15.2. NS Example 2 - Combined Poiseuille Couette Flow

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  • เผยแพร่เมื่อ 15 ม.ค. 2025

ความคิดเห็น • 3

  • @ShuffleJosh
    @ShuffleJosh 5 ปีที่แล้ว

    Hi Tony,
    I'm confused as to why when you take the step from u to u* the "yh"-term turns into "h^2". Any chance you could clue me in on whats happening there? Many thanks in advance.

    • @ShuffleJosh
      @ShuffleJosh 4 ปีที่แล้ว

      ​@@ProfessorSaadExplains at 5:07 your have u(y)=(1/mu)(dp/dx)(y^2-hy)+(Uw/h)y ; you then develop u* as u(y)/Uw and conclude at 5:29 u*=u(y)/Uw=y/h (moved from the back of previous equation) +(1/mu)(dp/dx)(1/Uw)

    • @Jono.
      @Jono. 4 ปีที่แล้ว +1

      @@ShuffleJosh I found the same. I believe this is simply a mistake copying from one page to the next. it should be (*)[y^2 - hy]
      and simplifies in the end to u* = eta + alpha(eta^2 - eta)