Type Projections... and why they work!

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  • เผยแพร่เมื่อ 22 พ.ย. 2024

ความคิดเห็น • 26

  • @typealias
    @typealias  8 หลายเดือนก่อน +4

    Hey all - there's been lots of great interest in the idea of doing some livestreams, so I'm working on that! ✨ If you're interested in it and you haven't already done so, take 60 seconds to fill out this survey ( www.surveymonkey.com/r/5MSRNDC ) to let me know what kinds of stuff you'd be interested in, and what times would work best for you. Thanks!

    • @sevbanthebuyer
      @sevbanthebuyer 8 หลายเดือนก่อน +1

      Hey Dave, link is broken for your information!

    • @typealias
      @typealias  8 หลายเดือนก่อน

      Ah, thanks for letting me know, Sevban! Looks like TH-cam got confused and thought the closing parenthesis was part of the link... Anyway, it's all fixed up now - thanks again! 👍

  • @enossalar8837
    @enossalar8837 3 หลายเดือนก่อน +2

    your channel is a gem

    • @typealias
      @typealias  3 หลายเดือนก่อน

      Thanks so much, Enos! I appreciate that!

  • @Никита-ж5с1ч
    @Никита-ж5с1ч หลายเดือนก่อน

    Best explanation of Kotlin generics I've ever seen. Thank you for your work man, please keep going 👨‍💻

  • @BaptistPiano
    @BaptistPiano 8 หลายเดือนก่อน

    I tend to believe more in functional programming and interfaces rather than subtyping, but this is an interesting problem for OO languages, and an interesting solution. Awesome video.

  • @mikhailbarash4041
    @mikhailbarash4041 8 หลายเดือนก่อน +1

    Thank you for the amazing video! 💯 At 4:15, should that rather be “covariance”, and and 5:18, should that be “contravariance”?

    • @typealias
      @typealias  8 หลายเดือนก่อน +1

      Thanks so much! I'm glad you liked it! I can definitely see how I could have explained those parts more thoroughly. In order for anything to be a subtype of another type, there must be _both_ contravariance _and_ covariance - there must be contravariance for each parameter type, and there must be covariance for each return type.
      By using `out` on a type argument, the type will _naturally_ have covariance with its return types that use T (which is why we're used to associating `out` with covariance). But something still has to happen to ensure that it has contravariance with its parameter types that use T. Kotlin handles this by replacing those types with `Nothing`. So at 4:15, I'm referring to how `Nothing` establishes that contravariance for the parameter type (rather than the covariance that exists naturally on the return type).
      Does that help to explain it better?

  • @westforduk
    @westforduk 8 หลายเดือนก่อน +2

    This was really insightful - thanks Dave!

    • @typealias
      @typealias  8 หลายเดือนก่อน +1

      Hey, thanks so much!
      PS - Love the Poirot avatar! I'm a big Agatha Christie fan.

    • @westforduk
      @westforduk 8 หลายเดือนก่อน

      @@typealiasmost kind of you to say mon ami ;)

  • @manjaro675
    @manjaro675 8 หลายเดือนก่อน

    I'm currently switching back to Native Android from Flutter and your videos really help out a lot. Thanks!

    • @typealias
      @typealias  8 หลายเดือนก่อน

      That's great to hear! I'm glad they're helpful!

  • @danielgibby5402
    @danielgibby5402 8 หลายเดือนก่อน

    I thought that the word projection in Kotlin meant the definition of projection which means looking into the future. e.g. projection: an estimate or forecast of a future situation. So that means that a projection of a variable is telling the compiler that you expect all future values of the variable to be of a certain type.

    • @typealias
      @typealias  8 หลายเดือนก่อน

      Ah, interesting - I never thought about how that particular definition of projection could apply to it! For programming, the term is rooted in mathematics, and the idea is basically that you're selecting certain parts of an existing type to project onto a new type. So for an out-projection, the covariant parts of the type (i.e., the ones where the type param is in the out-position) are technically the parts that are "projected" onto the new type, and the remaining parts are hidden or manipulated in some way (e.g., in Kotlin, manipulated so the types have the required variance).

  • @tanveerabbas26
    @tanveerabbas26 8 หลายเดือนก่อน +2

    Your content is awesome.

    • @typealias
      @typealias  8 หลายเดือนก่อน

      Ah, thanks so much! I'm glad you like it!

  • @Mister_Pine
    @Mister_Pine 8 หลายเดือนก่อน

    Why does an in projection modify the return types to `Any?`? Wouldn't the upper bound, in your example `Product`, work, too? Just as in a star projection?

    • @typealias
      @typealias  8 หลายเดือนก่อน +3

      There's a long-standing ticket about that here: youtrack.jetbrains.com/issue/KT-11273/Make-in-T-in-out-position-equivalent-to-upper-bound-of-T-rather-than-Any. There aren't any comments indicating a reason for the difference, and I can't think of any reason it would cause problems from a type-safety perspective. Here's hoping this ticket will get resolved sometime after Kotlin 2.0 comes out!

    • @Kubkochan
      @Kubkochan 8 หลายเดือนก่อน +1

      ​@@typealiasseems like it should be fixed in 2.0.0 betas

    • @Mister_Pine
      @Mister_Pine 8 หลายเดือนก่อน

      Interesting, thanks for your Answer!

  • @dk6024
    @dk6024 8 หลายเดือนก่อน

    Rather than 'supertype' do you mean 'assignable'?

    • @typealias
      @typealias  8 หลายเดือนก่อน +1

      The Kotlin language specification refers to `Any?` as the "unified supertype for all types in Kotlin", and I tend to stick with that phrasing as well - but it does bring the effect of assignability, so you could say that, too!

  • @dk6024
    @dk6024 8 หลายเดือนก่อน +3

    Help a Kotlin pregrammer find a job.

    • @typealias
      @typealias  8 หลายเดือนก่อน +3

      Ah, sorry if you're having trouble finding work! I'm sure you're not the only one - I'll put some thought into ways I might be able to help the community with this.