RL circuit analysis for determining the voltage and current in the circuit. You can see a listing of all my videos at my website, www.stepbystepscience.com
@@stepbystepscience Thank you so much. One request : Please use different value of resistors or components in your othef examples. As when you are trying to show them with the black background, it is just difficult to follow. Otherwise excellent explanation. Thank you for all your help and efforts.
Sir, I can't thank you enough for all these wonderful videos and your step by step explanations in all your videos. I have learned so much from you and may God reward you abundantly for making student's life easier.
Relays for starter motors and other high energy devices often contain a parallel resistor or diode, to quickly bleed off the backwards charge that is generated when the coil inside the relay is abruptly turned off. This nicely shows how those devices work, protecting upstream electronics from spikes in current flow, and immediately resetting the relay to zero potential so it is ready for use again.
Great information, Im not quite up to your speed. If It is possible, and if you haven't already done it, is it a possibility you could use a different color/size cursor? a larger one perhaps. Just though it might be easier to follow. Love the content. Thank you for putting your time into it!!!
After the switch has been closed for a long time the inductor is no longer resisting the change in current because the current is not changing anymore. Therefore each branch really just consists of one 8 ohm resistor. ( and each branch has the same resistance) If there is 3 A of current coming out of the battery then the 3 A of current is split evenly between each of the branches. 3 divided by 2 = 1.5 A of current for each branch/resistor. Does that help?
These amounts seem a bit high for a normal circuit. If you're doing this on a breadboard or something, you'd need to have 16 AA or AAA batteries in series to generate 24V DC, then if you have a resistor that's 8 ohms with 16 V and 2 amps, then it'd dissipate 2(16) = 32W of power. This is a lot for standard resistors to take. The most common ones I found at a normal price for use in breadboards (generally with axial leads, smd/smt ones would be even less) are rated at about 500 mW, 3W and 5W so both of these resistors would quickly get burnt out by this.
Jonathan McVinnie this is an explanatory video on how RL circuits work, so using simple numbers is not only easier but also makes everything more clear. I’m sure he knows about which numbers would be more applicable to the real world.
I have understood better here than in any other videos else where. Thank you very much.
Thanks for the great comment
@@stepbystepscience
Thank you so much.
One request :
Please use different value of resistors or components in your othef examples.
As when you are trying to show them with the black background, it is just difficult to follow. Otherwise excellent explanation. Thank you for all your help and efforts.
I've been watching videos on RL circuits and this is the first one that truly helped me understand the concept, thank you so much
You're very welcome and thanks for the comment.
Sir, I can't thank you enough for all these wonderful videos and your step by step explanations in all your videos. I have learned so much from you and may God reward you abundantly for making student's life easier.
You are very welcome, thanks for watching and taking the time to write such a nice comment.
I have my Electricity and Magnetism test tomorrow and these videos on RL circuits have been extremely helpful!
Hope the test went well!
How did you do?
Very profound with clear and explicit explainations,thanks a lot
You are most welcome!
This actually was really helpful. Thanks!
This is ABSOLUTELY amazing! Thank you! It is very intuitive and visual
You're very welcome! Thanks for the positive feedback.
Thanks man. Everything for RC and RL have been excellent so far.
Great and thank you very much for watching and commenting.
I like very much how you make us stop and think like this! Superb teacher! Thanks!
Yes, with these problems you need to do a little thinking first. You are very welcome and thanks for commenting.
Thank you so much! inductors have always been a trouble for me. You really helped clear things up a lot!
Great to hear! Thanks for the comment.
The first channel, in which all videos are truly helpful and explained in an accessible language for students!!
Thank you very much for the very nice comment.
Nice to know that 24V will appear at the inductor right away after battery is off ! Thanks !
that is extremely helpful!
thank you
Relays for starter motors and other high energy devices often contain a parallel resistor or diode, to quickly bleed off the backwards charge that is generated when the coil inside the relay is abruptly turned off. This nicely shows how those devices work, protecting upstream electronics from spikes in current flow, and immediately resetting the relay to zero potential so it is ready for use again.
sir pleaSe tell me..how after 4 ohm resistor the 24 voltage to be 16 volt
Sir, is there any concept of flux remaining constant before and after closing switch. Can, you please explain it.
Great explanation and animation! Thank you!
You're very welcome!
Very helpful sir thank you very much please give ur some questions at end the video just like u did in last video
Extremely helpful
Thanks, you can see a listing of all my videos at my website.....www.stepbystepscience.com
Love you videos man.
Huge help keep up the great work
Thank you very much for the comment.
It really helps me a lot, thank you,sir.
Most welcome and thanks for commenting
How come the equilibrium resistance isn't 8? The two 8's are in parallel so you add those to the 4
Crystal clear explanation.. thankyou for your effort
You are very welcome, thanks for the great comment
Awesome video. Helped me a lot, thanks! :)
Glad that it did. Thanks for watching and commenting.
Thank you very much. Great tutorial!
You are very welcome, thanks for watching and commenting.
Fabulous explanation!
Glad you think so!
Thank you. I got A in my exam because of your video :)
I am glad that you did...You can see a listing of al my videos at www.stepbystepscience.com
Really good explanation!
Glad it was helpful!
Super helpful thanks!
You are very welcome.
Great Video!
Thank you very much for the comment
THANK YOU
Thanks, Very helpful
Glad it was helpful!
what a great human thanks
Nice of you to say.
Step-by-Step Science thanks a lot man I got a good score thanks
Good work
Thank you so much !
Great information, Im not quite up to your speed. If It is possible, and if you haven't already done it, is it a possibility you could use a different color/size cursor? a larger one perhaps. Just though it might be easier to follow. Love the content. Thank you for putting your time into it!!!
I will look into it.
How did you get 1.5 A on IL8 and I8? didn't understand that.
After the switch has been closed for a long time the inductor is no longer resisting the change in current because the current is not changing anymore. Therefore each branch really just consists of one 8 ohm resistor. ( and each branch has the same resistance) If there is 3 A of current coming out of the battery then the 3 A of current is split evenly between each of the branches. 3 divided by 2 = 1.5 A of current for each branch/resistor. Does that help?
thank you very much sir
No problem, glad that you found the video helpful.
Very helpful
thanks alot
You're very welcome
Thank u❤❤❤❤❤❤❤
Thanks
You are very welcome again!
Thank you very much sir.
But make a playlist of the 8 video.
Thanks, but the video is already part of a playlist.
So is t = infinity the same as t > 0
Probably most of the time unless you are being ask to calculate something, current or voltage, at a particular time.
Now i know,thanks bro
Great.
Now what if i close again
😊
thanks
These amounts seem a bit high for a normal circuit. If you're doing this on a breadboard or something, you'd need to have 16 AA or AAA batteries in series to generate 24V DC, then if you have a resistor that's 8 ohms with 16 V and 2 amps, then it'd dissipate 2(16) = 32W of power. This is a lot for standard resistors to take. The most common ones I found at a normal price for use in breadboards (generally with axial leads, smd/smt ones would be even less) are rated at about 500 mW, 3W and 5W so both of these resistors would quickly get burnt out by this.
Jonathan McVinnie this is an explanatory video on how RL circuits work, so using simple numbers is not only easier but also makes everything more clear. I’m sure he knows about which numbers would be more applicable to the real world.
He's explaining how it works. Fuck off
The equivalent resistance between the two 8s is 1/4 because for parallel resistors the eq. resistance is 1/R + 1/R,
the equivalent resistance between two 8s is 4 because 1/R(equiv) = 1/R + 1/R. Is is not R(equiv) = 1/R +1/R.
hocam thx hintlileri dinlemekten gına gelmişti valla