg
Yes, conservation of momentum will happen if we see by the point of view of ball A .
Hence, solved 🎉.
Mass(m)=100kg
Velocity (v)=2.5m/s
P=ma
P=100×2.5
P=250kgm/s
Mass=100kg
Velocity=2.5m/s
Momentum(p)=Mass×Velocity
=100×2.5
=Momentum=250kg.m/s
Mass(m) = 1000kg
Velocity(v) = 2.5m/s
Momentum(p) = mass(m)X velocity(v)
=100kg X 2.5m/s
My name is Mahesh. I am practise many times this chapter. Your explanation is great sir . Sir you explain diply.
Mahesh dalle mass is 100kg not 1000kg
Mass(m) = 100kg
Final Velocity(v) = 2.5m
Momentum(p) = Mass*Velocity
= 100kg*2.5m/s
= 250kg/ms^-1
🎉🎉🎉
Therefore ,final momentum - initial momentum
Therefore,80kg m/s - 20kg m/s =60 kg m/s
*HW*
Given
Mass=100kg
Velocity=2.5m/s
P=mv
P=100kg×2.5m/s
*P=250kgm/s*
Please give me my samosa 😝
Mass(m)= 100kg
Velocity(v)= 2.5m/s
Momentum (p)= mass(m)× velocity(v)
p= 100kg × 2.5m/s
p= 250 kg m/s
14:25 ans is 2500 kg m/s
15:19 answer hai 250.0 m/s
Give me my reward samosa 💥
Mass-Denoted by (m)=100
Velociy-Denoted by (v)=2.5m/s
Ans---Momentum-Denoted by (p)=mass(m)×velocity(v)
=100kg×2.5m/s
Momentum(p) =250kg m/s
He is best teacher on TH-cam 😊😊. Love your teaching bro
Hey guys who are watching this video before one day at night to complete all chapter ❤😂😂
Mass=100kg
Velocity=2.5m/s
P=250kg m/s
Sir Mere nub sci mein 0/80 ata the per ab 73/80 ata h thanks. Manuu kaa gya. ❤ 🙏🏻
Z🥪🥖🥪
Mass (m) = 100 kg
Velocity (v) = 2.5 m/s
Momentum (p) = Mass (m) x Velocity (v)
= 100 kg x 2.5 m/s
Momentum (p) = 250 kg m/s
Hence Solved
💯
P=m+v
M-100g
V- 2.5m/s
100kg×2.5m/s = 250kg m/s
Mass-100kg
Velocity-2.5m/s
Momentum-mass / velocity
100kg/2.5m/s
Momentum -250.0kg m/s
15:14
m = 100kg
v = 2.5 m/s
p = m × v
= 100kg × 2.5 m/s
p = 250kg m/s
(m)=100kg
(v) = 2.5m-s
P=mv
P= (100) * (2.5)
= 250kgm-s Ans.
15:15 Momentum = 250kg m/s
🍕🍕🥪 moj kar beta
Mass (m) - 100kg
Velocity (v) - 2.5 m/s
Momentum (p) - mass(m) × velocity (v)
momentum (p) - 100kg × 2.5 m/s
momentum (p) - 250 kg m/s
Mass (m) - 100 kg
Velocity (v) - 2.5 m/s
So, Momentum (p) = Mass (m)× Velocity (v)
= 100 × 2.5 m/s
P = 250 kg m/s
Newton's fourth law of motion Every book continues to be in state of rest and covered with dust until and unless internal and external exam appears and the speed of page turning is directly proportional to the syllabus to be covered and tension in mind remain constant.😂😂😂
Nooo
Tension in mind increases with uniform acceleration 😂😂
Mass=100kg
Velocity=2.5m/s
P=MV
100kgx2.5ms
P=250kg m/s
14:55
P1=20
P2=80
P1-p2=80-20
=60kg/ms
Given : m = 100 kg
v =2.5 m/s
To find =p
Solution=p=m×v
100 ×2•5 = 250 kg m/s
Good explanation you are the best from my coaching teacher and school👍👍
Mass-100kg
Velocity -2.5m/s
P=mv
=100kg×2.5m/s
=100×25÷10
=250kg.m/s
Mass =100kg
Velocity=2.5m/s
Mumatum=?
P=mv
100×2.5
=2500 kg/ms
Wrong
It is 250 kg/ms, wrong calculation.
Why@@xtrokily
Mass 💯
Velocity 2.5m/s
P(momentum) = mass ×velocity
P=100×2.5
250kg m/s
M=100 kg
V=2.5 m/s
P=M×V
100×2.5
100×25÷100
ANSWER IS 250
Ans =] *250 Kg m/s* , I did the calculations in my head🙂
250 answer. Sir you have teach very legendary I can understand the topics of your video. You are very good teacher.I hope your channel will be billion of views and subscribe
All the best for today exam ❤️❤️ 2023
Mass =100kg
Velocity =2.5m/s
Momentum =mass×Velocity
P= 100kg ×2.5m/s
P=250kgmls
2:50 was personal
Final momentum is 60kg m/s amd momentum is 250
Sir monentum is 250kg m/s and i an your student Aryan Jaiswal Of Happy Model School
Location
Uuuu😮
@@prabhnoorsingh1294
Change in momentum = final momentum - initial momentum = 80-20 = 60
p=mv
p=2.5*100
=250kg m/s
change in momentum= p1-p2
= 80-20
=60kg m/s
P¹20 kg m/s
P2 80 kg m/s
Mu -mv
80-20 answer 60
Mass(m)=100kg
Velocity (v)=2.5m/s
Momentum (p)mass(m) velocity (v)
100kg×2.5m/s
Momentum (p)=250 kg m/s
Mass = 100
Velocity=2.5
P=mv
So,100×2.5
ANSWER=250kg ms
😱😱
250.0 kg m per sec
Mass 100 velocity 2.5 momentum p=250 ans
nitial velocity, (p1) = 20 kg m/s
Final velocity, (p2) = 80 kg m/s
Change in momentum = p2 - p1
= 80 kg m/s - 20 kg m/s
= 60 kg m/s
this is answer
Nitial
Nahi
Initial
@@kashish_creation551yea😂
Final momentum = 60 kg m/s
Hence solved 😊
2:50 i will also do this
Mannu bhaiya how to take membership for ur channel because I want to take it in my 10th class
Steps to get Notes, Sample paper, and Shout-out
1. Click on the link th-cam.com/channels/MIgfomhGEqdWVMAzU5i13w.htmljoin
2. Become a member
3. Go to the community tab on the TH-cam channel itself. There you will find a link to notes.
Thanks and good luck 👍
1) p=mv
100×2.5
=250
P=250
Q1
Ans. 250kg m/s
sir your explenation is very good
And sir change in momentum =final momentum - Initial momentum = 60 kg m/s
Ans = 250.0
P=250kg m/s
Mass into velocity =100×2.5= 250
Best explanation sir 👏
P=MV
=100×2.5
so momentum =250 kg m/s
14:52 sir. The answer is:-
M=100
V=2.5
[Formula]:-Momentum=mass×velocity
P=250kg.m/s
Sir answer to de diya lekin samose ka kya 🥺
ok
@@thinkbig.03 bhai sir ne samosa nahi diya 🥺
@@aniketsharmamusic692 koi ni 😊broooo
Mera samosa 😭
@@aniketsharmamusic692 🤣
MANJU, CHANGU OP♠️
M=100kg
V=2.5m/s
P=?
So, p=m*v
P=100kg*2.5m/s
Hence the momentum =250kg-m/s
250 kg mper second
Mass of stone is - 100 kg
Stone thrown with velocity - 2.5 m/s
Momentum = Mass x Velocity
P = mv
Now ,
100 × 2.5 = 250 kg m/s
Momentum = 250 kg m/s[where is my samosa]
Maa kasm kl annual paper h or aj raat ko sare chapter padh lunga 20 ya 40 min ke revision charo tarf se Patti padi h bhai 😅😅
Ans:
Momentum(p)=250kg m/s
15:25 250kgm/s
Mass of stone is - 100 kg
Stone thrown with velocity - 2.5 m/s
Momentum = Mass x Velocity
P = mv
Now ,
100 × 2.5 = 250 kg m/s
Momentum = 250 kg m/s
Sir I like samosa but Sir don't give me it .. Only Sir plzzzzz give me wishes that Aarya will definitely get good marks . Mare than 35 ..
P=MV
=› P= 100kg × 2.5 m/s
=› P= 250 Kg-m/s
So, Momentum is 250 Kg-m/s
Did really give us samosa 😅
15:26
15:20 answer = 250 N
I couldn't got samosa
😂😂😂😂😂
answer 250
15:33 momentum=250
Ans = 250 kg m/s
250 m/s sol likha h kyu ki 11 bhaj gye kal mera science ka paper hai
Change in momentum = Final momentum -- Initial momentum
P1=20kgm-s
P2=80kgm-s
Change in momentum= 80-20
= 60kgm-s Ans.
80-20. 60kgm/s
🎉
Thank u sir! 😊
Who are watching one day before exam comment 👇
Mass(m) =100kg
Velocity(v) =2.5m/s
Momentum(p) = mass × velocity
P=100kg x 2.5m/s
P=250kg m/s
WHERE IS MY SAMOSA ? 😋😋
I am the big fan of mannu sir❤🎉
17:45 60 kg m/s
Answer is 250.0
Mass of stone = 100 kg
Velocity=2.5m/s
P=mass×velocity
P=100kg×2.5m/s
=250kg m/s .answer 👍
250 kg m/s
Sir 250 kg m/s by multiplying. M and v
15:19 - Answer is 250.0 Kg m/s - Give me my samosa 😆 😆
13:46 80 ms-1
Mass = 100 kg
Velocity = 2.5 m/s
Momentum = mass × velocity
= 100 kg × 2.5 m/s
= 250 kg m/s
THANKS TODAY IS MY EXAM😅😊
Which school?
@@BoraNikita dehra public inter college
How'd it go