You deserve a raise! This is single handedly saving me in my advanced E&M class at UIUC. You explain these concepts so much more succinctly in ten minutes than my professors would in an hour.
Hello, thanks again for your excellent videos. at the point that you explained that there was 0v across the resistor (0 seconds) and -12v across the inductor. please consider adding annotations that show the voltages at different points in the circuit. i know for me that method of demonstration helped allot and it could be useful to your viewers
Try labeling the ends of each resistor with letters... To represent voltage at them... Call 2 resistors parallel only if both ends are at same voltage...
Would there be a current through the inductor in the first example since you stated that the current of the whole circuit is zero. If there is a current how would I find it?
Right after the switch is closed there would be NO current (I = 0A) in any part of the circuit. Then the current through the circuit increases overt time until it reaches its maximum. The maximum current can be found using Ohms law, V = I x R or I = V / R. So the maximum current would be 12 / 10K or 1.2 mA.
@@stepbystepscience Why is there no current? If the switch is closed. Then its just a normal series circuit is it not? I'm still a beginner sorry if this is a dumb question.
When the switch is first closed the inductor acts like an open circuit, after a specific amount of time it acts like a short circuit. The opposite of a capacitor. Does that help?
Since the current right after the switch is closed is 0, wouldn't there have to be a rate of change of current, to get an induced emf across the inductor? And would this be the time where the current is changing at the maximum rate?
The order of the resistors and inductor does not matter, the voltages and current would be the same. There is 0 V across the inductor because after a long time it is no longer resisting the changing increasing current. After a long time the inductor acts just like a wire and wires have no resistance. Does that help?
Right after the switch is closed there is 12 V across the inductor as it trys to resist the change in current. And the voltage across the resistor is 0 V. Then over time the voltage across the inductor decreases and the voltage across the resistor decreases. Does that help?
@@lollolzi2996 since the current is zero at t = 0 s, we can say that there is no current at all. It doesn't matter if we say it is about to get going or it is going with intensity zero. It's the same. What appears to be confusing to you is the fact with have voltage across the inductor with no current. Take a simpler example: remove the inductor. What's the voltage between ground and the unconnected leg of the resistor? It's also 12 V. There's no voltage drop over the resistor because there's no current flowing.
@flightlesssky note the battery polarity at 0 seconds (top is positive bottom is negative) note that negative of battery is connected to inductor by a wire. this means bottom of inductor is 'tied' to the negative of battery. negative of battery is 0v so bottom of inductor must be 0v. assuming you also understand why the top of the inductor is at 12v the following analogy should help. ( if you don't then ask and someone will help ) imagine 2 batteries with the pos of the first connected to the neg of the second. there polarities are the same. imagine then if you turn one around so that both the negatives are touching. they would now have opposite polarities. hope this helps and please comment i am wrong
the voltage across it, not through it ( the difference in voltage across the terminals) . this might help also: when a capacitor is charged we can call this point time = infinity (after a long time) however with an inductor, at the same point in time (infinity / after a long time) the current will be at I max (the maximum possible current in the circuit which is determined by the voltage of the battery x the resistance of the resistor)
I'm new to this myself but I'm thinking that because at t=0 the back voltage would be at it's highest at -12v. minus meaning the opposition of current. 12 because t=0 so the rate of change across the inductor is the highest rate. Am i close? I don't know
my university is so weird they use GL instead of RL, with G as conductance (Siemens)... making everything harder like there is no use using G.... the G is connected in parallel to the circuit, and the voltage source is replaced by a current source (Norton equivalent circuit).
You deserve a raise! This is single handedly saving me in my advanced E&M class at UIUC. You explain these concepts so much more succinctly in ten minutes than my professors would in an hour.
Thank you, I am glad that you find the videos helpful. Hope your studies go well.
Sir,
This is what I call circuit analysis! You have made it so clear to me. I have to see more of your videos. Thank you, thank you, thank you.
Excellent, great that you found the video helpful. Thanks for the comment.
Exams soon and I missed RC and RL classes due to sickness. You sir, are my saviour. Very neat explanation. :) Amazing job!
Thanks for the comment and I hope the exams got well.
Hello, thanks again for your excellent videos. at the point that you explained that there was 0v across the resistor (0 seconds) and -12v across the inductor. please consider adding annotations that show the voltages at different points in the circuit. i know for me that method of demonstration helped allot and it could be useful to your viewers
are you essentially looking at the circuit in dc steady state when is t=infinity?
yes
love the way you are explaining. you made it so clear. subscribed your channel. thank you so much
Thanks and welcome to the channel!
Great video and great explanations! You really helped me understand how capacitors and inductors work!! :)
Great to hear and thanks for watching!
That is the talented teacher. Thank you very much
Thanks for the comment. I love to teach!
Sir you making me topper STEP BY STEP.
Sir l like your way of teaching you did your best thanks
So nice of you to say so.
Is this an oscillatory electrical circuit?
This video is for direct current, not alternating current.
@@stepbystepscience Do you have videos on oscillatory electrical circuits?
you're star keep shining sir, God bless tou
are the resistors at 8:40 not in parallel?
No, they can not be in parallel, everything is in series. There is only one path for the current.
Try labeling the ends of each resistor with letters... To represent voltage at them...
Call 2 resistors parallel only if both ends are at same voltage...
i wish i found your channel earlier cause my life would be so much easier. thank you!
You are so welcome! Better late than never.
Well done sir
thanks so much
Would there be a current through the inductor in the first example since you stated that the current of the whole circuit is zero. If there is a current how would I find it?
Right after the switch is closed there would be NO current (I = 0A) in any part of the circuit. Then the current through the circuit increases overt time until it reaches its maximum. The maximum current can be found using Ohms law, V = I x R or I = V / R. So the maximum current would be 12 / 10K or 1.2 mA.
@@stepbystepscience Why is there no current? If the switch is closed. Then its just a normal series circuit is it not? I'm still a beginner sorry if this is a dumb question.
when the switch is closed , won't the inductor behaves as short circuit ?
When the switch is first closed the inductor acts like an open circuit, after a specific amount of time it acts like a short circuit. The opposite of a capacitor. Does that help?
Lenz's Law my dude.
Absolutely brilliant video!
Thanks for the comment
Since the current right after the switch is closed is 0, wouldn't there have to be a rate of change of current, to get an induced emf across the inductor? And would this be the time where the current is changing at the maximum rate?
I don't get why there is 0V across the inductor if there is 9V across the 3ohm resistor even though it is after the inductor?
The order of the resistors and inductor does not matter, the voltages and current would be the same. There is 0 V across the inductor because after a long time it is no longer resisting the changing increasing current. After a long time the inductor acts just like a wire and wires have no resistance. Does that help?
voltage = current x resistance OR V = I x R OR 0 volts = 0 amps x 3 ohms (across the inductor)
Wait a second, if there is no current in the circuit how can there be voltage across the inductor?
Right after the switch is closed there is 12 V across the inductor as it trys to resist the change in current. And the voltage across the resistor is 0 V. Then over time the voltage across the inductor decreases and the voltage across the resistor decreases. Does that help?
@@stepbystepscienceAlmost. When the switch is closed at t=0 are we assuming that the current is running or JUST about to start going?
@@lollolzi2996 since the current is zero at t = 0 s, we can say that there is no current at all. It doesn't matter if we say it is about to get going or it is going with intensity zero. It's the same. What appears to be confusing to you is the fact with have voltage across the inductor with no current. Take a simpler example: remove the inductor. What's the voltage between ground and the unconnected leg of the resistor? It's also 12 V. There's no voltage drop over the resistor because there's no current flowing.
I don't understand why the voltage across the inductor at t=0 is of negative polarity. Can you elaborate on that?
flightlesssky Because there is no Current flights owing through the Circuit.
I still don't get it, in the case of the capacitor when it's done charging there's no current flowing either yet the voltage through it is positive.
@flightlesssky note the battery polarity at 0 seconds (top is positive bottom is negative) note that negative of battery is connected to inductor by a wire. this means bottom of inductor is 'tied' to the negative of battery. negative of battery is 0v so bottom of inductor must be 0v. assuming you also understand why the top of the inductor is at 12v the following analogy should help. ( if you don't then ask and someone will help ) imagine 2 batteries with the pos of the first connected to the neg of the second. there polarities are the same. imagine then if you turn one around so that both the negatives are touching. they would now have opposite polarities.
hope this helps and please comment i am wrong
the voltage across it, not through it ( the difference in voltage across the terminals) . this might help also: when a capacitor is charged we can call this point time = infinity (after a long time) however with an inductor, at the same point in time (infinity / after a long time) the current will be at I max (the maximum possible current in the circuit which is determined by the voltage of the battery x the resistance of the resistor)
I'm new to this myself but I'm thinking that because at t=0 the back voltage would be at it's highest at -12v. minus meaning the opposition of current. 12 because t=0 so the rate of change across the inductor is the highest rate. Am i close? I don't know
Sir make a video on some complex RL circuit problems
OK, do you have an example.
@@stepbystepscience sir there is an app named HC Verma Physics textbook in the playstore u will get a lot of tough problems from RL circuit problems.
Thankyou so much for the great explanation..
Thank you so much!!! You explain it so well!
Glad it was helpful! You're very welcome.
Thank u for helping me out May the good God bless u
Thanks for the great comment.
you saved my life 😂!!! thank you very much
great video
Thanks, glad you liked it!
thank you sir, it is helpful
You are most welcome
you are the best. this was really helpful.
Very nice of you to say, thanks for watching and commenting.
my university is so weird they use GL instead of RL, with G as conductance (Siemens)... making everything harder like there is no use using G.... the G is connected in parallel to the circuit, and the voltage source is replaced by a current source (Norton equivalent circuit).
Yes, that seems weird...
Just what I needed. Thank you! Subscribing. 😊👍🏻😊
Thank you very much for everything, watching, commenting and subscribing.
Thank you sir 😃😃😃😃😃
You are very welcome
Sound is so low
Turn up the volume
@@stepbystepscience ok sir
This is fantastic.
Is that a typo or did your really mean funtastic, either way thanks for be the first to comment on my latest video.
Step-by-Step Science typo haha, thanks for telling me :)
Very helpful
Thanks for saying so!
thx
U R Welcome!
Thanks
You are very welcome!
Bravo !
Thanks!
Speak loudly
Thanks sir
Very low volume man....
Awesome!!!!!!!
Thanksssssssssss (:
Welcome
Ma fhemet
SLOW DOWN. You're reading like it's you and your friend who are talking and already know everything....too fast
Sorry, I try to strike a balance for those who prefer different paces.