Clever to detect the 28 pairs in R3 as that information yielded the 2 in C9; many digits were then located throughout the grid! Excellent solve and have a nice day!
Took me a while but finding the naked single 8 in col 6 helped. I absolutely missed the 18 pair in the bottom row which would have disambiguated the 69 pair in box 8. Enjoyed your solve as always!
... par (3,8) en 5a fila dentro del Sector 5; tercia (1,2,4) en dicha fila ent (5,2)=2 (5,7)=1 (5,9)=4 (8,8)=4 (9,8)=1; tercia (2,5,6) en el Sector 6; (9,4)=8 (5,4)=3 (5,5)=8; cuat (1,3,5,7) en 5a col; tercia (4,6,8) en el Sector 4; tercia (3,5,6) en 9a fila; par (6,9) en 4a col dentro del Sector 8 ent (8,5)=1 (6,4)=1; par (3,5) en 6a col dentro del Sector 8; (1,5)=3 (6,5)=5 (4,5)=7; par (2,4) en el Sector 5; cuat (5,6,7,8) en 7a col; cuat (2,4,5,7) en 4a col; tercia (3,5,6) en 2a col ent (1,2)=5 (2,2)=3 (3,2)=6; par (2,8) en 3a fila; par (2,8) en 3a fila quedando la tercia (3,5,7). Para desbloquearlo hice un Tanteo por Combinaciones: Si en (9,1)=6 con (3,6)=2 se obtiene un Error! en fila 6 ya que se duplica el #4 y luego la combinación (9,1)=6 con (3,6)=8 se llega a un Error! se duplica el #2 en 3ra col, Por lo tanto en (9,1)=3...
Clever to detect the 28 pairs in R3 as that information yielded the 2 in C9; many digits were then located throughout the grid! Excellent solve and have a nice day!
Thank you, you too
Took me a while but finding the naked single 8 in col 6 helped. I absolutely missed the 18 pair in the bottom row which would have disambiguated the 69 pair in box 8. Enjoyed your solve as always!
Catching up again. One slightly tricky step (31 = row 3 column 1):
31, 53, 57, 59, 52,
62, 88, 98, 94, 55,
54, 15, 85, 64, 45,
65, 32, 22, 12, 49 (hidden pair in row 3),
66, 44, 26, 48, 68,
36, 33, 81, 61, 13,
43, 41, 93, 83, 76,
86, 99, 91, 71, 27,
34, 14, 24, 18, 28,
11, 21, 17, 78, 38,
39, 87, 77, 84, 74,
89, 79.
Very very hard
... par (3,8) en 5a fila dentro del Sector 5; tercia (1,2,4) en dicha fila ent (5,2)=2 (5,7)=1 (5,9)=4 (8,8)=4 (9,8)=1; tercia (2,5,6) en el Sector 6; (9,4)=8 (5,4)=3 (5,5)=8; cuat (1,3,5,7) en 5a col; tercia (4,6,8) en el Sector 4; tercia (3,5,6) en 9a fila; par (6,9) en 4a col dentro del Sector 8 ent (8,5)=1 (6,4)=1; par (3,5) en 6a col dentro del Sector 8; (1,5)=3 (6,5)=5 (4,5)=7; par (2,4) en el Sector 5; cuat (5,6,7,8) en 7a col; cuat (2,4,5,7) en 4a col; tercia (3,5,6) en 2a col ent (1,2)=5 (2,2)=3 (3,2)=6; par (2,8) en 3a fila; par (2,8) en 3a fila quedando la tercia (3,5,7). Para desbloquearlo hice un Tanteo por Combinaciones: Si en (9,1)=6 con (3,6)=2 se obtiene un Error! en fila 6 ya que se duplica el #4 y luego la combinación (9,1)=6 con (3,6)=8 se llega a un Error! se duplica el #2 en 3ra col, Por lo tanto en (9,1)=3...