ANALYSIS OF A TRUSS USING THE METHOD OF JOINTS|FRAME ANALYSIS.

[@tuterruyi5178]

In simpler step:
Take every joint individually isolated.
Take From joint whose resultant (force) is known and take sum of all moments from this joint m=f*d or when it is not perpendicular take m=f*dcos*tita in x axis or m=d
F*dsin*tita in y axis, where moment direction of force is clockwise then + or if in anticlockwise then -. 0= sum of total moments( 0= m1+m2...).
Cause of it we get other resultants whose value where unknown till now.
Make free body diagram of which joint you are using, take value of 0=sum of x axis forces( if force direction is not in perpendicular use f*cos*tita) and 0= sum of y axis forces( here use f*sin*tita if force direction is not perpendicular).
Here if resultant force value is minus than it is compress and if it is positive than it is tense. Use it on every joint to find force values.
Joint are usually use in truss where external force are commonly in perpendicular. Unlike in this triangular, value of forces either + or - is decided by tense and compress of a 'member' when suming them according to their x axis and y axis. Where force direction toward joint is - and + in outward the force.

[@georgekamiti6538]

Alright Sir.

[@DanielEdwinsson]

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[@georgekamiti6538]

Thank you Sir for your support.

[@DorcaKemuma-v3x]

Thanks a lot sir

[@georgekamiti6538]

You are much welcome.

[@Ladynep]

Thank you so much sir

[@georgekamiti6538]

You are very much welcome.

[@freegamer6789]

Thank you sir

[@georgekamiti6538]

Welcome Sir.

[@josejaimesaldarriagagomez8848]

Thanks very much!

[@georgekamiti6538]

You are welcome

[@KiplangatWeldon-t3l]

Will it be the same if I assume the forces to be tensile at all point please

[@georgekamiti6538]

Yes Sir.

[@advertisementecosystem8347]

Thanks

[@georgekamiti6538]

You are welcome

[@g_nexentertainment9439]

good job bro

[@georgekamiti6538]

Thank You Very much man.