Ok, so you realise that the velocity is only maximum when the position is 0.... and it is 0 when the position is maximum. So you already got 4 points in the graph. From the given options, it can only be circular or elliptical right? Now, you realise that the maximum velocity and amplitude cannot be the same... Why? Because vmax = Aw which means they differ by a constant w. This must means circular is not possible. By elimination, elliptical is correct.
Let's say the equation of SHM is x=Asinωt . Then v=Aωcosωt ,we know that v²=ω²(A²-x²) by trig identities ,on rearranging we get the eq, is this a right way to do this?
Great way to solve it! I wanted to ask you if you have looked at my paper or if I sent it to someone who was imposing as you. I had on another TH-cam channel a scammer who tried to fool me and I’m hoping I didn’t fall for it here. Thanks for your time.
@@MichelvanBiezen I just wanted to make sure. I do have a change for one of the equations that is pretty significant. I’ll wait to see your reply. Hopefully you weren’t to hard on me. Thank You!
@@MichelvanBiezen SIR THERE IS A VERY AMAZING BOOK PATHFINDER FOR PHYSICS OLYMPIAD AND JEE ADVANCE PHYSICS U CAN EASILY FIND ITS SOFT COPY ON INTERNET....i was saying plz upload its solutions means 6-7 questions per chapter as they are really challenging
wow Michel.. that video was PERFECT from Start To Finish!! I love relearning this Physics, especially when you present it in such a Clear Cut Fashion!! I hope your summer went well. All is good in Michigan.. Thanks for all your time and efforts in creating these Videos.
Can someone explain the 1st method to me. I didn’t get how you concluded that it would be an ellipse by looking at that equation
Ok, so you realise that the velocity is only maximum when the position is 0.... and it is 0 when the position is maximum. So you already got 4 points in the graph. From the given options, it can only be circular or elliptical right? Now, you realise that the maximum velocity and amplitude cannot be the same... Why? Because vmax = Aw which means they differ by a constant w. This must means circular is not possible. By elimination, elliptical is correct.
Let's say the equation of SHM is x=Asinωt .
Then v=Aωcosωt ,we know that v²=ω²(A²-x²) by trig identities ,on rearranging we get the eq, is this a right way to do this?
That is definitely one way
Thank you sir for this solution
DIVINE
Great way to solve it!
I wanted to ask you if you have looked at my paper or if I sent it to someone who was imposing as you. I had on another TH-cam channel a scammer who tried to fool me and I’m hoping I didn’t fall for it here. Thanks for your time.
Scott,
Yes, I have read your paper and it was an interesting read.
@@MichelvanBiezen I just wanted to make sure. I do have a change for one of the equations that is pretty significant. I’ll wait to see your reply. Hopefully you weren’t to hard on me. Thank You!
Best teacher ☺️☺️
You are brilliant 💙💙❤️❤️
Thank you! 😃
👍Thank You🙏
Welcome 👍
amazing
Thank you! Cheers!
@@MichelvanBiezen SIR THERE IS A VERY AMAZING BOOK PATHFINDER FOR PHYSICS OLYMPIAD AND JEE ADVANCE PHYSICS U CAN EASILY FIND ITS SOFT COPY ON INTERNET....i was saying plz upload its solutions means 6-7 questions per chapter as they are really challenging
wow Michel.. that video was PERFECT from Start To Finish!! I love relearning this Physics, especially when you present it in such a Clear Cut Fashion!! I hope your summer went well. All is good in Michigan.. Thanks for all your time and efforts in creating these Videos.
Hi Philip. Good to hear from you. Yes, our summer was good as well. Tomorrow, our second oldest son is getting married. Looking forward to tomorrow.
❤❤🙏🙏❤❤❤❤
So easy I did it in my sleep